Aldehydes Ketones and Carboxylic Acids Test

Result

Aldehydes Ketones and Carboxylic Acids Test - 16

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Weekly Quiz Competition

Question 1
1 / -0

Which of the following compounds does not have a carboxyl group?

A
Methanoic acid

B
Ethanoic acid

C
Picric acid

D
Benzoic acid

Solution
Question 2
1 / -0

The oxidation products of 1-nitronaphthalene and $$\alpha$$-naphthylamine respectively are :

A
phtalic acid and 3-aminophthalic acid

B
3-nitrophtalic acid and phtalic acid

C
phtalic acid and phthalic acid

D
3-nitrophtalic acid and 3-aminophthalic acid

Solution
Question 3
1 / -0

From above reaction, the formation of product is:

A
HCOOH

B

C

D

Solution
Question 4
1 / -0

$$X$$ is:

A

B

C

D

Solution

It is an example of oxidative cleavage. The $$C=C$$ double bond breaks and C atoms attached to double bond are oxidised to carboxylic groups.
Question 5
1 / -0

What is the compound $$A$$?

A
Oxalic acid

B
Malonic acid

C
Succinic acid

D
Adipic acid

Solution

Acidified potassium permanganate oxidizes cyclohexene to adipic acid (hexane-1,6-dioic acid).
Question 6
1 / -0

Toluene$$\xrightarrow[]{KMnO_{4}/KOH/H_{3}O^{\bigoplus }}$$ A.

What is A?

A
Acetice acid

B
Benzene

C
Benzoic acid

D
Benzaldehyde

Solution
Question 7
1 / -0

In the manufacture of acetic acid from aerial oxidation of acetaldehyde, the catalyst used is :

A
acidified $$K_{2}Cr_{2}O_{7}$$

B
$$(CH_{3}COO)_{2}Mn$$

C
$$HgSO_{4}$$

D
$$Ni$$

Solution

B
Question 8
1 / -0

$$CH_{3}CH_{2}CH_{2}CHO\overset{x}{\rightarrow}CH_{3}CH_{2}CH_{2}COOH$$
In the above reaction X is an oxidising agent and X is__________.

A
Tollens reagent

B
Fehlings reagent

C
$$H NO_{3}$$

D
All the above

Solution

D
Question 9
1 / -0

On vigorous oxidation by permanganate solution $$(CH_{3})_{2}C=CH-CH_{2}CHO$$ gives :

A
$$(CH_{3})_{2}CO$$ and $$OHC-CH_{2}-CHO$$

B
$$(CH_3)_3COH$$ and $$HCHO$$

C
$$(CH_{3})_{2}CO$$ and $$OHC-CH_{2}-COOH$$

D
$$(CH_{3})_{2}CO$$ and $$CH_{2}(COOH)_{2}$$

Solution

On vigorous oxidation by permanganate solution $$(CH_3)_2C=CH-CH_2CHO$$ gives $$(CH_3)_2CO$$ and $$CH_2(COOH)_2$$.

The $$C=C$$ bond is cleared and oxidised to $$-COOH, -CHO$$ group is also oxidised to $$-COOH$$.

$$(CH_3)_2C=CH-CH_2CHO\xrightarrow[KMnO_4]{[O]} (CH_3)_2CO+COOH-CH_2-COOH$$

Due to vigorous oxidation the $$\pi$$ bond breaks and oxidation takes place forming ketone and acid.
Question 10
1 / -0

Assertion (A) : $$CH_{3}CN$$ on hydrolysis gives Acetic Acid
Reason (R) : Cyanides on hydrolysis liberates $$NH_{3}$$ gas

A
Both A and R ae true and R is the correct explanation of A

B
Both A and R are true and R is not

the correct explanation of A

C
A is true but R is false

D
A is false but R is true.

Solution

A
R is the correct explanation of A.