Principles of Inheritance and Variation Test

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Principles of Inheritance and Variation Test - 69

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Weekly Quiz Competition

Question 1
1 / -0

Sickle cell anaemia is a case of

A
Transition

B
Transversion

C
Frame shift mutation

D
Silent mutation

Solution

Transition, in genetics and molecular biology, refers to a point mutation that changes a purine nucleotide to another purine (A ↔ G), or a pyrimidine nucleotide to another pyrimidine (C ↔ T). Sickle-cell disease is caused by a single point mutation (a missense mutation) in the beta-hemoglobin gene that converts a GAG codon into GUG, which encodes the amino acid valine rather than glutamic acid.

So, the correct answer is 'Transition'.
Question 2
1 / -0

Give a chromosome segment a-b-c with $$40\%$$ interference, the frequency of double cross-over (dco) will be.

A
$$20\%$$

B
$$10\%$$

C
$$1.2\%$$

D
$$0.12\%$$
Question 3
1 / -0

What will happen, if the sperm containing $$'X'$$ chromosomes fertilises the Ovum?

A
Female child born

B
Male child born

C
Can not guess

D
None

Solution

The process of fusion of a sperm with an ovum is called fertilisation. During fertilisation, a sperm comes in contact with the zona pellucida layer of the ovum and induces changes in the membrane which blocks entry of additional sperms. This also induces the formation of the haploid secondary oocyte, by meiotic division, which fuses with sperm to form zygote. At this stage the sex of the baby is determined. Males have XY chromosomes so sperms who have haploid no. of chromosomes carry either X or Y. While females have XX chromosomes, so all ovum will carry X chromosome. So when a sperm containing X chromosome fertilises an ovum, a zygote with XX chromosomes is formed. Thus a female child is born.
Question 4
1 / -0

Following is a pedigree for the albinium (aa). What is the probability of II-I to be beterozygous?

A
$$\cfrac{1}{3}$$

B
$$\cfrac{1}{2}$$

C
$$\cfrac{2}{3}$$

D
$$\cfrac{1}{4}$$
Question 5
1 / -0

Study the pedigree chart of a certain family given and select the correct conclusion which can be drawn for the character.

A
The female parent in heterozygous

B
The parents could bot have had a normal daughter for this character

C
The trait under study could not be colourblindness

D
The male parent is homozygous dominant
Solution
Correct Option: A
Explanation:
- The male parent is affected but the female parent is not.
- Since three out of four children are affected, the female parent must be a carrier of the disease/disorder.
Hence, the female parent in heterozygous.
Question 6
1 / -0

In the given pedigree chart, the mutant trait is shaded black. The gene responsible for the trait is

A
dominant and sex linked

B
dominant and autosomal

C
recessive and sex linked

D
recessive and autosomal
Question 7
1 / -0

Sudden change in genetic character is known as

A
Mutation

B
Mitotic division

C
Meiotic division

D
Recombination

Solution

Sudden change in genetic character is known as mutation. Mutation is the phenomenon of alterations to DNA. This results in the development of new characteristics that are capable of being inherited. It results either due to error during DNA replication or damage to DNA.
Thus, the correct answer is option A.
Question 8
1 / -0

A homozygous recessive with cd genes was crossed with dominant (+ +).If their hybrid is test crossed and the following result was obtained
++ - 900
cd - 880
+d - 115
+c - 105
than what will be the distance between genes c and d.

A
5.75 unit

B
11 unit

C
44 unit

D
90 unit
Question 9
1 / -0

Presence of which of the following in the cells of amniotic fluid is responsible for the sex determination of the embryo?

A
Barr Body

B
Sex Chromosomes

C
Chiasmata

D
Antigen

Solution

The amniotic fluid contains fetal cells. A small amount of the fluid is extracted and tested to determine the presence of any genetic/chromosomal abnormality in the fetus, a process called amniocentesis. As all cells contain sex chromosomes or allosomes the test can also be used to determine the sex of the fetus. However, the determination of sex is illegal.
So, the correct answer is option B.
Question 10
1 / -0

In a polygenic inheritance of skin colours controlled by two gene pairs, how many phenotypes, mulattoes and total progenies are formed in $$F_2$$.

A
3,3, 16 respectively

B
5,6,16 respectively

C
7,20, 64 respectively

D
7, 6, 16 respectively

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Principles of Inheritance and Variation Test - 69

Result

Principles of Inheritance and Variation Test - 69

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SHARING IS CARING

Question 1

Transition

Transversion

Frame shift mutation

Silent mutation

Solution

Question 2

$$20\%$$

$$10\%$$

$$1.2\%$$

$$0.12\%$$

Question 3

Female child born

Male child born

Can not guess

None

Solution

Question 4

$$\cfrac{1}{3}$$

$$\cfrac{1}{2}$$

$$\cfrac{2}{3}$$

$$\cfrac{1}{4}$$

Question 5

The female parent in heterozygous

The parents could bot have had a normal daughter for this character

The trait under study could not be colourblindness

The male parent is homozygous dominant

Solution

Question 6

dominant and sex linked

dominant and autosomal

recessive and sex linked

recessive and autosomal

Question 7

Mutation

Mitotic division

Meiotic division

Recombination

Solution

Question 8

5.75 unit

11 unit

44 unit

90 unit

Question 9

Barr Body

Sex Chromosomes

Chiasmata

Antigen

Solution

Question 10

3,3, 16 respectively

5,6,16 respectively

7,20, 64 respectively

7, 6, 16 respectively

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