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Alcohols Phenols and Ethers Test - 47

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Alcohols Phenols and Ethers Test - 47
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  • Question 1
    1 / -0
    Which of the following leads to formation of $${ 1 }^{ 0 }$$ alcohol?
    Solution
    Morbenzene rule $$\rightarrow H^+$$ goes to carbon having more hydrogen among the double bond ones.

  • Question 2
    1 / -0
    The IUPAC name of the compound is: 

    Solution
    For naming a compound, the longest carbon chain is considered and the carbon atom near the functional group is given the first number or priority.

    Hence, $$-OH$$ is at second carbon and a double bond is between third carbon. Also, a methyl group is present at the third carbon. 

    So, the IUPAC name of the compound will be $$3-methyl  pent-3-en-2-ol$$.

    Hence, option $$C$$ is correct.
  • Question 3
    1 / -0
    Which of the following is the best reagent to convert $$1-$$ Methylcyclohexene into $$2-$$ methylcyclohexanol?
    Solution

  • Question 4
    1 / -0
    Identify $$Z$$ in the sequence of reaction, $$CH_3CH_2CH = CH_2 \xrightarrow{HBr/H_2O_2} Y \xrightarrow{C_2H_5ON_a} Z$$
    Solution

  • Question 5
    1 / -0
    Which of the following ether is not cleaved by HI even at 525K ?
    Solution
    Will not cleaned by HI even at $$525k$$ temperature.Cyclic ether don't reaction by HI.

  • Question 6
    1 / -0
    Propene is allowed to react with HBr in the presence of benzoyl peroxide, and the product is subsequently heated with aqueous KOH. The final product obtained is:
    Solution
    Propene is allowed to react with $$HBr$$ in the presence of benzoyl peroxide, and the product is subsequently heated with aqueous $$KOH$$. The final product obtained is $$propan-1-ol$$

  • Question 7
    1 / -0
    $$\underrightarrow { { H }^{ 2 } } $$

    Solution
    solution is given

  • Question 8
    1 / -0
    The final product 'X' is:

  • Question 9
    1 / -0

    What is $$A$$?

    Solution
    Option A is the correct answer.
    As we can see from the given mechanism, the compound at Option A will be formed.

  • Question 10
    1 / -0
     

    Solution

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