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Laws of Motion Test - 24

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Laws of Motion Test - 24
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  • Question 1
    1 / -0
    $$Force\times time =$$________. Fill in the blank.
    Solution
    Impulse acting on the body is defines as the product of force acting on the body and the time interval for which force has been applied.
    $$\therefore$$  Impulse      $$I = F\Delta t$$
  • Question 2
    1 / -0
    Column AColumn B
    a) Forcei) $$f\times t$$
    b) Momentumii) $$m\times a$$
    c) Impulseiii) $$m\times v$$
    Solution
    (a)  From Newton's second law,       Force   $$f = m\times a$$
    (b)  Momentum      $$P = m\times v$$
    (c)   Impulse      $$I = f\times t$$
  • Question 3
    1 / -0
    A ride in an amusement park called scream machine swings the riders around a complete vertical circle during the course of the ride.
    Identify where on ride rider feels the maximum speed?

    Solution
    At the lowermost position of the circular motion, the potential energy is zero and thus the kinetic energy of the rider is maximum at that position.
    Using        $$K.E = \dfrac{1}{2}mv^2  $$            
    Hence the rider feels maximum speed at the lowermost position of motion i.e point A.
  • Question 4
    1 / -0
    Two similar trucks are moving with the same velocity on the road. One is loaded and the other is empty. Which truck will require more force to be stopped?
    Solution
    Force required         $$|F| = \dfrac{|\Delta P|}{\Delta t} = \dfrac{|m(0-u)|}{\Delta t} = \dfrac{mu}{\Delta t}$$
    $$\implies$$    $$|F| \propto  m$$                             $$(\because u,\Delta t = constants)$$
    As the loaded truck has more mass compared to the empty one, thus more force is required to stop the loaded truck.
  • Question 5
    1 / -0
    Which of the following quantities has equivalent units as Impulse?
    Solution
    Impulse $$I= Fdt=m\frac{dv}{dt} dt=mdv=$$ change in linear momentum. 
    Thus, the linear momentum has equivalent units as Impulse. 
  • Question 6
    1 / -0
    The amateur boxers, use larger and more padded gloves than professional boxers. The amateur boxers are more protected from injury because:
    Solution
    We have impulse $$\vec{I}=\vec{F}\times t=\vec{p}_{2}-\vec{p}_{1}$$ 
    when a boxer hits another boxer , change in momentum remains constant therefore product of force and time should be constant .we can decrease the force by increasing time of impact so boxer uses larger gloves to increase the time of impact  thus  decreases the force and avoids from injury.

  • Question 7
    1 / -0
    $$Mass \times velocity$$ =
    Solution
    Momentum of the body is defined as the product of mass of the body and its velocity.
    $$\therefore$$     Momentum    $$\vec{P} = m\vec{v}$$
  • Question 8
    1 / -0
    "Every action has its equal and opposite reaction" is Newton's:
    Solution
    Newton's third law of motion states that every action has an equal and opposite reaction. Force on a body 2 applied by the body 1 $$(F_{21})$$ is equal and opposite to the force on body 1 applied by the body 2 $$(F_{12})$$, i.e.
    $$F_{21}=-F_{12}$$
  • Question 9
    1 / -0
    A force acts on a body of mass 3 kg such that its velocity changes from 4 m $$s^{-1}$$ to 10 m $$s^{-1}$$.Calculate the change in the momentum of the body.
    Solution
    A force acts on a body of mass 3 kg such that its velocity changes from 4 m/s to 10 m/s
    change in momentum 
    $$\Delta p=m(v_1-v_2)=3*(10-4)=18kg m/s$$
  • Question 10
    1 / -0
    An astronaut in space throws an object away from his space shuttle. Which of the following statements is true?
    Solution
    From Newton's third law of motion, a reaction force acts on the astronaut equal in magnitude and opposite in direction to the force acted on the object.
    Since they would take same amount of time to acts,
    $$\int Fdt=\int Rdt$$
    $$\implies I_1=I_2$$
    Hence impulses on both are same in magnitude and opposite in direction.
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