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System of Particles and Rotational Motion Test - 34

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System of Particles and Rotational Motion Test - 34
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  • Question 1
    1 / -0
    The point through which the total weight of an object appears to act for any orientation of the object is ______.
    Solution
    The point through which the total weight of an object appears to act for any orientation of the object is centre of gravity.
  • Question 2
    1 / -0
    Two bodies of unequal masses possess the same momentum. Which of the following can be concluded?
    Solution
    Kinetic energy   $$K = \dfrac{P^2}{2m}$$
    For same momentum,   $$K\propto \dfrac{1}{m}$$
    Thus heavier mass possesses lesser kinetic energy.
  • Question 3
    1 / -0
    A particle is projected at an angle of $${30}^{0}$$ with the horizontal with a momentum $$P$$. At the highest point its momentum is
    Solution
    At the point of projection, $$P=mu$$
    At the highest point, vertical component of velocity is 0.
    Therefore, $$u_x=ucos30^0$$

    $$P'=m\left( u\cos { \theta  }  \right) $$

         $$=mu\dfrac { \sqrt { 3 }  }{ 2 } \\$$
        
         $$=\dfrac { P\sqrt { 3 }  }{ 2 } $$
  • Question 4
    1 / -0
    Two bodies of mass $$4 \ kg$$ and $$5\  kg$$ are moving along east and north directions with velocities $$5\  m/s$$ and $$3 \ m/s$$ respectively. Magnitude of the velocity of centre of mass of the system is:
    Solution
    Let east direction be x axis and north be y axis. Then, velocity of first body is $${ v }_{ 1 }=5i\quad m/s$$ and that of body 2 will be $${ v }_{ 2 }=3j\quad m/s$$. Since velocity of center of mass is given by 

    $${ v }_{ cm }=\dfrac { { m }_{ 1 }{ v }_{ 1 }+{ m }_{ 2 }{ v }_{ 2 } }{ { m }_{ 1 }+{ m }_{ 2 } } =\dfrac { 4(5i)+5(3j) }{ 4+5 } =\dfrac { 20 }{ 9 } i+\dfrac { 15 }{ 9 } j\quad m/s$$

    Hence, magnitude of velocity is $$|{ v }_{ cm }|=\dfrac { \sqrt { 400+225 }  }{ 9 } m/s=\dfrac { 25 }{ 9 } \ m/s$$.
  • Question 5
    1 / -0
    Which of the following quantities is zero, when a uniform object is being supported at its centre of gravity?
    Solution
    Force of gravity on the object acts at its centre of gravity.  If the uniform object is supported at its centre of gravity, net torque acting on it becomes zero.
  • Question 6
    1 / -0
    While opening a tap with two fingers, the forces applied by the fingers are:
    Solution
    A couple has to be applied to the tap in order to open it. A couple is the combination of two equal and opposite parallel forces acting at different axes. Thus option D is correct.
  • Question 7
    1 / -0
    Two particles $$A$$ and $$B$$ are connected by a rigid rod $$AB$$. The rod slides on perpendicular rails as shown in figure. The velocity of $$A$$ to the left is $$10m/s$$. What is velocity of $$B$$ when $$\alpha= 60^o$$? (in m/s)

    Solution
    Given :  $$V_A = 10 m/s$$
    Both the particles move can move parallel to the surface but not perpendicular to the surface.
    From figure, 
    $$\tan 60^o = \dfrac{V_B}{V_A}$$

    $$\implies V_B = V_A \tan 60^o $$
              $$V_B = 10 \times \sqrt3$$
              $$V_B = 17.3 \ \ m/s$$

  • Question 8
    1 / -0
    A sphere moving at some instant with horizontal velocity $$v_c $$ towards right and angular velocity in the anti-clockwise sense. If $$|v_c| = |\omega R|$$ The instantaneous center of rotation is:
    Solution

  • Question 9
    1 / -0
    Which of the following has the maximum momentum?
    Solution
    For (A) :  $$m =100 \ kg$$  and  $$v = 0.02 \ m/s$$
    Thus momentum  $$P = mv = (100)(0.02) = 2 \ kg \ m/s$$
    For (B) :  $$m =4 \ g =0.004 \ kg$$  and  $$v=10000\ cm/s = 100 \ m/s$$
    Thus momentum  $$P = mv = (0.004)(100) = .4 \ kg \ m/s$$
    For (C) : Kinetic energy  $$K = 10^6 \ J$$ and mass $$m = 0.2 \ kg$$
    Thus momentum  $$P = \sqrt{2mK} = \sqrt{2(0.2)(10^6)}  = 632.45 \ kg \ m/s$$
    For (D) : Mass  $$m = 0.02 \ kg$$  and height  $$h =1000 \ m$$
    Thus kinetic energy acquired  $$K=  mgh = (0.02)(10)(1000) = 200 \ J$$
    Thus momentum  $$P = \sqrt{2mK} = \sqrt{2(0.02)(200)}  = 2.83 \ kg \ m/s$$
    Option C has the maximum momentum, so correct answer is option C.
  • Question 10
    1 / -0
    Two bodies have same mass and speed, then:
    Solution
    Given that the mass and speed of two bodies are same
    We know that momentum is equal to $$p=mv$$ 
    But the momentums of two bodies are not equal, because momentum is a vector quantity
    The ratio of momentums is not defined because it is a vector quantity and ratio is a scalar quantity
    The ratio of their magnitudes are same, Therefore option $$D$$ is correct 
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