Principles of Inheritance and Variation Test

Result

Principles of Inheritance and Variation Test - 24

Score
-
out of -
Rank
-
out of -

TIME Taken - -

SHARING IS CARING

If our Website helped you a little, then kindly spread our voice using Social Networks. Spread our word to your readers, friends, teachers, students & all those close ones who deserve to know what you know now.

Weekly Quiz Competition

Question 1
1 / -0

A common test to find the genotype of hybrid is by

A
Crossing of one F$$_2$$ progeny with male parent

B
Crossing of one F$$_2$$ progeny with female parent

C
Studying the sexual behaviour of F$$_1$$ progenies

D
Crossing of one F$$_1$$ progeny with male parent

Solution

Correct Option: D

Explanation:

To find the genotype of a hybrid, take a look at cross is performed during which an associate degree organism showing dominant composition is crossed with the recessive parent rather than selfing. The progenies of such cross will simply be analyzed to predict the genotype organism.

So, the proper answer is 'Crossing of 1 F1 issue with male parent'.
Question 2
1 / -0

Male XX and female XY sometime such conditions occur due to

A
Deletion

B
Transfer of segments in X and Y chromosomes

C
Aneuploidy

D
Hormonal imbalance

Solution

Human follows XX- XY mechanism of sex determination in which females have XX sex chromosomes and males have XY chromosomes as their sex chromosomes.
The Y chromosome carries TDF gene that is responsible for the development of testis in human males absence of this gene in females determines feminism. Unequal crossing over between X and Y chromosomes during meiosis results in the transfer of TDF gene on X chromosome while the Y chromosome lacks it.
Fertilisation of sperm carrying Y chromosome without TDF gene with egg lead to the development of XY females as the Y chromosome does not have TDF gene so no testis formation. Similarly, fertilization of sperm with X chromosome carrying the TDF gene with egg lead to development of XX males as the X chromosome has TDF gene so male genital organs are formed.
Changes in chromosome number by additions or deletions of less than a whole set is called aneuploidy, but here chromosomal parts are exchanged.
Removal of one or more nucleotide bases to the DNA segment is known as deletion, it is a point mutation that alters the gene at molecular level.
Hormonal imbalance does not change the chromosomal constitution of organisms.
So, the correct answer is option B.
Question 3
1 / -0

Sickle cell anemia is

A
Characterized by elongated sickle like RBCs with a nucleus

B
An autosomal linked dominant trait

C
Caused by substitution of valine by glutamic acid in the $$\beta$$-globin chain of haemoglobin

D
Caused by a change in a single base pair of DNA

Solution

Sickle cell disease the haemoglobin beta gene found on chromosome 11 gets mutated. Red blood cells with normal haemoglobin are smooth and round and glide through blood vessels but in this disease, the cell becomes the sickle shape. It is caused by a single point mutation (a missense mutation) in the beta-hemoglobin gene that converts a GAG codon into GUG, which encodes the amino acid valine rather than glutamic acid. Haemoglobin transports oxygen from the lungs to other parts of the body. Thus, the correct answer is option D.
Question 4
1 / -0

Inheritance of skin colour in humans is an example of

A
Chromosomal aberration

B
Point mutation

C
Polygenic inheritance

D
Codominance

Solution

A polygene, multiple factor, multiple gene inheritance, or quantitative gene is a group of non-allelic genes that together influence a phenotypic trait. The precise loci or identities of the non-allelic genes are often unknown to biologists. Advances in statistical methodology and high throughout sequencing are, however, allowing researchers to locate candidate genes for the trait. These genes are generally pleiotropic as well. The genes that contribute to type 2 diabetes are thought to be mostly polygenes.
Polygenic inheritance occurs when one characteristic is controlled by two or more genes. Often the genes are large in quantity but small in effect. Examples of human polygenic inheritance are height, skin color, eye color and weight. Polygenes exist in other organisms, as well. Drosophila, for instance, display polygeny with traits such as wing morphology, bristle count and many others.
Question 5
1 / -0

Which of the following is the example of pleiotropy?

A
Haemophilia

B
Thalassemia

C
Sickle cell anaemia

D
Colour blindness

Solution

A mutation is defined as the genetic alteration that causes a change in the phenotype or expression of that gene. Sometimes, we see genetic changes and phenotype changes not from a mutation, but from a gene controlling multiple traits. This is called as pleiotropy. Therefore, pleiotropy is where one gene winds up controlling multiple phenotypic traits in the organism. Sickle cell anemia is an example of pleiotropy as because the expression of a single mutated HBB gene produces numerous consequences throughout the body.
Thus, the correct answer is option C.
Question 6
1 / -0

Which one of the following conditions though harmful in itself, is also a potential survivor from a mosquito borne infectious disease?

A
Thalaessaemia

B
Sickle cell anaemia

C
Pernicious anaemia

D
Leukemia

Solution

Sickle cell anemia is caused by a variant form of hemoglobin in red blood cells. The amino acid valine replaces glutamine in the 6th position in hemoglobin chain. The homozygous individuals die at an early stage. In heterozygotes also, the red blood cells with a variant form of hemoglobin become sickle shaped. Due to this, the RBCs are unable to bind oxygen efficiently. As sickle shaped RBCs are destroyed the malarial parasite is killed. This allows the individual heterozygous for this variant to be able to deal with malaria infections much better than a normal person. Hence a person with sickle cell anemia is also a potential survivor from a mosquito borne infectious disease such as malaria. Thus the correct answer is option B.
Question 7
1 / -0

AABbCc genotype forms how many types of gametes

A
4

B
8

C
2

D
6
Solution
Correct Option- A
Explanation-
AABbCc genotype has three different types of genes.
The possible numbers of gametes that can be formed from the above genotype are- ABC, Abc, ABc and AbC.
Hence, the correct answer is 4.
Question 8
1 / -0

After a mutation at a genetic locus, the character of an organism changes due to the change in

A
Protein structure

B
DNA replication

C
Protein synthesis pattern

D
RNA transcription pattern.

Solution

As per the central dogma, the DNA makes RNA and RNA makes proteins. So, the code in DNA determines the code in mRNA and the code in mRNA determines the sequence of amino acids. The amino acid chains are the basis of protein structure. So, if something goes wrong in the DNA (like mutation in the genetic locus), then the mRNA will also be wrong and if mRNA is wrong, then the amino acid chain will be wrong and will cause a problem in the protein. The changes in the protein leads to changes in certain characters of an organism.
Thus, the correct answer is option (A), 'Protein structure'.
Question 9
1 / -0

When AABBcc is crossed with AaBbCc then the ratio of hybrid for all the three genes is

A
1/8

B
1/4

C
1/16

D
1/32

Solution

P generation : AABBcc x AaBbCc
Gametes : ABc 8 types: ABC, Abc, ABc, AbC, abc, aBC, aBc, abC.

AABBCc , AABbcc , AABBcc , AABbCc, AaBbcc, AaBBCc, AaBBcc , AaBbCc
As seen from the above, the ratio of hybrid for all the three genes (AaBbCc) = 1/8
Question 10
1 / -0

If Mendel might have studied 7 pairs of characters in a plant with 12 chromosomes, instead of 14, then

A
He could not discover independent assortment.

B
He might have not discovered linkage.

C
He might have discovered crossing-over.

D
He might have not observed dominance.

Solution

Mendel studies seven traits in different pea plants. Pea plants have 14 chromosomes, that is 7 chromosomes in haploid condition. Hence, he studied one trait or gene on one chromosome. If pea plants would have had 12 chromosomes instead of 14, he would not have discovered the law of independent assortment. Instead, he would have discovered linkage as two genes would have been present on single chromosome.
Thus, the correct answer is option A.

User

Question Analysis

Correct -
Wrong -
Skipped -

My Perfomance

Score
-
out of -
Rank
-
out of -

Re-Attempt Weekly Quiz Competition


	AABBCc	, AABbcc	, AABBcc	, AABbCc,	AaBbcc,	AaBBCc,	AaBBcc	, AaBbCc

Principles of Inheritance and Variation Test - 24

Result

Principles of Inheritance and Variation Test - 24

Score

-

Rank

-

SHARING IS CARING

Question 1

Crossing of one F$$_2$$ progeny with male parent

Crossing of one F$$_2$$ progeny with female parent

Studying the sexual behaviour of F$$_1$$ progenies

Crossing of one F$$_1$$ progeny with male parent

Solution

Question 2

Deletion

Transfer of segments in X and Y chromosomes

Aneuploidy

Hormonal imbalance

Solution

Question 3

Characterized by elongated sickle like RBCs with a nucleus

An autosomal linked dominant trait

Caused by substitution of valine by glutamic acid in the $$\beta$$-globin chain of haemoglobin

Caused by a change in a single base pair of DNA

Solution

Question 4

Chromosomal aberration

Point mutation

Polygenic inheritance

Codominance

Solution

Question 5

Haemophilia

Thalassemia

Sickle cell anaemia

Colour blindness

Solution

Question 6

Thalaessaemia

Sickle cell anaemia

Pernicious anaemia

Leukemia

Solution

Question 7

4

8

2

6

Solution

Question 8

Protein structure

DNA replication

Protein synthesis pattern

RNA transcription pattern.

Solution

Question 9

1/8

1/4

1/16

1/32

Solution

Question 10

He could not discover independent assortment.

He might have not discovered linkage.

He might have discovered crossing-over.

He might have not observed dominance.

Solution

User

Question Analysis

My Perfomance

Score

-

Rank

-

Results Announcement on: coming Monday

Stay Tuned: We’ll update you on your result via email or SMS.