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Gravitation Test - 84

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Gravitation Test - 84
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  • Question 1
    1 / -0
    If the acceleration due to gravity at a height 'h' from the surface of the earth is $$96$$% less than its value on the surface, then h= ______R where R is the radius of the earth.
    Solution

  • Question 2
    1 / -0
    The diameter of a planet is four times that of the earth and its mean density is equal to that of earth. If the acceleration due to gravity on the earth surface is $$9.8 m/s$$ the acceleration due to gravity on the planet surface is
    Solution

  • Question 3
    1 / -0
    The escape velocity of a particle of mass $$m$$ varies at
  • Question 4
    1 / -0
    At what height from the surface of the earth will the value of acceleration due to gravity be reduced by $$36$$% from the value at the surface ? (Given radius of earth $$= 6400\, km$$)
    Solution

  • Question 5
    1 / -0
    A stone weighs $$100N$$ on the surface of the earth. The ratio of its weight at a height of half the radius of the earth to its weight at a depth of half the radius of the earth will be approximately
    Solution

  • Question 6
    1 / -0
    If the radius of the earth is half of its present value and its mass 1/$$8^{ th }$$ of the present mass , the 'g' value would have been reduced to 
    Solution

  • Question 7
    1 / -0
    The escape velocity on the surface of earth is V. If body is thrown with twice this this velocity then what will be its velocity after escaping the gravitational field
    Solution

  • Question 8
    1 / -0
    The acceleration due to gravity slightly below and above the surface of the earth (radius R) at distances d and h, respectively. varies with the distance the centre as 
    Solution

  • Question 9
    1 / -0
    The acceleration due to gravity at a height $$\frac { R }{ 20 } $$ from the surface is $$9ms^{-2}$$. Its value at a point, at an equal distance below the surface of the earth is
    Solution

  • Question 10
    1 / -0
    A body is thrown from the surface of the earth with a speed of $$\sqrt {GM/R} (R =$$ radius and $$M =$$ mass of earth). It rises to a maximum height of
    Solution

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