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Aldehydes Ketones and Carboxylic Acids Test - 49

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Aldehydes Ketones and Carboxylic Acids Test - 49
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Weekly Quiz Competition
  • Question 1
    1 / -0
    Which of the following reactions will give $$\displaystyle \alpha -$$ hydroxy acid as a product?
    Solution
    Treatment of acetaldehyde with sodium cyanide in presence of HCl gives acetaldhyde cyanohydrin.
    This is followed by hydrolysis of cyano group in presence of acid to form hydroxy acid as a product which is 2-hydroxy propanoic acid.
  • Question 2
    1 / -0
    In the given reaction, the product $$(B)$$ is :

    $$\displaystyle CH_{3}CHO\xrightarrow[\left ( ii \right )H_{2}O/H^{\oplus }/\Delta ]{\left ( i \right )NaCN/HCl}\left ( A \right )\xrightarrow[reagent]{Fenton}\left ( B \right )$$
    Solution
    Treatment of acetaldehyde with sodium cyanide in the presence of $$HCl$$ gives acetaldehyde cyanohydrin.

    This is followed by hydrolysis of cyano group in the presence of acid to form compound $$A$$, which is $$2$$-hydroxy propanoic acid.

    The hydroxyl group is then oxidized to carbonyl group with fenton reagent to obtain compound $$B$$, which is Pyruvic acid.

    Option C is correct.

  • Question 3
    1 / -0
    What will be the product of the following reaction :
     (according to OPTIONS in the image shown)

    Solution
    Aniline acts as a nucleophile and attacks the two carbonyl carbons in stepwise manner to form a five member ring.
    This is followed by loss of two molecules of water to give the end product.
  • Question 4
    1 / -0
    In the given reaction,
    $$ CH_3COCH_3 \xrightarrow{CH_3C\equiv \overset{\Theta}{C}\overset{\oplus }{Na}} X \xrightarrow[]{H_2O} Y\xrightarrow[]{H_2-Pd/CaCO_3}Z\xrightarrow[]{Al_2O_3} $$ W, W is:
    Solution
    First step is the nucleophilic addition of sodium prop-2-yn-1-ide to carbonyl carbon of acetone to give compound X. This is followed by protonation to give compound Y. Hydrogenation with Lindlar's catalyst reduces triple bond to double bond to give compound Y. This is followed by dehydration in the presence of alumina to give compound W.
    Hence, compound D is represented by option C.
    $$CH_3COCH_3 \xrightarrow{CH_3C\equiv \overset{\Theta}{C}\overset{\oplus }{Na}} \underset {X} {CH_3C \equiv C-C(CH_3)_2-O^-} \xrightarrow[]{H_2O} \underset {Y} {CH_3C \equiv C-C(CH_3)_2-OH}$$
    $$\xrightarrow[]{H_2-Pd/CaCO_3}\underset {Z} {CH_3CH=CH-C(CH_3)_2-OH} \xrightarrow[]{Al_2O_3} \underset {W} {CH_3CH=CH-C(CH_3)=CH_2}$$
  • Question 5
    1 / -0
    The IUPAC name of the compound given below is:
    $$ CH_{3}CH_{2}CO CH_{2} CH_{3}$$
  • Question 6
    1 / -0
    Compound 'P' of the following reaction sequence can be :

    Solution
    The compound $$P$$ is acetylene benzene as it forms $$C_8H_6O_3$$ on ozonolysis. Hence, the formula of the compound should be $$C_8H_6$$.  
  • Question 7
    1 / -0
    Which of the following compound cannot have the condensed formula $$C_5H_{10}O$$?
    Solution

  • Question 8
    1 / -0
    IUPAC name of the following compound is:

    Solution
    The IUPAC name of the above compound is 5-Ethyl- hexane-1, 3, 6-tricarboxylic acid.

    The parent compound contains 6 C atoms and is named hexane. Three carboxylic groups $$\displaystyle (-COOH)$$ are present as a substituent and named as suffix tricarboxylic acid.

    An ethyl group is present as a substituent on the fifth C atom.

  • Question 9
    1 / -0
    Which of the following compound would be appropriate for the synthesis of amino acid (2)?

    Solution
     

  • Question 10
    1 / -0

    What is the final product of the above reaction sequence?

    Solution
    $$S_N2$$ reaction at $$sp^3$$ carbon followed by hydrolysis of cyano group as

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