Alcohols Phenols and Ethers Test

Result

Alcohols Phenols and Ethers Test - 65

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Weekly Quiz Competition

Question 1
1 / -0

$$CH_3CH_2-OH\xrightarrow{A}CH_3-CH_2-Cl\xrightarrow{B}CH_2=CH_2.$$

A and B in this sequence of reactions are :

A
KOH(aq) and $$PCl_5$$

B
$$PCl_5$$ and KOH(aq)

C
$$Cl_2$$ and KOH(alc)

D
$$PCl_5$$ and KOH(alc)

Solution

A and B in this sequence of reactions are $$\displaystyle PCl_5$$ and KOH(alc).

$$\displaystyle CH_3CH_2OH\xrightarrow{PCl_5(A)}CH_3CH_2Cl\xrightarrow{alc.KOH(B)}CH_2=CH_2$$

Ethanol reacts with $$PCl_5$$ to give ethyl chloride. Ethyl chloride on heating with alcoholic potash undergoes dehydrohalogenation to give ethene.

Hence the correct option is D.
Question 2
1 / -0

$$R-OH\xrightarrow {P+I_2}A\xrightarrow[alc. \ KCN]{Heating}B\xrightarrow[Na/alcohol]{LiAlH_4}C\xrightarrow[NaNO_2+dil\ HCl]{HNO_2}D$$

What are $$A,B,C$$ & $$D$$ respectively?

A
$$R-I$$, $$R-CN$$, $$R-NH_2$$, $$R-CH_2OH$$

B
$$R-I$$, $$R-CN$$, $$R-CH_2-NH_2$$, $$R-CH_2OH$$

C
$$R-I$$, $$R-NC$$, $$R-CH_2-NH_2$$, $$R-CH_2OH$$

D
$$R-I$$, $$R-CN$$, $$R-CH_2-NO_2$$, $$R-CH_2OH$$

Solution

$$R-OH\xrightarrow{P+I_2}R-I\xrightarrow[alc KCN]{Heating}R-CN\xrightarrow[Na/alchohol]{LiAlH_4}R-CH_2-NH_2\xrightarrow[NaNO_2+dil\ HCl]{HNO_2}R-CH_2OH$$

Hence option B is correct.
Question 3
1 / -0

$$R-OH\xrightarrow {PBr_3}A\xrightarrow[]{Mg/Dry \ ether}B\xrightarrow[CH_2-CH_2-O]{Grignard\ reaction}C\xrightarrow[]{H^+/H_2O}D$$

What are $$A,B,C$$ and $$D$$ are respectively?

A
$$R-Br,R-Mg-Br,R-CH_2-O-Mg-Br,R-CH_2CH_2-OH$$

B
$$R-Br,R-Mg-Br,R-CH_2-O-CH_2-Mg-Br,R-CH_2CH_2-OH$$

C
$$R-Br,R-Mg-Br,R-CH_2-CH_2-O-Mg-Br,R-CH_2CH_2-OH$$

D
$$R-Br,R-Mg-Br,R-CH_2-CH_2-O-Mg-Br,R-CH_2OH$$

Solution

$$R-OH\overset{PBr_3}{\rightarrow}R-Br\xrightarrow[]{Mg/Dry\ ether}R-Mg-Br\xrightarrow[CH_2-CH_2-O]{Grignard\ reaction}R-CH_2-CH_2-O-Mg-Br\\ \quad \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \quad \quad \quad \quad \quad \quad \quad \quad \quad \quad \quad \quad \quad \quad \quad \xrightarrow[]{H^+/H_2O}RCH_2-CH_2-OH$$

$$PBr_3$$ converts primary or secondary alcohol to alkyl halide. Mg and dryether forms Grignard reagent R-Mg-X , which on reaction with epoxide like ethylene oxide ($$CH_2CH_2O$$) forms $$R-CH_2CH_2-O-Mg-Br$$ and then in presence of acid gives alcohol.

So the order is $$R-Br, R-Mg-Br, \ R-CH_2-CH_2-O-Mg-Br,\ R-CH_2CH_2-OH$$.

Hence option C is correct,
Question 4
1 / -0

Phenol is an organic compound even though it is soluble in water due to the presence of:

A
ionic bonding

B
covalent bonding

C
hydrogen bonding

D
coordinate bonding

Solution

Phenol is an organic compound even though it is soluble in water due to the presence of hydrogen bonding. Phenol has hydroxyl group which is involved in the formation of hydrogen bonds with water. It increases the solubility. Hydrogen bonding is possible when $$H$$ atom is attached to electronegative $$N,\ O$$ or $$F$$ atom.
Question 5
1 / -0

Identify E:

A
ethene

B
ethane

C
ethyne

D
propyne

Solution
Question 6
1 / -0

Product formed in the following reaction is/are :

A

B

C
both (A) and (B)

D
none is correct

Solution

$$Y$$ is less soluble than $$\left(X\right)$$ due to lack of symmetry of chiral carbon. This is reduced to $$-C{H}_{2}OH$$.
Question 7
1 / -0

$$CH_3-OH\xrightarrow{P+I_2}A\xrightarrow[alc\ KCN]{Heating}B\xrightarrow[Na/alcohol]{LiAlH_4}C\xrightarrow[NaNO_2\ + \ dil \ HCl] {HNO_2}D$$

What is $$D$$?

A
$$CH_3CHO$$

B
$$CH_3COOH$$

C
$$CH_3CH_2OH$$

D
$$CH_3-O-CH_3$$

Solution

$$CH_3-OH\xrightarrow{P+I_2}CH_3-I\xrightarrow[alc \ KCN]{Heating}CH_3-CN\xrightarrow[Na/ethyl \ alchohol]{LiAlH_4}CH_3-CH_2NH_2\xrightarrow[NaNO_2+dil \ HCl]{HNO_2}CH_3-CH_2OH$$

Hence option C is correct.
Question 8
1 / -0

Under suitable condition temperature,pressure and catalyst,methanol can be obtain by:

A
partial oxidation of hydrocarbons

B
reacting $$H_2$$ with $$CO$$

C
reacting $$H_2$$ with $$CO_2$$

D
All the above

Solution

Partial oxidation of hydrocarbons produces methanol.
$$CO + 2H_2O \longrightarrow CH_3OH$$
$$CO_2 + H_2O \longrightarrow CH_3OH + H_2O$$
All the three processes produces mathanol.
Question 9
1 / -0

The major product of the reaction is:

A
I

B
II

C
III

D
IV

Solution
Question 10
1 / -0

Methyl phenyl ether can be obtained by reacting:

A
Phenolate ions and methyl iodide

B
Bromobenzene with methoxide ions

C
Methanol and phenol

D
Bromobenzene and methyl iodide

Solution

Methyl phenyl ether can be obtained by reacting phenolate ions and methyl iodide. Methyl phenyl ether is also known as anisole. The reaction is called Williamson's reaction.
$$ \displaystyle \underset { \displaystyle \text { phenol } }{ C_6H_5-OH} + NaOH \rightarrow \underset { \displaystyle \text { sodium phenoxide } }{ C_6H_5-ONa} \xrightarrow {\underset { \displaystyle \text { methyl iodide } }{ CH_3-I}} \underset { \displaystyle \text { anisole } }{ C_6H_5-O-CH_3}$$
Williamson's reaction can be used for the preparation of simple as well as mixed ethers.