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Amines Test - 32

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Amines Test - 32
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  • Question 1
    1 / -0
    Which of the following diazonium salt is relatively stable at $$0-{ 5^0 }^{ }C$$?
    Solution
    The $$+I$$ effect which stabilizes the $${ N }^{ + }$$ion is in the following order $${ C }_{ 6 }{ H }_{ 5 }-<{ CH }_{ 3 }-<{ \left( { CH }_{ 3 } \right)  }_{ 2 }-<{ \left( { CH }_{ 3 } \right)  }_{ 3 }$$
    $$\therefore $$ The $${ \left\{ { \left( { CH }_{ 3 } \right)  }_{ 3 }C-N\equiv N \right\}  }^{ + }{ Cl }^{ - }$$ is most stable
  • Question 2
    1 / -0
    Select the basic strength order of following molecules.

    Solution
    Since in (III) lone pair is only involved in delocalisation, in (II) nitrogen is attached to the carbonyl (withdrawing group) and one alkyne group (donating group+I effect) which have the more basic character them the (I) in which (N) is attached to the two group i.e benzene and carbonyl.
  • Question 3
    1 / -0
    Which of the following conditions is most suitable for the above reaction?

    Solution
    In this reaction, primary aromatic amine is treated with nitrous acid ($${ HNO }_{ 2 }$$). $${ HNO }_{ 2 }$$ can be obtained by dissolving solid $${ NaNO }_{ 2 }$$ in aqueous acidic solution.
  • Question 4
    1 / -0
    $$H-COOH > Ph-COOH > CH_{3}-COOH$$ (acidic nature)$$CF_{3}-COOH > CCI_{3}-COOH > CH_{2}-COOH$$ (Acidic nature)$$N- methylmethanamine > methanamine > N, N- dimethylmethanamine $$ (Basic nature in aqueous phase)$$N,N- diethlethanamine > N-ethylethanamine > Ethanamine $$ (Basic nature in aqueous phase)Then the correct order is:
    Solution
    In aqueous phase, the basicity of amines depends upon:
    $$(i)$$ Inductive effect: which fovours tertiary amine to be more basic due to greater $$+I$$ effect of $$3$$alkyl group directly attached to nitrogen.
    $$(ii)$$ Solution Effect: Which favours primary amine to be more basic due to greater solution of its cation.
    $$(iii)$$ Steric Factor: Which cause tertiary amine to be less basic due to steric hinderance .
  • Question 5
    1 / -0
    Decreasing order of basicity of the three isomers of nitro aniline is:
    Solution
    Nitro group is an electron-withdrawing group. It mainly withdraws electrons from the ortho and para positions. Therefore para isomer is less basic than meta isomer.

    Ortho substituted anilines are generally weaker bases than aniline irrespective of the electron releasing or electron-withdrawing nature of the substituent.

    Hence decreasing order of basicity of the isomers of nitroaniline:
    $$m-nitroaniline>p-nitroaniline>o-nitroaniline$$
  • Question 6
    1 / -0
    The order of basic strength of the given basic nitrogen atoms is :

    Solution
    Since $$(II)$$ is more basic then $$(III)$$ due $$(II)$$ nitrogen get negative charge due resonance hence it is more basic.
    There for correct order is $$II$$>$$III$$>$$I$$>$$IV$$
    D)
  • Question 7
    1 / -0
    What is the major organic product of the following reaction?
    $$ { CH }_{ 3 }{ CH }_{ 2 }{ NHCH }_{ 2 }{ CH }_{ 3 }\longrightarrow $$?

    Solution

  • Question 8
    1 / -0
    The correct sequence regarding base strength of aliphatic amines in aqueous solution is:
    Solution
    Since the bascities of amine depend upon the no of alkyl group  directly attached to the nitrogen directly due to $$+I$$ effect to alkyl group increased the bascities of amine.
  • Question 9
    1 / -0
    Which of the following will accept $$H^{+}$$ from $$NH_{4}^{+}$$ ion?
    Solution
    Since the aromatic amines (aniline) are less basic than aliphatic amines.
    Because lone pair of nitrogen in aromatic amines are involved in resonance.
  • Question 10
    1 / -0
    Which of the following Statements is/are correct?
    Solution
    $$A.$$ $${(SiH_3)}_3N$$ is a weaker base than $${(CH_3)}_3N$$.
    In $${(CH_3)}_3N$$ the lone pair is concentrated on the $$N-atom$$. But in case of Trisillyl amine, the lone pair on nitrogen gets delocalised on the $$3$$ silicon atoms bonded to it.
    Since, base strength is a measure of tendency to donate lone pair, trimethylamine is stranger base.

    $$D.$$ In ethers there is no intermolecular hydrogen bond, where as in alcohol, intermolecular hydrogen bond is present which makes them less volatile and have high boiling point.
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