Mechanical Prop...

The stress required to double the length of wire (or) to produce $$100\%$$ longitudinal strain is:

 A uniform rod of length $$60 cm$$ and mass $$6kg$$ is acted upon by two forces as shown in the diagram. The force exerted by $$45 cm$$ part of the rod on $$15 cm$$ part of the rod is 

Two wires A and B are identical in shape and size are stretched by same magnitude of force. Then the extensions are found to be 0.2% and 0.3% respectively. Find the rate of their Young's modulii

In the Searle's method to determine the Young's modulus of a wire, a steel wire of length $$156\ cm$$ and diameter $$0.054\ cm$$ is taken as experimental wire. The average increase in length for $$1.5\ kg\ wt$$ is found to be $$0.050\ cm$$. Then the Young's modulus of the wire is

For a material $$Y={ 6.6\times 10 }^{ 10 }\ { N/m }^{ 2 }$$ and bulk modulus $$K{ 11\times 10 }^{ 10 }\ { N/m }^{ 2 }$$, then its Poisson's ratio is:

A copper wire and an aluminium wire have lengths in the ratio 3:2, diameters in the ration 2:3 and forces applied in the ration 4:5. Find the ratio of the increase in the length of the two wires. 
$$\left( { Y }_{ cu }=1.1\times { 10 }^{ 11 }N{ m }^{ -2 },\quad { Y }_{ Al }=0.70\times { 10 }^{ 11 }N{ m }^{ -2 }\quad  \right) $$

The breaking stress of aluminium is $$7.5\times 10^{7}Nm^{-2}$$. The greatest length of aluminium wire that can hang vertically without breaking is(Density of auminium is $$2.7\times 10^{3}\ kg\ m^{-3}$$)

A steel wire $$2\ m$$ in length is stretched by $$1\ mm$$. The cross-sectional area of the wire is $$2\ mm^{2}$$. If Young's modulus of steel is $$2\times 10^{11}\ N/m^{2}$$, then the elastic potential energy stored in the wire is

Three bars having length $$l,2l$$ and $$3l$$ and area of cross-section $$A,2A$$ and $$3A$$ are joined rigidly and to end. Compound rod is subjected to a stretching force $$F$$. The increase in length of rod is (Young's modulles of material is $$Y$$ and bars are massless)

A hydraullic press contains $$250 lit$$ of oil. Find the decrease in volume of the oil when its  pressure increases to $$ 10^7 Pa$$ . The bulk modulus of the oil is $$ K = 5 \times 10^5 Pa$$