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Evolution Test - 85

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Evolution Test - 85
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  • Question 1
    1 / -0
    One way to classify humans is by their blood type. There are over two dozen ways to group blood types. One of them is by the presence of the D antigen on the surface of blood cells. If an individual expresses the D antigen, they are referred to as Rh positive. This is controlled by an autosomal dominant allele. In a given town, 16% of the student population is considered Rh negative.
    If this town's high school has 2,000 students, how many would you expect to be heterozygous for the D antigen?
    Solution
    16% of the student population is Rh$$^-$$, that the frequency of the recessive allele (q) is .16
    The frequency of the dominant allele is determined by p+q = 1
                                                                                                 p + 0.16 = 1
                                                                                                 p = 1 - 0.16
                                                                                                   = 0.84
    According to the Hardy Wienberg equation, the heterozygous condition in the population is represented by 2pq 
                                 = 2 (.16 x 0.84)
                                 =0.2688
    For a population size of 2000 = 0.2688 x 2000
                                                       = 538
     
  • Question 2
    1 / -0
    A population of squirrels has 100 black individuals and 400 grey individuals.
    What is the phenotype frequency of black squirrels?
    Solution

    The Hardy-Weinberg law can be used under some circumstances to calculate genotype frequencies from allele frequencies. Let A1 and A2 be two alleles at the same locus,

    p is the frequency of allele A10 =< p =< 1
    q is the frequency of allele A20 =< q =< 1 and p + q = 1
    if they procreate :    (p + q)2 = p2 + 2pq + q2 = 1
    where:
    p2 = frequency of the A1 A1 genotype <-- HOMOZYGOUS
    2pq = frequency of the A1 A2 genotype   <-- HETEROZYGOTE
    q2 = frequency of the A2 A2 genotype  <-- HOMOZYGOUS 
    these frequencies remain constant in successive generations. So, the correct answer is " 0.2 ".
  • Question 3
    1 / -0
    Which of the following questions would best be tested using mathematical modeling?
    Solution
     Mathematical modeling:-Is the practice of making sense of the world through a mathematical perspective.
    Purpose of a mathematical model:- The model formulation process clarifies assumptions, variables and parameters. The behavior of precise mathematical models can be analyzed using mathematical methods and computer simulations. Modeling is an experimental tool for testing theories and assessing quantitative conjectures.
    So, the correct answer is "If 75% of individuals with a dominant phenotype do not reproduce, how many generations will it take for the dominant allele to be eliminated from the population?
  • Question 4
    1 / -0
    One way to classify humans is by their blood type. There are over two dozen ways to group blood types. One of them is by the presence of the D antigen on the surface of blood cells. If an individual expresses the D antigen, they are referred to as Rh positive. This is controlled by an autosomal dominant allele. In a given town, 16% of the population is considered Rh negative.
    If this town's high school has 2,000 students, how many would you expect to have the homozygous recessive genotype?
    Solution
    Autosomal dominant allele:- The first allele is dominant and the second allele is recessive.
    total number of town's high school- 2000. then we have to calculate the 16% of the 2000 is 320.
    So, the correct answer is "320".
  • Question 5
    1 / -0
    In the late 1970's, the Galapagos Islands experienced a severe drought that sharply reduced the finch population living there. It was discovered that only finches with large, thick beaks survived the drought as they subsisted on cactus, which are drought tolerant plants.
    In the early 1980's, the Galapagos Islands underwent an El Nino event that led to higher annual levels of precipitation than normal. This climate event occurred just a few years after the drought. The increase in rainfall led to a dramatic increase in growth of seed-producing plants, which led to an abundance of foods for seed-eating finches, which have small, short beaks.
    The increase in rainfall also decreased the availability of cactuses on the islands. Which of the following would you predict occurred in the finch population as a result of the second change in climate? 
    Solution
    The finches show the case of natural selection. According to Darwin's concept of natural selection, as a struggle for existence, only those organisms could survive which have favourable variation to adapt with the environmental conditions. In other words, struggle for existence results in survival of the fittest which means that natural selection tends to favour those organisms which are most fit to survive with the reproductive age in a particular environment and to produce offspring.
    Hence, as result of second change in the environment, short beaked finches will predominate as they will be able to survive but the population of long beaked finches will decline a they won't be able to adapt to the change in environment.
    So, the correct answer is 'The population of short-beaked finches increased while the population of large beaked birds decreased'.
  • Question 6
    1 / -0
    Find the mis-match from the following pairs.
    Solution
    • Genetic drift describes random fluctuations in the numbers of gene variants in a population.
    • It takes place when the occurrence of variant forms of a gene, called alleles, increases and decreases by chance over time. 
    • So, the gene frequency keeps on changing and is not constant.
    • Thus, the correct answer is option D.
  • Question 7
    1 / -0
    Human earwax texture is determined by a single gene with two alleles, wet and dry. Dry is recessive and wet is dominant.
    Evidence suggests that the dry allele first appeared in Eastern Asia about 2,000 generations ago. The frequency of the dry allele in a European population is .15. What percentage of this population is expected to have the wet earwax phenotype?
    Solution
    According to Hardy Wienberg's principle the sum of the two alleles is 1, where the dominant allele is represented by p, while the recessive allele is represented by q, that is, p + q = 1
    Here, the dry allele percentage in the population is .15
    Therefore, the wet allele percentage is = 1 - .15 = .85
    So, the correct answer is '0.85'
  • Question 8
    1 / -0
    Convergent evolution in closely related species is called 
    Solution
    Convergent evolution is similar to parallel evolution, which occurs when two independent species evolve in the same direction and thus independently acquire similar characteristics. For example, Tasmanian wolf is a marsupial while a wolf is a placental mammal.
    So, the correct answer is "Parallel evolution".
  • Question 9
    1 / -0
    Examine the data showing the percent identity of the GAPDH gene and protein sequences between humans and the three species shown below.
    SpeciesGene IdentityProtein Identity
    Chimpanzee99.6%100%
    Fruit Fry72.4%76.7%
    Roundworm68.2%74.3%
    Provide a plausible reason for why the percent identity between gene sequences is lower than the percent identity of protein sequences.
    Solution
    The coding sequences on the genes differ due to different ancestral lineages, however since an amino acid is coded by multiple codons, that is a single amino acid is represented by more than one codons, even though the genetic code varies in different organisms, they may happen to code for the same amino acid. The property also known as degeneracy of genetic code.
    So, the correct answer is 'Multiple codons code for the same amino acid'
  • Question 10
    1 / -0
    In a particular population of mice that lives in the Southwestern United States, there are two fur color variants: black and light brown. The black fur is a dominant trait in these mice. The population described lives in an area dominated by dark-colored rock and that is populated by owls that prey upon mice that do not blend into the environment. The frequency of the black fur allele in this particular population is 0.6.
    If the rock were to become covered by sand dunes, what change in the population would you predict? 
    Solution
    Black fur mice is dominant in the area as it can escape the owls by blending with the dark-coloured rocks. If the rock will get covered by sand dunes, then light fur mice will be able to escape the owls and predominate in the area as they will be able to blend with the environment but the dark fur mice will be unable to do this. Hence, dark fur mice will be eaten by the owls and light fur mice will predominate in the area. This is in accordance with Darwin's natural selection that as a struggle for existence, only those organisms could survive which have favourable variation to adapt with the environmental conditions. In other words, struggle for existence results in survival of the fittest which means that natural selection tends to favour those organisms which are most fit to survive with the reproductive age in a particular environment and to produce offspring.
    Hence, the frequency of mice having light fur will increase.
    So, the correct answer is 'The frequency of the light fur color would increase'.
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