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Molecular Basis of Inheritance Test - 29

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Molecular Basis of Inheritance Test - 29
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  • Question 1
    1 / -0
    If the total amount of adenine and thymine in a double-stranded DNA is 60% the amount of guainine in this DNA will be
    Solution
    If the amount of adenine+ thymine = 60%, then the amount of guanine + cytosine will be 40%. 
    So, the amount of guanine in this DNA will be = 20%.
  • Question 2
    1 / -0
    Select the correct option regarding genetic code of Glycine.
    Solution
    • The standard genetic code is represented as an RNA codon because, when proteins are made in a cell by ribosomes, it is mRNA that directs protein synthesis.
    •  Glycine is an amino acid, a building block for protein. The genetic code of glycine is GGU, GGA, GGC.

    • So, the correct answer is 'GGU, GGA, GGC'
  • Question 3
    1 / -0
    What is incorrect about the above figure representing DNA replication?

    Solution
    DNA polymerase can polymerize nucleotides only in $$5'\rightarrow 3'$$ direction on $$3'\rightarrow 5'$$ strand because it adds them at the $$3'$$ end. Since, the two strands of DNA run in antiparallel directions, the two templates provide different ends for replication. Replication over the two templates thus proceeds in opposite directions. One strand with polarity $$3'\rightarrow 5'$$ forms its complementary strands continuously because $$3'$$ end of the latter is open for elongation. It is called leading strand. Replication is discontinuous on the other template with polarity $$5'\rightarrow 3'$$ because only a short segment of DNA strand can be built in $$5'\rightarrow 3'$$ direction due to exposure of a small stretch of template at one time. Short segments of replicated DNA are called Okazaki fragments.
  • Question 4
    1 / -0
    Which of the following is correct regarding genetic code?
    Solution
    There are $$64$$-triplet codons which code for $$20$$ amino acids. This is due to the degeneracy of code as some amino acids are influenced by more than one codon. Only tryptophan and methionine are specified by single codons. All other amino acids are specified by two (e.g., phenylalanine-UUU, UUC) to six (e.g., arginine- CGU, CGC, CGA, CGG, AGA, AGG) codons.
  • Question 5
    1 / -0
    A segment of DNA contains 1200 nucleotides, of which 200 have adenine base. How many cytosine bases are present in this segment of DNA?
    Solution
    • According to Chargaff's rule, the proportion of adenine is equal to thymine and the proportion of cytosine is equal to guanine because they are complementary bases. 
    • There are 200 adenine bases. The number of thymine bases will be equal to adenine which is 200 bases. 
    • The total number of bases is 1200. So, the remaining bases are 1200-(200+200)= 800. 
    • From the 800 bases, the number of cytosine and guanine will be the same, which is equal to 400 bases each.

    Thus, the correct answer is option C. 
  • Question 6
    1 / -0
    Out of 64 codons, 61 codons code for 20 types of amino acid. What is it called as?
    Solution
    The genetic code is degenerate in that most amino acids are encoded by more than one codon with the exception of tryptophan and methionine which has only one codon. Codons that specify the same amino acids are called synonyms and these codons usually differ in the last base of the triplet.
  • Question 7
    1 / -0
    DNA multiplication is also called as
    Solution
    Multiplication of DNA is otherwise called as replication. It means the process of multiplication of DNA strand to give daughter strands. DNA replication is semi conservative in the case of eukaryotes.

  • Question 8
    1 / -0
    Which of the following statements is not true for retroviruses:
  • Question 9
    1 / -0
    What is an anticodon?
    Solution
    Anticodon is a sequence of three nucleotides in a region of transfer RNA that recognizes a complementary coding triplet of nulceotides in messenger RNA during translation by the ribosomes in protein biosynthesis.
  • Question 10
    1 / -0
    The experimental system used in studies of the discovery of replication of DNA has been
    Solution
    Escherichia coli is used for the studies related to the discovery of replication of DNA because of the following reasons:
    a) E. coli is a single-celled organism and it grows and reproduces rapidly which leads to the enormous amount of sample DNA that can be used for the study and experiments.
    b)  E. coli can survive in variable growth conditions. 
    c) The naturally occurring strains of E.coli are harmless.
    So, the correct answer is option C.
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