Sexual Reproduction in Flowering Plants Test

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Sexual Reproduction in Flowering Plants Test - 70

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Question 1
1 / -0

Male haploid cells are produced in

A
1

B
2

C
3

D
6

E
8

Solution

Anther (2) is a broad knob part of the stamen that is present at the top of the filament (3). Stigma (1) is the top most style (4) which in turn culminates in the swollen end, ovary (8). Ovary consist of ovules (6) arranged on the placenta. Anther is a broad knob part of the stamen that contains two long and cylindrical microsporangia in its lobes. Each microsporangium has inner sporogenous tissue that differentiates into microspore/pollen mother cell or first undergoes mitotic divisions to increase the cell number. These diploid cells undergo meiosis to produce four haploid microspores/pollen grains that remain suspended in central of each microsporangium. This makes option B correct answer.
Question 2
1 / -0

The production of male gametes in flowering plants is carried out by

A
Ovary

B
Anther

C
Microsporangium

D
Sporophyte

E
Generative nucleus
Solution
1. An ovary is the part of the pistil that produces ovum.
2. Anthers are the part of stamens that produce pollen grains (male gametophytes)
3. Microsporangium in anthers gives rise to microspore mother cell.
4. The sporophyte is the condition in an alternation of generation in plants in which spore develops the gametophyte of a plant as in ferns.
5. The generative nucleus is one of the two nuclei in angiosperms that divide to produce two male gamete nuclei (male gametes) for double fertilization.
So the correct option is 'Generative nucleus'
Question 3
1 / -0

Wind pollinated plants generally do not show the following character

A
Feathery stigma

B
Single ovule in the ovary

C
Well exposed stamens

D
Flowers are large and colourful

Solution

The characteristics of wind pollination or anemophily includes a lack of scent production, less attractive and large floral parts, reduced production of nectar and production of enormous number of pollen grains. This distinguishes them from entemophilous (pollen being transported by the insects). The pollen grains are light and non-sticky, so that they can be transported with the wind currents.
Thus, the correct answer is option D.
Question 4
1 / -0

The diagram of the section of a maize grain is given below. Identify the parts labelled A, B, C and D.

A
A- Endosperm, B- Coleoptile, C- Scutellum, D- Aleurone layer

B
A- Cotyledon, B- Coleoptile, C- Scutellum, D- Epithelium

C
A- Endosperm, B- Caleoptile, C- Scutellum, D- Epithelium

D
A- Endosperm, B- Coleorrhiza. C- Scutellum, D- Epithelium

Solution

Testa represents the outer layer of seed coat and develops from outer integument of ovule. Tagmen is the inner layer of seed coat which develops from inner integument layer of ovule. Testa and tagmen together form seed coat and surrounds aleurone layer. Aleurone grains store the granular protein in a thin aleurone layer which forms the outer most covering of endosperm; “A” is endosperm and D is aleurone layer. Coleoptile (B) is a protective covering that surrounds part of epicotyl (the immature shoot). The single cotyledon of maize grains (monocot) is called as scutellum (C) and is present between developing embryo and endosperm. Option A is correct.
Question 5
1 / -0

Seeds without fertilization is obtained from

A
Parthenocarpy

B
Apomixis

C
Polyembryony

D
Dormancy
Solution
Apomixis is a process of reproduction by special generative tissues without fertilisation in which the generative tissues can be a sporophyte or gametophyte.
Parthenocarpy is the process of development of fruits without prior fertilization of ovules.
Polyembryony is the formation of more than one embryo from a single fertilized ovum.
Seed dormancy is defined as a state in which seeds are prevented from germinating even under environmental conditions normally favorable for germination.
So, the correct answer is option B.
Question 6
1 / -0

X is a dicot flowering plant and Y is an algae. Identify X and Y.

A
X-coconut, Y-yeast

B
X-maize, Y-mushroom

C
X-balsam, Y- mushroom

D
X-long bean,Y- spirogyra

Solution

The label X refers to a dicot plant in which there are two cotyledons and the leaves possess reticulate venation. The example of the dicot plant is the long bean. The label Y refer to an alga which is Spirogyra. These are the filamentous algae with spiral shaped chloroplast.
Thus, the correct answer is option D.
Question 7
1 / -0

Continued self pollination results in

A
Inbreeding depression

B
Self incompatibility

C
Formation of unisexual flowers

D
Loss of vigor in gametes

Solution

Inbreeding depression is the reduced biological fitness in a given population as a result of inbreeding, or breeding of related individuals. Continued self-pollination reduces the fertility and even productivity of the plant.
Thus, the correct answer is option A.
Question 8
1 / -0

Emasculation ensures cross-pollination in ______

A
Staminate flower

B
Bisexual flower

C
Neuter flower

D
Pistillate flower

Solution

Emasculation is a process of removal of stamen from bisexual flower during artificial hybridization to ensure the cross-pollination with desired plants.
So, the correct answer is option B.
Question 9
1 / -0

A plant produced 50 flowers. Ovary of each flower has 50 ovules. How many fruits and seeds are produced by that plant respectively.

A
50, 50

B
550, 100

C
50, 2500

D
2500, 2500

Solution

After fertilisation ovules form seeds, hence 50 viable seeds are produced from 50 ovules. Also, each flower produces a fruit. Hence, there will be 50 fruits produced by 50 flowers.
Thus, the correct answer is option A.
Question 10
1 / -0

Pollination in Rafflesia is occurred by

A
Carrion flies

B
Elephant

C
Bat

D
Crow

Solution

Pollination helps in the dispersal of pollens which ultimately fuses with ovules. Rafflesia flowers are the largest one with an aroma which attracts carrion flies for pollination. The carrion flies are a parasite of elephants and but the pollinating agents are the flies, not the elephants.
So, the correct answer is option A.

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Re-Attempt Weekly Quiz Competition

Sexual Reproduction in Flowering Plants Test - 70

Result

Sexual Reproduction in Flowering Plants Test - 70

Score

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Rank

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SHARING IS CARING

Question 1

1

2

3

6

8

Solution

Question 2

Ovary

Anther

Microsporangium

Sporophyte

Generative nucleus

Solution

Question 3

Feathery stigma

Single ovule in the ovary

Well exposed stamens

Flowers are large and colourful

Solution

Question 4

A- Endosperm, B- Coleoptile, C- Scutellum, D- Aleurone layer

A- Cotyledon, B- Coleoptile, C- Scutellum, D- Epithelium

A- Endosperm, B- Caleoptile, C- Scutellum, D- Epithelium

A- Endosperm, B- Coleorrhiza. C- Scutellum, D- Epithelium

Solution

Question 5

Parthenocarpy

Apomixis

Polyembryony

Dormancy

Solution

Question 6

X-coconut, Y-yeast

X-maize, Y-mushroom

X-balsam, Y- mushroom

X-long bean,Y- spirogyra

Solution

Question 7

Inbreeding depression

Self incompatibility

Formation of unisexual flowers

Loss of vigor in gametes

Solution

Question 8

Staminate flower

Bisexual flower

Neuter flower

Pistillate flower

Solution

Question 9

50, 50

550, 100

50, 2500

2500, 2500

Solution

Question 10

Carrion flies

Elephant

Bat

Crow

Solution

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