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System of Particles and Rotational Motion Test - 46

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System of Particles and Rotational Motion Test - 46
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  • Question 1
    1 / -0
    Four identical thin rods each of mass $$M$$ and length $$l$$, form a square frame. Moment of inertia of this frame about an axis through the centre of the square and perpendicular to its plane is
    Solution

  • Question 2
    1 / -0
    Two discs of same mass and same thickness have densities as $$17\ g/{cm}^{3}$$ and $$51\ g/{cm}^{3}$$. The ratio of their moment of inertia are in the ratio
    Solution
    $$I=\dfrac{1}{2}M{R}^{2}$$      ......$$(1)$$
    Now, $$M=\dfrac{4}{3}\pi{R}^{3}d\rho$$ where $$m$$ is the mass, $$d$$ is the thickness and $$\rho$$ is the density
    $$\Rightarrow R={\left(\dfrac{3M}{4\pi d\rho}\right)}^{\frac{1}{3}}$$
    $$\Rightarrow {R}^{2}={\left(\dfrac{3M}{4\pi d\rho}\right)}^{\frac{2}{3}}$$
    Hence eqn$$(1)$$ becomes,
    $$I=\dfrac{1}{2}M\times {\left(\dfrac{3M}{4\pi d\rho}\right)}^{\frac{2}{3}}$$     .......$$(2)$$
    Now if $$M$$ and $$d$$ are remaining constant as per the given condition then 
    $$I\propto\dfrac{I}{{\rho}^{\frac{2}{3}}}$$     ......$$(3)$$
    Given: moment of inertia of first disk of density $${\rho}_{1}=17$$g/$${cm}^{3}$$ and 
     moment of inertia of second disk of density $${\rho}_{2}=51$$g/$${cm}^{3}$$ 
    $$\dfrac{{I}_{1}}{{I}_{2}}={\left(\dfrac{{\rho}_{2}}{{\rho}_{1}}\right)}^{\frac{2}{3}}$$
    $$={\left(\dfrac{51}{17}\right)}^{\frac{2}{3}}$$
    $$={\left(\dfrac{3}{1}\right)}^{\frac{2}{3}}$$
    $$={9}^{\frac{1}{3}}$$
  • Question 3
    1 / -0
    Four thin uniform rods of length $$L$$ and mass $$m$$ are joined to form a square. The moment of inertia of square about an axis along its one diagonal is :
    Solution
    From Perpendicular axis theorem 
    $$I_z=I_y +I_x\quad \left\{I_x =I_y \right\}$$
    $$\boxed {I_z =2I_x}$$

    from parallel axis theorem $$I_z =I_{com}+md^2$$

    $$\Rightarrow \ I_z=\dfrac {ML^2}{12}+M\left (\dfrac {L}{2}\right)^2$$

    $$\Rightarrow \ I_z =\dfrac {ML^2}{12}+\dfrac {ML^2}{4}\ \Rightarrow \boxed {I_z =\dfrac {1}{3} ML^2}\to$$ For single Ros

    for $$4$$ rod $$I_z =4\times \dfrac {1}{3} ML^2 =\dfrac {4}{3}ML^2$$

    $$\boxed {I_x =\dfrac {I_z}{2}=\dfrac {\dfrac {4}{3}ML^2}{2}=\dfrac {2}{3}ML^2}$$

  • Question 4
    1 / -0
    A wire of length $$L$$ and mass $$M$$ is bent in the form of a circular ring. Its moment of inertia about its axis is
    Solution

  • Question 5
    1 / -0
    Force-time graph for the motion of a body is shown in figure. Change is linear momentum between 0 s to 8 s is : 

    Solution

  • Question 6
    1 / -0
    Two blocks of masses $$10\ kg$$ and $$4\ kg$$ are connected by a spring of negligible mass and placed on a frictionless horizontal surface. An impulse gives a velocity of $$14\ m/s $$ to the heavier block in the direction of the lighter block. The velocity of the centre of mass is 
    Solution

  • Question 7
    1 / -0
    The linear density of a rod of length $$L$$ varies as $$\rho=A+Bx$$ where $$x$$ is the distance from the left end. The distance of centre of mass from $$O$$ is
    Solution

  • Question 8
    1 / -0
    A man stands at the centre of a turn table it extended horizontally, with a $$5 kg$$ mass hand. He is set into rotation with an angular of one revolution in $$2s$$. His new angular is he drops his hands to his sides is (Assume moment of inertia of the man is $$6 \ kgm^2$$. The distance of the wavelength from the axis is $$1 m$$and final distance is $$0.2 m$$)
  • Question 9
    1 / -0
    Three particles each of mass $$200 g$$, are kept at corners of an equilateral triangle of side $$10 cm$$. Find the moment of inertia of the system about an axis joining two of the particle.
  • Question 10
    1 / -0
    A person sitting firmly over a rotating stool has his arms stretched. If he folds his arms, his angular momentum about the axis of rotation
    Solution

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