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Molecular Basis of Inheritance Test - 45

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Molecular Basis of Inheritance Test - 45
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  • Question 1
    1 / -0
    The regions expressed as polypeptides on mRNA are 
    Solution
    Exon is the nucleotide sequence of mRNA that carries information for the synthesis of a protein while the interrupting sequences that do not code for any protein but are present between exons in mRNA, are called as introns. The nucleotide sequence of exon determines the sequence and type of amino acids of a polypeptide. Cistron is defined as DNA segment that carries the genetic code for a single polypeptide and therefore functions as a hereditary unit, i.e., cistrons are transcribed as a unit into a single polynucleotide sequence of mRNA
    So, the correct answer is option B.
  • Question 2
    1 / -0
    "It has not escaped our notice that the specific pairing we have postulated immediately suggests a possible copying mechanisms for the genetic material," this is written by 
    Solution

    Francis Crick and James D. Watson published an article entitled as "Molecular Structure of Nucleic Acids: A Structure for Deoxyribose Nucleic Acid" in the scientific journal Nature dated 25 April 1953 which described the discovery of the double helix structure of DNA. The above quote refers to the fact the complementary base pairing is key to the double helical structure of DNA and the same pairing facilitates the synthesis of new DNA strands using parental DNA strand as a template.
    As we know that new DNA molecules are synthesized during replication which is a semi-conservative mechanism and forms a daughter DNA duplex carrying one parental and one new strand. This copying mechanism ensures inheritance of genetic information, present on DNA, from parents to offspring. 

  • Question 3
    1 / -0
    In genetic coding, triplet codons make possible 64 types of codons. If the genetic code was a doublet instead of a triplet codon, the number of types of codons possible would be
    Solution
    As we know that there are only four nucleotides namely deoxyadenosine, deoxyguanosine, deoxythymidine and deoxycytidine. Further, there are 20 essential amino acids that are to be encoded by these four nucleotides.  A triplet code could make a genetic code for 64 different combinations (4 X 4 X 4) genetic code. A code of single nucleotides would give only four amino acids to be translated. The doublet code would code for 16 amino acids (4 x 4). Option D is correct answer.
  • Question 4
    1 / -0
    In a double-stranded DNA, the sequence of base pairs in one strand is AGCTAAGC. What is the complementary sequence on the other strand?
    Solution
    According to Watson and Crick model, DNA has four nitrogenous bases, that includes two purines and two pyrimidines, in its nucleotide chains. The purines are adenine and guanine and pyrimidines are namely cytosine, thymine. In a dsDNA, a purine always pairs with a pyrimidine and a pyrimidine base pairs with purine base only; thus, adenine pairs with thymine (A-T) and guanine pairs with cytosine (G-C). A DNA strand with sequence "AGCTAAGC" will have a complementary strand with the sequence "TCGATTCG". Uracil (U) is a pyrimidine base that is present in RNA in place of T; it is not found in DNA. The sequence given in option B and D have "U", which makes them wrong. A DNA strand cannot have the same base sequence in its complementary strand; thus option C is wrong.
  • Question 5
    1 / -0
    A naturally occurring coding strand composed of alternating C and U residues would result in the formation of polypeptide containing
    Solution
    As we know that a set of three bases of mRNA, called as triplet codon, specify one amino acid. Also genetic code is commaless and non-overlapping which means that one base can not be shared by two sequential triplets and the codons are read sequentially. A naturally occurring coding strand composed of alternating C and U residues would have codons as: CUCUCUCUCUCUCUCUCUCUCUCUCUCUCUCUCUC and so on. If read as triplet, it gives two alternating codons "CUC" and "UCU". 
    The codon CUC codes for leucine and UCU codes for serine. Thus, the resultant polypeptide will contain alternating leucine and serine residues. Correct option is A. 
    An mRNA strand with a series of CUCCUCCUCCUCCUCCUCC will give only leucine residues in the polypeptide; option B and C are wrong. Likewise an mRNA with sequence UCUUCUUCUUCUUCUUC will give only serine residues in the polypeptide; option B and D are wrong. To have phenylalanine rich polypeptide with U and C bases, the mRNA should have sequence UUCUUCUUCUUCUUCUUCUUC; option E is wrong.
  • Question 6
    1 / -0
    Which of the following help in repairing of DNA?
    Solution
    DNA polymerase I serve clean-up functions during replication, recombination, and repair. It has 3' --> 5' proofreading exonuclease activity and 5' --> 3' exonuclease activity. The 5' --> 3' exonuclease activity of DNA polymerase I can replace an error containing the segment of DNA/RNA, paired to the template strand which is then simultaneously replaced by polymerase activity of the same enzyme. The process is called as nick translation. DNA polymerase III with its ten types of subunits has 5' --> 3' polymerization and 3' --> 5' proofreading activities in its $$\alpha$$ and $$\epsilon$$ subunits, respectively. 
    As DNA pol III does not have 5' --> 3' exonuclease activity; it can not remove the erroneous segments of DNA/RNA. RNA primer is an oligonucleotide, synthesized by primase enzyme, that is elongated into long strands of deoxyribonucleotides or ribonucleotides by DNA and RNA polymerase enzymes respectively. Ligase enzyme joins two DNA strands by facilitating phosphodiester bond formation between the adjacent nucleotides; it can not cut and remove the DNA segments and thus, can not repair DNA. The correct option is B.
  • Question 7
    1 / -0
    Which one of the following pairs are correctly matched with regard to the codon and the amino acid coded by them?
    Solution
    A set of three nucleotide bases specify particular amino acid; the set is called as triplet codon. The triplet "UUA" codes for leucine while valine is encoded by GUA, GUG, GUC, GUU; option A is wrong. The triplet "AAA" codes for lysine; option B is right. The triplet "AUG" codes for methionine while cysteine is encoded by UGU and UGC; option C is wrong. The triplet "CCC" codes for proline while alanine is encoded by GCA, GCC, GCG, GCU; option D is wrong.
  • Question 8
    1 / -0
    Which one of the following lacks active site of RNA polymerase?
    Solution
    The DNA-dependent RNA polymerase of is a large, complex, holoenzyme. It has five core subunits (Mr 390,000) and a sixth subunit. The five core units are two copies of alpha subunit, one copy of each beta, beta prime and omega subunit. The sigma subunit carries active site of the enzyme and binds transiently to the core to direct the enzyme to specific binding sites on the DNA. Thus the core enzyme ($${\alpha _2\beta {\beta}'}$$) lacks active site. Correct answer is D.
  • Question 9
    1 / -0
    DNA strands
    Solution
    Quaternary structure of the protein refers to the number and arrangement of multiple folded protein subunits with respect to each other to form a multi-subunit complex; it does not include any molecule other than polypeptide chains. Quaternary structure of DNA refers to the organization of DNA into chromatin via histone octamers to arrange it into a condensed structure; statement A is incorrect. Each nucleotide base of one strand is paired, via a hydrogen bond, in the same plane with a base of the other strand thereby joining two strands together; statement B is incorrect. The same orientation of all phosphodiester linkages along the chain imparts each linear nucleic acid strand a distinct polarity and distinct 5’ and 3’ ends; statement C is incorrect. The 5’ end lacks a nucleotide at the 5’ position thereby having free phosphate group and the 3’ end lacks a nucleotide at the 3’ position thereby having a free hydroxyl group. The two DNA strands are antiparallel means that 5’ end of one strand faces 3’ end of other strand and vice versa. Thus, option D is correct. 
  • Question 10
    1 / -0
    During splicing, the exons are joined and the enzyme which catalyzes this reaction is 
    Solution
    RNA primase synthesizes RNA primer which is a strand segment (complementary to the template) and has a free 3’ hydroxyl group to facilitate addition of nucleotides by polymerase enzymes. RNA polymerase synthesizes RNA using DNA template strand by adding the ribonucleotides to a primer in 5' to 3' direction via phosphodiester bonds. Splicing is removal of introns from the primary transcript and ligation of exons to form a continuous sequence specifying a functional polypeptide. RNA ligase enzyme joins two exons together via phosphodiester bond between 3’ hydroxyl at the end of one exon and a 5’ phosphate at the end of another exon. 
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