Principles of Inheritance and Variation Test

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Principles of Inheritance and Variation Test - 77

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Question 1
1 / -0

An individual homozygous to genes cd is crossed with wild type $$++$$ and $$F_1$$ crossed back with the double recessive. The appearance of the offsprings is as follows.
$$++ \rightarrow 903$$
$$cd \rightarrow 897$$
$$+d \rightarrow 98$$
$$c+ \rightarrow 102$$
The distance between the genes $$c$$ and $$d$$ is

A
$$20$$ map units

B
$$9.8$$ map units

C
$$10.2$$ map units

D
$$10$$ map units

Solution

Recombination Frequency = (No of recombinants/Total number of progeny) * 100 map units. The total number of recombinants in this case is 98+102=200 and the total number of progeny is 200+903+897=2000. So the recombination frequency is 200/2000 X 100 = 10 map units.

So the correct option is '10 map units'.
Question 2
1 / -0

In our society, women are blamed for producing female children. Choose the correct option for sex determination in humans.

A
Due to some defect like aspermia in man

B
Due to genetic makeup of some particular sperm which fertilizes the egg

C
Due to genetic makeup of the eggs

D
Due to some defect in women

Solution

The male produces two type of sperms - one having genetic makeup as 22A+X and other one having as 22A+Y. So, if a sperm consisting of genetic makeup 22A+X fertilizes the egg of genetic makeup 22A+X then will result in the formation of zygote having genotype as 22AA+XX which will result in the female child. While, if a sperm of genetic makeup 22A+Y fertilizes the egg of genetic makeup 22A+X then will result in the formation of zygote having the genetic constitution of 22AA+XY, which will result in the formation of the male child. So, clearly mother is never responsible for the sex of a child, it is the father who determines the sex of a child.
So, the correct answer to the question id 'Due to the genetic makeup of some particular sperm which fertilizes the egg'.
Question 3
1 / -0

Which of the following is true for progenies of $$F_3$$ generation of monohybrid cross?

A
$$ 75 \% $$ pure and $$25 \%$$ impure

B
$$ 25 \% $$ pure and $$75 \% $$impure

C
$$ 50 \% $$ pure and $$50\%$$ impure

D
$$ 87.5 \% $$ pure and $$12.5 \%$$ impure

Solution

A monohybrid cross is when the offspring of homozygous parents that only differ on a single trait is bred to come up with the second generation.
Refer to the image.

So, the correct answer is '75% pure and 25% impure'.
Question 4
1 / -0

Three genes A, B and C are involved in determination of skin colour. If a couple with fair skin colour, produced a child with dark skin colour, then the genotype of the parents most probably can be:-

A
Aabbcc x aaBbcc

B
AAbbcc x aabbcc

C
Aabbcc x aaBBcc

D
AaBbcc x aaBbCc

Solution

If a couple are A, B, and C and child have vanished dark color be a,b and c.so the genotype can be ABC and abc from parents.
So, the correct option is 'AaBbcc x aaBbCc'.
Question 5
1 / -0

Select the monohybrid ratio in Pea.

A
$$1039$$ tall $$:$$ $$178$$ dwarf

B
$$80$$ tall $$:$$ $$20$$ dwarf

C
$$401$$ tall $$:$$ $$133$$ dwarf

D
$$150$$ tall $$:$$ $$20$$ dwarf
Question 6
1 / -0

If a mutation occurs in a gamete, it would influence

A
only a single individual

B
sterility in the progeny

C
all successive generation of the parents

D
only the particular sex of the progeny, whose gamete had undergone mutation

Solution

A mutation that occurs in body cells that are not passed along to subsequent generations is a somatic mutation. A mutation that occurs in a gamete or in a cell that gives rise to gametes is special because they impact the next generation and may not affect the adult at all. therefore it would only influence a single individual.
So, 'the correct option is - only a single individual'.
Question 7
1 / -0

When a cross is made between round seed and yellow seeds (RrYy) and round seed and green seeds (Rryy), what proportion of phenotype in the offspring could be expected to be wrinkled and green

A
$$\dfrac{1}{8}$$

B
$$\dfrac{1}{4}$$

C
$$\dfrac{1}{2}$$

D
$$\dfrac{1}{16}$$

Solution

Gamete Ry ry
RY RRYy RrYy
Ry RRyy Rryy
rY rRYy rrYy
ry Rryy rryy
Since Yellow and Round seeds are dominant phenotypes, they are expressed in Heterozygous state.
Green and wrinkled seeds are expressed in recessive homozygous state, found only in rryy.
So, the correct option is 1/8.
Question 8
1 / -0

_____ is the root of any plant breeding programme

A
Mutation

B
micropropagation

C
Generic variability

D
Testing and commercialisation of new cultivars
Question 9
1 / -0

Mendel choose pea plants because

A
They were cheap

B
They were having seven pairs of contrasting characters

C
They were easily available

D
Of great economic importance

Solution

Mendel chose pea plants because they had easily observable characteristics and there were two contrasting observable traits of each character. There were seven pairs of such contrasting characters seen and used (manipulated) by Mendel for his experiments. So, the correct option is 'They were having seven pairs of contrasting characters'.
Question 10
1 / -0

In pea plant gene 'A' governs height of stem and gene 'B' governs starch grain size. If plant is heterozygous for these two genes and is selfed, what are proportionate presence of different phenotypic groups?

A
$$9:3:3:1$$

B
$$3:6:3:1:2:1$$

C
$$9:6:1$$

D
$$4:2:2:1$$

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Gamete	Ry	ry
RY	RRYy	RrYy
Ry	RRyy	Rryy
rY	rRYy	rrYy
ry	Rryy	rryy

Principles of Inheritance and Variation Test - 77

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Principles of Inheritance and Variation Test - 77

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SHARING IS CARING

Question 1

$$20$$ map units

$$9.8$$ map units

$$10.2$$ map units

$$10$$ map units

Solution

Question 2

Due to some defect like aspermia in man

Due to genetic makeup of some particular sperm which fertilizes the egg

Due to genetic makeup of the eggs

Due to some defect in women

Solution

Question 3

$$ 75 \% $$ pure and $$25 \%$$ impure

$$ 25 \% $$ pure and $$75 \% $$impure

$$ 50 \% $$ pure and $$50\%$$ impure

$$ 87.5 \% $$ pure and $$12.5 \%$$ impure

Solution

Question 4

Aabbcc x aaBbcc

AAbbcc x aabbcc

Aabbcc x aaBBcc

AaBbcc x aaBbCc

Solution

Question 5

$$1039$$ tall $$:$$ $$178$$ dwarf

$$80$$ tall $$:$$ $$20$$ dwarf

$$401$$ tall $$:$$ $$133$$ dwarf

$$150$$ tall $$:$$ $$20$$ dwarf

Question 6

only a single individual

sterility in the progeny

all successive generation of the parents

only the particular sex of the progeny, whose gamete had undergone mutation

Solution

Question 7

$$\dfrac{1}{8}$$

$$\dfrac{1}{4}$$

$$\dfrac{1}{2}$$

$$\dfrac{1}{16}$$

Solution

Question 8

Mutation

micropropagation

Generic variability

Testing and commercialisation of new cultivars

Question 9

They were cheap

They were having seven pairs of contrasting characters

They were easily available

Of great economic importance

Solution

Question 10

$$9:3:3:1$$

$$3:6:3:1:2:1$$

$$9:6:1$$

$$4:2:2:1$$

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