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Aldehydes Keton...

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  • Question 1
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    Directions For Questions

    $$\underset {(A)}{(C_9H_{12}O)} \xrightarrow[Hot\ KMnO_4]{[O]} PhCOOH$$

    (i) (A) does not decolourise $$Br_2$$ in $$CCl_4$$; reacts with Na to give a colourless and odourless gas (B).
    (ii)     (A) does not give iodoform test.
    (iii) (A) is a chiral compound and oxidation of (A) with $$CrO_3 / Pyridine$$ gives a chiral compound (C).
    (iv)     The colour of $$Cr_2O_7^{2-}$$ changes from orange to blue-green when added to compound (A).

    ...view full instructions

    The colour of $$Cr_2O_7^{2-}$$ changes from orange to blue-green when added to compound (A). The blue-green colour is due to the formation of :

  • Question 2
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    Identify the functional group in Product B?

  • Question 3
    1 / -0

    Directions For Questions

    $$\underset {(A)}{(C_9H_{12}O)} \xrightarrow[Hot\ KMnO_4]{[O]} PhCOOH$$

    (i) (A) does not decolourise $$Br_2$$ in $$CCl_4$$; reacts with Na to give a colourless and odourless gas (B).
    (ii)     (A) does not give iodoform test.
    (iii) (A) is a chiral compound and oxidation of (A) with $$CrO_3 / Pyridine$$ gives a chiral compound (C).
    (iv)     The colour of $$Cr_2O_7^{2-}$$ changes from orange to blue-green when added to compound (A).

    ...view full instructions

    The colourless and odourless gas (B) is:

  • Question 4
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    Which of the following on oxidation with alkaline $$KMnO_4$$ followed by acidification with dil. $$HCl$$ gives terephthalic acid?

  • Question 5
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    In the following sequence of reactions, products (A) to (H) are formed. Then the Compound (D) is :

  • Question 6
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    In the following sequence of reactions, products (A) to (H) are formed. Then the Compound (B) is :

  • Question 7
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    In the following sequence of reactions, products (A) to (H) are formed. Then the Compound (F) is :

  • Question 8
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    Select the correct group(s) of reagent(s) used in the following conversions:

  • Question 9
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    Reagent (A) is :

  • Question 10
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    In the following sequence of reactions, products (A) to (H) are formed. Then the Compound (C) is :

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