Mechanical Prop...

The ratio of lengths of two wires made of same material is $$2 :3$$. The ratio of their respective longitudinal stress to produce same elongation is

Ratio of lengths of two brass wires is 3 : 4; their areas of cross section are in the ratio 2:3. When same force is applied on them, the elongations produced will be in the ratio:

The length of a wire of cross-sectional area $$1 \times $$ 10$$^{-6}   m^{2}$$ is 10m. The young's modulus of the material of the wire is 25 G.pa. When the wire is subjected to a tensile force of $$100N$$, the elongation produced in $$mm$$ is:

A steel wire of length 1 m has cross sectional area $$1cm$$$$^{2}$$. If young's modulus of steel is $$10^{11}N / m^{2}$$ ,then force required to increase the length of wire by 1 mm will be :

Two steel wires have equal volumes. Their diameters are in the ratio 2 : 1. When same force is applied on them, the elongation produced will be in the ratio of:

A $$3 cm$$ long copper wire is stretched to increase its length by $$0.3cm.$$ If poisson's ratio for copper is $$0.26$$, the lateral strain in the wire is

The diameters of two steel wires are in the ratio 2: 3. Their lengths are equal. When same force is applied on them, the ratio of the elongation produced is

A copper wire and a steel wire of radii in the ratio $$1:2$$ lengths in the ratio $$2:1$$ are stretched by the same forces. If young's modulus of copper $$=1.1\times 10^{11}N / m^{2}$$, young's modulus of steel $$= 2\times 10^{11}N /m^{2}$$. Ratio of their extensions is :

The force that must be applied to a steel wire $$6m$$ long and diameter $$1.6mm$$ to produce an extension of 1mm [$$y=2.0 \times 10^{11}N.m^{-2}$$] is approximate.

A volume of $$10^{-3}m^{3}$$ is subjected to a pressure of 10 atmospheres. The change in volume is $$10^{-6}m^{3}$$. Bulk modulus of water is (Atmosphere pressure = 1x10$$^{5} N / m^{2}$$ ) :