Aldehydes Ketones and Carboxylic Acids Test

Result

Aldehydes Ketones and Carboxylic Acids Test - 60

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Weekly Quiz Competition

Question 1
1 / -0

Complete the reactions with appropriate products.
(i) $$CH_3CHO+NH_2OH \rightarrow X$$
(ii) $$CH_2=CH_2+PdCl_2+H_2O \xrightarrow{CuCl_2}Y $$
(iii) $$CH_3CH_2CH_2CH_2OH \xrightarrow{CrO_3-H_2SO_4}Z $$

A
$$X = CH_3CH=NOH, \,\, Y = CH_3CHO, \,\, Z = CH_3CH_2CH_2COOH$$

B
$$X = CH_3CH_2NH_2, \,\, Y= CH_3CH_2CHO, \,\, Z = CH_3CH_2CH_2COOH$$

C
$$X = CH_3CONH_2, \,\, Y= HCHO, \,\, Z= CH_3COCH_3$$

D
$$X = CH_3C\equiv N, \,\, Y = CH_3CHO,\,\, Z = HCOOH$$

Solution

When butanol undergo reaction with $$CrO_3 - H_2SO_4$$ in presence of sulphuric acid, it poroduce batanoic acid.
Hence, the products are
$$X \rightarrow CH_3 = NOH$$
$$Y \rightarrow CH_3 - CHO$$
$$Z \rightarrow$$ $$CH_3 CH_2 CH_2 COOH$$
Question 2
1 / -0

Consider the following sequence of reactions. The final product (B) is?

A

B

C

D

Solution

In the above reacation $$HIO_4$$ cleanes 1,2 diole into two carbonyl compounds . i,e the reaction is selective for 1 ,2 diole. this reaction occurs via the formation of a cyclic periodic ester. It can be used as a functional group test for 1,2 diole also the products are determined by the substituent on the diole.
Question 3
1 / -0

The product of acid hydrolysis of [P] and [Q] can be distinguished by:

A
Lucas reagent

B
2,4-DNP

C
Fehling's solution

D
$$NaHSO_{3}$$
Question 4
1 / -0

Product (x) in this reaction is:

A

B

C

D
Question 5
1 / -0

Above compound is hydrated maximum at which position?

A
$$1$$

B
$$2$$

C
$$3$$

D
equal
Solution
Correct Option: $$B$$

Explanation
- Hydration reaction refers to the addition of $$H_2O$$ molecule to a compound.
- A hydration reaction is a nucleophilic addition reaction.
- It is initiated by the addition of nucleophile $$OH^-$$ on a positive center.
- Carbonyl groups are stable bonds but have very good nucleophile centers.
- More is the positive polarity on the carbonyl carbon, easier is it for the nucleophile to attack.
- The three carbonyl groups here are all $$sp^2$$ hybridized and thus in resonance.
- Therefore, the two carbonyl groups ($$1$$ and $$3$$) act as $$-R$$ as well as $$-I$$ groups, both of which are electron-accepting groups.
- Thus, the most positive polarity is on $$2$$ carbonyl group.
Hence, the above compound is hydrated maximum at $$2$$ position
Question 6
1 / -0

Product $$(D)$$ in above reaction is:

A

B

C

D

Solution

PCC oxidises alcohols to aldehydes and ketones. Aldehydes are more reactive to form acetals.
(Refer to Image)
Acetals convert to aldehydes in presence of acidic medium.
Question 7
1 / -0

Which of the following has lowest $$pK_a$$ value?

A

B

C

D

Solution
Question 8
1 / -0

Given the major organic product of the following reaction.

A

B

C

D

Solution

Sodium acetylide is a nucleophilic which attacks on electrophilic carbons like carbonyl carbons.
Sodium acetylide $$\Rightarrow Na^+C^{\circleddash}\equiv C^{\circleddash}Na^+$$
So, (Refer to Image)
Question 9
1 / -0

The compound $$(C)$$ is:

A

B

C

D

Solution

(Refer to Image)
The presence of $$SOCl_2, SN_1$$ takes place in which retention of configuration occur. On addition of $$KCN$$ again $$SN_2$$ takes place. Then in presence of acid, hydrolysis of $$CN$$ takes place and convert it into acid.
Question 10
1 / -0

The IUPAC name of the compound is:

A
$$2-ethyl-3-methylcyclohexa-1, 3-diene$$

B
$$2, 5-dimethylhepta-2, 6-dienoic$$ acid

C
$$3-bromo-2-methylbutanoic$$ acid

D
$$3-bromo-2, 3 dimethylbutanoic$$ acid

Solution