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Alcohols Phenols and Ethers Test - 62

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Alcohols Phenols and Ethers Test - 62
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Weekly Quiz Competition
  • Question 1
    1 / -0
    Which one of the following cannot be the product of the dehydration reaction of the above shown alcohol?

    Solution
    The reactions are given below. All the possible products are shown. Option C can not be formed.

  • Question 2
    1 / -0
    What is $$A$$ ?

    Solution
    Catalytic p-toluenesulfonic acid $$(TsOH)$$ reacts as acid and gives elimination products with the formation of $$TsO-CH_2-C\equiv CH$$.

  • Question 3
    1 / -0
    Reactions I and II are limited mainly to naphthalene compounds. These reactions are called, respectively:

    Solution
    The Bucherer reaction is the reversible conversion of a naphthylamine to a naphthol in the presence of an aqueous sulfite or bisulfite.
    The reaction is given as shown above. 

  • Question 4
    1 / -0
    Which of the following is the correct method for synthesizing methyl-t-butyl ether?
    Solution
    In the synthesis of n-alkyl ter-alkyl ether by Williamson's method, 
    $$\displaystyle 1^{\circ}RX\:and\:3^{\circ} RONa$$ are used.

    If $$\displaystyle 3^{\circ}RX$$ is used, it will undergo dehydrohalogenation to form alkene.

    Hence, the correct method for synthesising methyl-t-butyl ether is:

    $$\displaystyle \left ( CH_{3} \right )_{3}CONa+CH_3Br\rightarrow \left ( CH_{3} \right )_{3}COMe+NaBr$$
  • Question 5
    1 / -0
    When the given compound is treated with $${C}_{2}{H}_{5}MgBr$$ followed by hydrolysis, the product is:

    Solution

  • Question 6
    1 / -0
    Give the decreasing order of reactivity of the following alkyl halides in the Williamson' s reaction.
    i. $$\displaystyle \left ( CH_{3} \right )_{3}C-CH_{2}Br$$
    ii. $$\displaystyle ClCH_{2}CH=CH_{2}$$
    iii. $$\displaystyle ClCH_{2}CH_{2}CH_{3}$$
    iv. $$\displaystyle  BrCH_{2}CH_{2}CH_{3}$$
    Solution
    ii > iv > iii > i (ally chloride > $$\displaystyle RX=1^{\circ}RBr> 1^{\circ}>$$ neopentyl bromide. (R-Br) bond is weaker than (R-CI) bond. $$SN^{2}$$ reaction is faster with (R-Br) than with (R-CI).
  • Question 7
    1 / -0
    The product (B) is :

    Solution
    The cleavage of (C- OH) bond is feasible rather than cleavage of (Ar-OH)  bond because of resonance stabilistion in ArOH.
  • Question 8
    1 / -0
    The compound (A) is:

    Solution
    Red $$P$$ and $$HI$$ is a traditional reducing agent to convert alcohols into alkanes. $$H_3PO_3$$ form in this reduction reaction. The product $$A$$ of reaction is cyclobutandicarboxylic acid.   

  • Question 9
    1 / -0
    Which statement is correct for the conversion of $$ROH$$ to $$RX$$ by reagents $$(A)$$ $$ ( SOCl_{2},\ PBr_{3}$$ $$ PCl_{3}$$ $$ Pl_{3},\:TsCl  )$$ compared to using $$HX$$?
    Solution
    All the three statements (A), (B) and (C) are correct. Hence, (D) is the correct option.

    (A) No rearrangement occurs with predictable stereochemistry by reagents $$(A)$$. However if $$HX$$ is used, the rearrangement is possible.

    (B) Reagents $$(A)$$ are not useful for tertiary  alcohols, while $$HX$$ reacts easily with tertiary alcohols involving no rearrangement.

    (C) Reagents $$(A)$$ must be used in anhydrous conditions because all react vigorously with $$H_2O$$ and they produce harmful gases ($$SO_2$$, $$HCl$$, $$HBr$$ and $$HI$$).  

    For example, phosphorous trichloride reacts with water to form orthophosphorous acid and $$HCl$$.

    $$PCl_3 + 3H_2O \rightarrow P(OH)_3 + 3HCl$$
  • Question 10
    1 / -0
    Which statement is correct for the conversion of ROH to RX by reagents $$\displaystyle \left ( SOCl_{2},PBr_{3},PCl_{3},PI_{3} \right )$$  and TsCl compared to using HX?
    Solution
    All the statements given in options A, B and C are correct for the conversion. Hence option D is correct.
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