Aldehydes Ketones and Carboxylic Acids Test

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Aldehydes Ketones and Carboxylic Acids Test - 14

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Weekly Quiz Competition

Question 1
1 / -0

$$CH_{3}COOH \xrightarrow []{LiAlH_{4}}X \xrightarrow []{Cu/300^{o}C} Y \xrightarrow []{dil.NaOH}Z$$ in the above reaction $$Z$$ is

A
Acetal

B
Ketal

C
Aldol

D
Acid

Solution
Question 2
1 / -0

$$CH_3CH_2Cl \xrightarrow {aq.\ KOH} X \xrightarrow {K_2Cr_2O_7/H^+} Y$$

Which of the following represents Y?

A
Ethylene

B
Acetic acid

C
Acetylene

D
Acetone

Solution

$$C_2H_5Cl\xrightarrow []{aq.\,KOH}C_2H_5-OH$$ $$\xrightarrow[]{K_2Cr_2O_7,H^+}CH_3COOH$$

$$X$$: Ethanol

$$Y$$: Acetic acid
Question 3
1 / -0

The IUPAC name of the given compound is:

A
4-pentanone

B
Pentanone-2

C
Pentan-2-one

D
none of the above

Solution

The correct IUPAC name is 2- Pentanone or Pentan-2-one. The parent hydrocarbon contains 5 $$C$$ atoms.

Hence the given compound is derivative of pentane. The second carbon atom has carbonyl group. Hence, $$e$$ from pentane is replaced with $$one $$ to obtain pentanone.

The position of carbonyl group is represented by number 2.

Option C is correct.
Question 4
1 / -0

The compound(B) in the below reaction is:

$$C_{2}H_{5}Cl\overset{KCN}{\rightarrow}A\overset{H_{3}O^{+}}{\rightarrow}B$$

A
ethylene chloride

B
acetic acid

C
propionic acid

D
ethyl cyanide

Solution

$$C_{2}H_{5}Cl\overset{KCN}{\rightarrow}\underset {A}{C_{2}H_{5}-C \equiv N} \overset{H_{3}O^{+}}{\rightarrow}\underset {B}{C_{2}H_{5}-COOH}$$

In the first reaction, cyanide ion substitutes chloride ion.

In the second reaction, acid hydrolysis converts the cyanide group to the carboxylic group.

The compound (B) in the below reaction is propionic acid.

Option C is correct.
Question 5
1 / -0

.

A
oxidation, chlorination

B
reduction, chlorination

C
oxidation, addition

D
reduction, substtution
Solution
- The first step is oxidation with suitable oxidising agent $$(CrO_2Cl_2/CS_2)$$ that will convert alcohol to aldehyde.
- Second step is chlorination that will substitute the hydrogen of aldehyde in the presence of $$(Cl_2/hv)$$.
Question 6
1 / -0

General formula of saturated monocarboxylic acid is :

A
$$C_{n}H_{2n+1} COOH$$

B
$$C_{n}H_{2n}O_{2}$$

C
Both A and B

D
None of the above

Solution

Monocarboxylic acids are in the form of $$RCOOH$$.

Let's take examples,
For R is $$-H$$ or $$-CH_{3}$$,

a) $$HCOOH\to C_{1}H_{2}O_{2}$$ which is following $$C_n H_{2n} O_2$$ trend.

b) $$CH_{3}COOH\to C_{2}H_{4}O_{2}$$ which is also following $$C_n H_{2n} O_2$$ trend.

When R is other than $$-H$$ or $$-CH_{3}$$ group,

a) $$C_{2}H_{5}COOH\to C_{3}H_{6}O_{2}$$ which is following $$ C_n H_{2n+1} COOH$$ trend.

So, the general formula is both A & B, i.e., $$C_n H_{2n} O_2$$ and $$ C_n H_{2n+1} COOH$$.

Hence, both options A and B are correct.

Option C is correct.
Question 7
1 / -0

The IUPAC name of the compound is:

A
hexane-2,4-dione

B
hexane-2,4-diol

C
pentane-2,4-dione

D
heptane-2,4-dione

Solution

$$\underset{6}{CH_3}- \, \underset{5}{CH_2}- \, \underset{4}{\overset{O}{\overset{||}{C}}} -\, \underset{3}{CH_2}- \, \underset{2}{\overset{O}{\overset{||}{C}}}- \, \underset{1}{CH_2}$$

$$Ketone$$ is the main functional group as two ketone groups so its suffix is -dione.

$$\Rightarrow 6$$ carbon chain

Hexane-2,4-dione

Option A is correct.
Question 8
1 / -0

The IUPAC name of the compound is:

A
3 - Methyl - 5 - heptanone

B
5-Methylheptan-3-one

C
5 - Ethyl - 5 - hexanone

D
2 - Ethyl - 4 - hexanone

Solution

It contains ketonic group on third carbon and one methyl group is substituted to the fifth carbon of the parent chain.

The IUPAC name is 5-Methylheptan-3-one.
Question 9
1 / -0

A compound of general formula $$C_{n}H_{2n}O_{2}$$ could be :

A
an acid

B
a diketone

C
an ether

D
an aldehyde

Solution

Formula i $$C_n H_{2n} O_2$$ (H is double of C)
i) $$acid: CH_3 COOH \cdot C_n H_{2n} O_2$$
diketane:
ether: $$CH_3 OCH_3\cdot single oxygen$$
aldehyde : $$ CH_3 CHO\cdot single oxygen$$
Question 10
1 / -0

$$CH_{3}Cl \xrightarrow[]{KCN} A \xrightarrow[]{H_{3}O^+} B$$

In this reaction, the product B is :

A
$$CH_{3}COOC_{2}H_{5}$$

B
$$CH_{3}COOH$$

C
$$HCOOH$$

D
$$CH_{3}CONH_{2}$$

Solution

The complete reaction sequence is as follows:
$$CH_{3}Cl \xrightarrow[]{KCN} CH_3CN \xrightarrow[]{H_{3}O^+} CH_3COOH$$

Nitriles are hydrolysed to amides and then to acids in the presence of $$H^+$$ or $$OH^-$$ as the catalyst. Mild reaction conditions are used to stop the reaction at the amide stage.

Hence, $$A$$ is $$CH_3CN$$ and $$B$$ is $$CH_3COOH$$.

Option B is correct.