Motion in A Str...

The average velocity of a freely falling body is numerically equal to half of the acceleration due to gravity. The velocity of the body as it reaches the ground is numerically equal to:

A body leaving a certain point $$O$$ moves with an acceleration which is constant. At the end of the first second after it left $$O$$, its velocity is $$1.5m/\sec$$. At the end of the sixth second after it left $$O$$ the body stops momentarily and begins to move backwards. The distance traveled by the body before it stops momentarily is

A driver takes $$0.20s$$ to apply the brakes after he sees a need for it. This is called the reaction time of the driver. If he is driving a car at a speed of $$54 km/h$$ and the brakes causes a deceleration of $$ 6.0 \ { m }/{ { s }^{ 2 } }$$, find the distance traveled by the car after he sees the need to put the brakes on.

A train accelerates from rest at a constant rate $$a_{1}$$ for distance $$S_{1}$$ and time $$t_{1}$$. After that it decelerates to rest at a constant rate $$a_{2}$$ for distance $$S_{2}$$ at time $$t_{2}$$. Then the correct relation among the following is

A proton in a uniform electric field moves along a straight line with constant acceleration starting from rest. If it attains a velocity $$4\times 10^3$$ $$km/s$$ at a distance of $$2\;cm$$, the time required to reach the given velocity is :

From a building two balls A & B are thrown such that A is thrown upwards and B downwards (both vertically with same speed). If $$V_{A}$$ and $$V _{B}$$ are their respective velocities on reaching the ground then :

It takes one minute for a passenger standing on an escalator to reach the top. If the escalator does not move it takes him 3 minutes to walk up. How long will it take for the passenger to arrive at the top if he walks up the moving escalator?

Two cars are travelling towards each other on a straight road at velocities $$15\ m/s$$ and $$16\ m/s$$ respectively. When they are $$150\ m$$ apart, both the drivers apply the brakes and the cars decelerate at $$3\ m/s^{2}$$ and $$4\ m/s^{2}$$ until they stop. Separation between the cars when they come to rest is :

From an elevated point P, a stone is projected vertically upwards. When it reaches a distance $$d$$ below P, its velocity is doubled. The greatest height reached by it above P is :

A bus starts from rest and moves with a uniform acceleration of $$1\;ms^{-2}$$. A boy $$10\;m$$ behind the bus at the start runs at a constant speed and catches the bus in $$10\;s$$. Speed of the boy is :