Aldehydes Ketones and Carboxylic Acids Test

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Aldehydes Ketones and Carboxylic Acids Test - 54

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Weekly Quiz Competition

Question 1
1 / -0

Cyanogen $$(CN)_2$$ on hydrolysis yields:

A
malonic acid

B
maleic acid

C
formic acid

D
oxalic acid

Solution

Cyanogen $$(CN)_2$$ on hydrolysis yields oxalic acid.
Question 2
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Which of the following cyanohydrins on hydrolysis give an optically active acid giving iodoform reaction?

A
Acetone cyanohydrin

B
Propionaldehyde cyanohydrin

C
Acetaldehyde cyanohydrin

D
Formaldehyde cyanohydrin

Solution

Acetaldehyde cyanohydrin on hydrolysis give an optically active acid giving iodoform reaction.

This acid can be easily oxidized to contain $$CH_3CO$$ group which is required for positive iodoform test.

Option C is correct.
Question 3
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In the reaction $$\text{X}$$ is:

A
$$CH_3CH_2COOH$$

B
$$CH_3COOH$$

C
$$CH_3CH_2CHO$$

D
$$CH_3CH_2OH$$

Solution
Question 4
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A carbonyl compound '$$A$$' reacts with hydrogen cyanide to form a cyanohydrin '$$B$$' which on hydrolysis gives an optically active alpha-hydroxy acid '$$C$$'. '$$C$$' also gives a positive iodoform test.
'$$A$$', '$$B$$' and '$$C$$' is given by the set:-

A
$$HCHO$$;

B
$$CH_{3}CHO$$;

C
$$CH_{3}CH_{2}CHO$$

D
Question 5
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Write the $$IUPAC$$ names of the following ketones and aldehydes. Wherever possible, give also common names.

A
$$CH_3CO(CH_2)_4CH_3$$

B
$$CH_3CH_2CHBrCH_2CH(CH_3)CHO$$

C
$$CH_3(CH_2)_5CHO$$

D
$$Ph-CH=CH-CHO$$

Solution

(i) IUPAC Name: Heptan-2-one
Common Name:Methyl n-pentyl ketone

(ii) IUPAC Name:4-Bromo-2-methylhexanal
Common Name:$$\gamma$$ -bromo-$$\alpha$$ methylhexanal

(iii) IUPAC Name: Heptanal

(iv) IUPAC Name: 3-Phenylprop-2-enal

(v) IUPAC Name: Cyclopentacarbaldehyde

(vi)IUPAC Name: Diphenyl methanone
Common Name: Benzophenone
Question 6
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R and S are:

A
I only

B
I and II

C
III only

D
None of these

E
Blank

Solution

Benzene undergo Friedal crafts acylation reaction to produce acetophenune, it form $$1$$- phenyl, $$1-, 3$$- butanedione. After halogenation reaction it produce iodoform and sodium containing salt.
Question 7
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Directions For Questions

An organic compound $$(A)\;C_3H_6Cl_2$$ on reduction with red $$P\;and\;Hl$$ gives propane. $$(A)$$ on hydrolysis by an alkali followed by oxidation gives $$(B)\;C_3H_4O_4$$, which on heating gives $$(C)$$. Both $$(B)\;and\;(C)$$ give effervescence with $$NaHCO_3$$. $$(B)$$ on reacting with ethyl alcohol gives $$(D)\;C_7H_{12}O_4$$, a well known synthetic reagent.
Answer the following questions:

...view full instructions

Compound $$(C)\;\xrightarrow{P_4O_{10}}\;Product\;(F)$$

The product $$F$$ may be:

A
Malonic anhydride

B
Ethanoic anhydride

C
Ethanal

D
A lactone

Solution
Question 8
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In the given reaction, $$A$$ also reacts with $$NaOI$$ followed by the reaction with $$H^+$$ to give $$3,\,4-$$dilhydroxybenzoic acid. Which of the following is correct?

A

B
$$'C'$$ is optically active which is derived from $$A$$

C
No other side product is formed along with $$'A'$$

D

Solution

It can be seen that compound $$C$$ has a chiral carbon. Hence, C is a optically active compound.
Question 9
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Directions For Questions

An organic compound $$(A)\;C_3H_6Cl_2$$ on reduction with red $$P\;and\;Hl$$ gives propane. $$(A)$$ on hydrolysis by an alkali followed by oxidation gives $$(B)\;C_3H_4O_4$$, which on heating gives $$(C)$$. Both $$(B)\;and\;(C)$$ give effervescence with $$NaHCO_3$$. $$(B)$$ on reacting with ethyl alcohol gives $$(D)\;C_7H_{12}O_4$$, a well known synthetic reagent.
Answer the following questions:

...view full instructions

$$(D)+Benzaldehyde\;\xrightarrow[(ii)\;H_2O^+]{(i)\;Pyridine,\;\Delta}\;Major\;Product\,(E)$$
The major product $$(E)$$ is

A
Crotomic acid

B
Cinnamic acid

C
Benzoic acid

D
Mandelic acid

Solution

The organic compound (A) is 1,3-dichloropropane. On reduction with red $$P$$ and $$Hl$$, it gives propane.

(A) on hydrolysis by an alkali followed by oxidation gives malonic acid (B). The $$-Cl$$ groups of 1,3-dichloropropane are replaced with $$-OH$$ groups to give propylene glycol. Primary alcoholic groups are then oxidized to carboxylic groups to give malonic acid. Malonic acid on heating gives acetic acid (C) by thermal decarboxylation of beta keto acid.

Both (B) and (C) give effervescence with $$NaHCO_3$$. This indicates presence of $$-COOH$$ groups.

Malonic acid (B) on reacting with ethyl alcohol gives diethyl malonate (D) which is a well known synthetic agent. The next step is the condensation between benzaldehyde and diethyl malonate (D). A molecule of water is lost during condensation. In the next step, the ester groups are hydrolyzed. The final step is the thermal decarboxylation of beta keto acid to form cinnamic acid (E).
Question 10
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Which of the following acids does not contain $$-COOH$$ group?

A
Carbamic acid

B
Barbituric acid

C
Lactic acid

D
Succinic acid

Solution

(a) Carbamic acid: $$HOOC - NH_{2}$$

(b) Barbituric acid: $$C_{4}H_{4}N_{2}O_{3}$$

(c) Lactic acid: $$CH_{3}CH(OH)COOH$$

(d) Succinic acid: $$HOOC - CH_{2} - CH_{2} - COOH$$

Therefore, barbituric acid is actually not an acid.