Principles of Inheritance and Variation Test

Result

Principles of Inheritance and Variation Test - 71

Score
-
out of -
Rank
-
out of -

TIME Taken - -

SHARING IS CARING

If our Website helped you a little, then kindly spread our voice using Social Networks. Spread our word to your readers, friends, teachers, students & all those close ones who deserve to know what you know now.

Weekly Quiz Competition

Question 1
1 / -0

When Mendel crossed a pure white flowered strain of pea with a pure red flowered strain, the first generation hybrids had

A
only red flowers

B
only white flowers

C
pink flowers

D
three red and one white flowers
Question 2
1 / -0

Choose the correct answer from the alternatives given.

Which of the following characters was not chosen by Mendel?

A
Pod shape

B
Pod colour

C
Location of flower

D
Location of pod
Question 3
1 / -0

Study the given pedigree chart of a certain family and select the correct conclusion which can be drawn for the character.

A
The female parent is heterozygous.

B
The parents could not have had a normal daughter for this character.

C
The trait under study could not be colourblindness.

D
The male parent is homozygous dominant.
Solution
Correct Option: C
Explanation:
- Colourblindness is a X-linked trait.
- The male parent is affected.
- The female parent is a carrier as three of the progeny is affected.
- Although it is recessive in her as she isn't affected.
Hence, the trait under study could not be colourblindness.
Question 4
1 / -0

In the following human pedigree, the filled symbols represent the affected individuals. Identify the type of given pedigree

A
X - linked dominant

B
Autosomal dominant

C
X- linked recessive

D
Autosomal recessive
Solution
Correct Option: C
Explanation:
The mentioned pedigree does not have a dominant disease because III-6 and III-7 are unaffected.
The pedigree in question has an X-linked recessive disease.
The female is a carrier of the disease in generation I, whereas the male is afflicted. In generation II, both the mother and the father pass on the afflicted genes to the female.
When II-1 marries a healthy guy, her progeny is immune to the sickness. The female of generation III, on the other hand, is a disease carrier since she inherited the defective gene from her mother.
Hence, the given pedigree is of X-recessive.
Question 5
1 / -0

The mutations that involve addition, deletion or substitution of a single base pair in a gene are referred to as

A
point mutations

B
lethal mutations

C
silent mutations

D
retrogressive mutations.

Solution

Most of the gene. mutations involve a change in only a single nucleotide or nitrogen base of the cistron. These gene mutations are called point mutations e.g. sickle cell anemia in which polypeptide chain coding for haemoglobin contains valine instead of glutamic acid due to substitution ofT byA in second position of triplet codon.
Question 6
1 / -0

Chromosome duplication without nuclear division refers to

A
Meiosis

B
Mitosis

C
Androgenesis

D
Endomitosis

Solution

Endomitosis is the replication of chromosomes in the absence of cells or nuclear division resulting in numerous copies within each cell. It occurs in the salivary glands of Drosophila and other files.

Question 7

1 / -0

Choose the correct answer from the alternatives given.

Some of the dominant traits studied by Mendel were _______.

Round seed shape, green seed colour and axial flower position

Terminal flower position, green pod colour and inflated pod shape

Violet flower colour, green pod colour and round seed shape

Wrinkled seed shape, yellow pod colour and axial flower position

Solution

Mendel uses seven different characters or traits of a pea plant with two contrasting variants in his experiments are as follows-

Character	Dominant	Recessive
Seed colour	Yellow	Green
Seed form	Round	Wrinkled
Pod shape	Inflated	Constricted
Pod colour	Green	Yellow
Stem length	Tall	Dwarf
Flower colour	Violet	White
Flower position	Axial	Terminal

So, the correct answer is option C.

Question 8
1 / -0

In an organism, tall phenotype is dominant over recessive dwarf phenotype, and the alleles are designated as $$T$$ and $$t$$, respectively. Upon crossing two different individuals, total 250 offsprings were obtained, out of which 124 displayed tall phenotype and rest were dwarf. Thus,, the genotype of the parents were

A
$$TT \times TT$$

B
$$TT \times tt$$

C
$$Tt \times Tt$$

D
$$Tt \times tt$$

Solution

In order to obtain both recessive and dominant offspring, both parents should be heterozygous. Due to the absence of allele for dwarfism, a cross between two pure-breeding tall varieties (TT x TT) obtains only tall but no dwarf offspring.
A cross between two pure-breeding tall and dwarf varieties produce heterozygous tall (Tt) offspring wherein the expression of recessive allele (t) is marked by the presence of the dominant allele (T).
A cross between Tt and tt produces both tall and dwarf offspring in 1: 1 ratio and is known as a test cross.
So the correct option is 'Tt×tt'.
Question 9
1 / -0

Choose the correct answer from the alternatives given.

______ pairs of contrasting traits were studied by Mendel in pea plant.

A
6

B
7

C
8

D
10
Question 10
1 / -0

Choose the correct answer from the alternatives given.

In fruit flies, the long wing is dominant to the vestigial wing. When heterozygous long-winged flies were crossed with vestigial-winged flies, 192 offsprings were produced. Of these, 101 had long wings and 91 had vestigial wings. If an exact Mendelian ratio had been obtained, then the number of each phenotype would have been Long-winged: vestigial-winged.

A
Long winged 64, Vestigial winged - 128

B
Long winged - 96, Vestigial winged 96.

C
Long winged - 128, Vestigial winged 64

D
Long winged - 192, Vestigial winged 0

Solution

A cross between heterozygous long-winged flies and (homozygous) vestigial winged
flies represents an example of test cross, in which the exact Mendelian ratio of 1: 1 is obtained. i e. 96 long-winged flies and 96 vestigial winged flies.

User

Question Analysis

Correct -
Wrong -
Skipped -

My Perfomance

Score
-
out of -
Rank
-
out of -

Re-Attempt Weekly Quiz Competition

Principles of Inheritance and Variation Test - 71

Result

Principles of Inheritance and Variation Test - 71

Score

-

Rank

-

SHARING IS CARING

Question 1

only red flowers

only white flowers

pink flowers

three red and one white flowers

Question 2

Pod shape

Pod colour

Location of flower

Location of pod

Question 3

The female parent is heterozygous.

The parents could not have had a normal daughter for this character.

The trait under study could not be colourblindness.

The male parent is homozygous dominant.

Solution

Question 4

X - linked dominant

Autosomal dominant

X- linked recessive

Autosomal recessive

Solution

Question 5

point mutations

lethal mutations

silent mutations

retrogressive mutations.

Solution

Question 6

Meiosis

Mitosis

Androgenesis

Endomitosis

Solution

Question 7

Round seed shape, green seed colour and axial flower position

Terminal flower position, green pod colour and inflated pod shape

Violet flower colour, green pod colour and round seed shape

Wrinkled seed shape, yellow pod colour and axial flower position

Solution

Question 8

$$TT \times TT$$

$$TT \times tt$$

$$Tt \times Tt$$

$$Tt \times tt$$

Solution

Question 9

6

7

8

10

Question 10

Long winged 64, Vestigial winged - 128

Long winged - 96, Vestigial winged 96.

Long winged - 128, Vestigial winged 64

Long winged - 192, Vestigial winged 0

Solution

User

Question Analysis

My Perfomance

Score

-

Rank

-

Results Announcement on: coming Monday

Stay Tuned: We’ll update you on your result via email or SMS.