Gravitation Tes...

If R is the radius of the earth, then the ratio of acceleration due to gravity on surface of the earth to acceleration due to gravity at height nR is:

The value of $$g$$ on the earths surface is $$980\ cm/{sec}^{2}$$. Its value at a height of $$64\ Km$$ from the earth's surface is

The largest and the shortest distance of the earth from the sun are $$r_{1}$$ and $$r_{2}$$. Its distance from the sun when it is at perpendicular to the major-axis of the orbit drawn from the sun is:

The height of the point vertically above the earths surface at which the acceleration due to gravity becomes $$1\%$$ of its value at the surface is ($$R$$ is the radius of the earth)

At what height from the ground will be the value of $$g$$ be the same as 

A particle hanging from a spring stretches it by 1 cm at earth's surface. Radius of the earth is 6400 km. At a place 800 km above the earth's surface, the same particle will stretch the spring by 

The value of acceleration due to gravity at a point P inside the earth and at another point Q outside the earth is g/2 .(g being acceleration due to gravity at the surface of the earth). Maximum possible distance in terms of radius of earth R between P and Q is:

A body weight W Newton at the surface of the earth. Its weight at a height equal to half the radius of the earth will be :

The height at which the value of acceleration due to gravity becomes 50% of that at the surface of the earth. (Radius of the earth = 6400 km) is (approximately) :

The ratio of acceleration due to gravity at a depth $$h$$ below the surface of earth and at a height $$h$$ above the surface for $$h<< R$$