Principles of Inheritance and Variation Test

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Principles of Inheritance and Variation Test - 93

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Weekly Quiz Competition

Question 1
1 / -0

Which among the following is not true about garden pea

A
It belongs to the family Fabacceae and is a pulse

B
Its flowers are bisexual and is naturally self-pollinated

C
It contains seven pairs of chromosomes in the somatic cells

D
It has a generation time of 2-3 weeks

Solution

The generation time is more than 2-3 weeks.
So, option D is the correct answer.
Question 2
1 / -0

Quantitative/polygenic inheritance was first noted by

A
H. Nilson- Ehle and East

B
Galton

C
Mendel

D
Kolreuter.

Solution

Inheritance is controlled by two or more genes in which the dominant alleles have cumulative effect, with each dominant allele expressing a part of functional polypeptide and full trait is shown when all the dominant alleles are present, is called Polygenic or Quantitative inheritance. This was first noted by H.Nilson – Ehle and East.
So, the correct option is 'H.Nilson - Ehle and East'.
Question 3
1 / -0

Which is true for recessive disease in family A and B?

A
In family A, both parents are homozygous recessive

B
In family B, both the parents are homozygous dominant

C
In family B, both are parents are heterozygous recessive

D
In family A, both the parents are heterozygous recessive

Solution

1. Since the parents of family A are not affected by the disease, but a few of their offsprings are, they must be heterozygous recessive for the disease.
2. Both parents along with their offsprings are affected by the disease in family B, which clearly indicates they are homozygous recessive.
So, the correct option is 'In family A, both the parents are heterozygous recessive'.
Question 4
1 / -0

In a population of families having three children each, the percentage of population of families having both boys and girls is?

A
$$10$$

B
$$25$$

C
$$50$$

D
$$75$$

Solution

The concept of boys and girls could be modelled by probability. There would be 8 possible combinations - GGG, GGB, GBG, GBB, BBB, BBG, BGG, BGB, here, the combination with both girls and boys is 6, the percentage of which would be 75.
Question 5
1 / -0

Study the given pedigree chart for sickle-cell anaemia and select the most appropriate option for the genotypes.

A
Genotypes of parents - $$Hb^A Hb^S, Hb^A Hb^A$$, Genotypes of $$1^{st}$$ and $$3^{rd}$$ child in $$F_1$$ - $$Hb^A Hb^A, Hb^A Hb^S$$

B
Genotypes of parents - $$Hb^A Hb^S, Hb^A Hb^S$$, Genotypes of $$1^{st}$$ and $$3^{rd}$$ child in $$F_1$$ - $$Hb^A Hb^A, Hb^A Hb^A$$

C
Genotypes of parents - $$Hb^A Hb^A, Hb^A Hb^S$$, Genotypes of $$1^{st}$$ and $$3^{rd}$$ child in $$F_1$$ - $$Hb^A Hb^A, Hb^S Hb^S$$

D
Genotypes of parents - $$Hb^A Hb^S, Hb^A Hb^S$$, Genotypes of $$1^{st}$$ and $$3^{rd}$$ child in $$F_1$$ - $$Hb^A Hb^S, Hb^S Hb^S$$
Question 6
1 / -0

When two genes control a single character and have cumulative effect the ratio is _______

A
$$1:1:1:1$$

B
$$1:4:6:4:1$$

C
$$1:2:1$$

D
$$1:6:15:20:15:6:1$$

Solution

When two genes present on the same loci give an additive or cumulative effect like the spotted and Dotted seed of Lens sps the ratio is 1:2:1
So, the correct answer is '1:2:1'
Question 7
1 / -0

If a pea plant shows a recessive phenotype

A
it can be either U or It

B
it can be either Tt or II

C
it can be only U

D
it can be only tt

Solution

In pea plant, tt represents the pure dwarf condition, and the dwarf is a recessive phenotype, while tall is the dominant phenotype.
So, the correct option is 'it can be the only tt'.
Question 8
1 / -0

Choose the correct answer from the alternatives given.
Consider a cross in which a trait is inherited by incomplete dominance. What percentage of the $$F_2$$ from the mating of homozygous dominant and homozygous recessive, What percent of individuals will possess the dominant phenotype ?

A
100 percent

B
25 percent

C
50 percent

D
75 percent

Solution

In incomplete dominance, the offsprings with the heterozygous genotype show the intermediate character. When a homozygous dominant and a homozygous recessive individual are mated in such a condition the F2 generation will show a genotypic and a phenotypic ratio of 1:2:1 for homozygous dominant, heterozygous and homozygous recessive offsprings respectively. So, the percentage of homozygous dominant will be, 1/4 X 100 = 25%. So, the correct option is '25 percent'.
Question 9
1 / -0

Study the pedigree given below and assign the type of inheritance of the trait.

A
X-linked recessive

B
Y-linked

C
autosomal recessive

D
autosomal dominant

Solution

The given trait is X-linked recessive because it is transferred from mother to son. It is present in the homozygous dominant condition in the mother in the F1 generation, while in the 2nd son of the F2 generation, it is present in recessive condition. Same is seen with the female in the F3 generation, But in F4 generation, the first son is showing the homozygous dominant trait, thus getting affected.
So the correct option is 'X-linked recessive'.
Question 10
1 / -0

Type of ovule present in pea is

A
Anatropus

B
Compylotropus

C
Hemitropus

D
Amphitropus
Solution
- Type of ovule present in pea is compylotropus.

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Principles of Inheritance and Variation Test - 93

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Principles of Inheritance and Variation Test - 93

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SHARING IS CARING

Question 1

It belongs to the family Fabacceae and is a pulse

Its flowers are bisexual and is naturally self-pollinated

It contains seven pairs of chromosomes in the somatic cells

It has a generation time of 2-3 weeks

Solution

Question 2

H. Nilson- Ehle and East

Galton

Mendel

Kolreuter.

Solution

Question 3

In family A, both parents are homozygous recessive

In family B, both the parents are homozygous dominant

In family B, both are parents are heterozygous recessive

In family A, both the parents are heterozygous recessive

Solution

Question 4

$$10$$

$$25$$

$$50$$

$$75$$

Solution

Question 5

Genotypes of parents - $$Hb^A Hb^S, Hb^A Hb^A$$, Genotypes of $$1^{st}$$ and $$3^{rd}$$ child in $$F_1$$ - $$Hb^A Hb^A, Hb^A Hb^S$$

Genotypes of parents - $$Hb^A Hb^S, Hb^A Hb^S$$, Genotypes of $$1^{st}$$ and $$3^{rd}$$ child in $$F_1$$ - $$Hb^A Hb^A, Hb^A Hb^A$$

Genotypes of parents - $$Hb^A Hb^A, Hb^A Hb^S$$, Genotypes of $$1^{st}$$ and $$3^{rd}$$ child in $$F_1$$ - $$Hb^A Hb^A, Hb^S Hb^S$$

Genotypes of parents - $$Hb^A Hb^S, Hb^A Hb^S$$, Genotypes of $$1^{st}$$ and $$3^{rd}$$ child in $$F_1$$ - $$Hb^A Hb^S, Hb^S Hb^S$$

Question 6

$$1:1:1:1$$

$$1:4:6:4:1$$

$$1:2:1$$

$$1:6:15:20:15:6:1$$

Solution

Question 7

it can be either U or It

it can be either Tt or II

it can be only U

it can be only tt

Solution

Question 8

100 percent

25 percent

50 percent

75 percent

Solution

Question 9

X-linked recessive

Y-linked

autosomal recessive

autosomal dominant

Solution

Question 10

Anatropus

Compylotropus

Hemitropus

Amphitropus

Solution

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