Amines Test

Result

Amines Test - 36

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Weekly Quiz Competition

Question 1
1 / -0

Which of the following is the strongest base?

A

B

C

D

Solution

Aniline is the strongest base here. This is because, $$NH_2$$ is stabilized by conjugation and resonance stabilised . More stability implies stronger the base.
Question 2
1 / -0

which compound is Prepare propan -I- amine from?

A
Butaniteuie

B
I-Nitropropane

C
Propanamide

D
Butanamide

Solution

Propan-1-amine can be prepared by propanamide by treating it with an acid anhydride and then reducing the nitrile compound formed with the help of Lithium Aluminum Anhydride.
Question 3
1 / -0

Adrenaline and ephedrine contain:

A
$${1}^{o}$$ amino group

B
$${2}^{o}$$ amino group

C
$${3}^{o}$$ amino group

D
quaternary amino group

Solution

Thus Adrenaline and ephedrine contain $$2^0$$ amino group.
Question 4
1 / -0

Which of the following is most basic?

A

B

C

D

Solution

Basicity is enhanced by the presence of electron donating group & availability of a lone pair of electrons on the nitrogen atom. Hence is most basic.
Question 5
1 / -0

Which of the following is weak base than aniline ?

A

B

C

D

Solution

An electron withdrawing groups decrease the availability of a lone pair of electrons on $$N-$$atom of aniline thereby decreasing its basicity.
Hence it is less basic than aniline.
Question 6
1 / -0

Sanger's reagent is used for the identification of:

A
N-thermal of peptide chain

B
C-terminal of a peptide chain

C
side chain of amino acids

D
number of amino acids in peptide chain

Solution

1-Fluoro-2,4-dinitrobenzene. Undergoes nucleophilic aromatic substitution (NAS) with the N-terminal amino group of a peptide or protein, resulting in a chemical tag on the terminal amino acid residue. After hydrolysis into individual amino acids, the peptide's or protein's terminal amino acid can be identified by the specific wavelength of light absorbed (i.e., colorimetric analysis).
So option $$A$$ is correct
Question 7
1 / -0

Among the following which is not correct?

A
P methyl benzyl carbonyl is more stable than ethyl benzyl carbonyl

B
Aniline is more basic than pyridine

C
Cyclopentadienyl anion is more stable than cyclopentadienyl Carbo cation

D
K of Ethene 1 ol is more than that of propene 2 en 1 ol
Question 8
1 / -0

$${C}_{6}{H}_{5}-{NO}_{2}\xrightarrow [ ]{ Fe/HCl } A\xrightarrow [ H{ NO }_{ 3 } ]{ 273K } B\xrightarrow [ ]{ { C }_{ 6 }{ H }_{ 5 }OH } C$$, $$C$$ is

A

B

C

D

Solution
Question 9
1 / -0

In an amino acid, the carboxyl group ionises at $$p{K}_{{a}_{1}}=2.34$$ and ammonium ion at $$p{K}_{{a}_{2}}=9.60$$. The isoelectric point of the amino acid is at $$pH$$:

A
$$5.97$$

B
$$2.34$$

C
$$9.60$$

D
$$6.97$$

Solution

The isoelectronic point or isoionic point is the pH at which the amino acid does not migrate in an electric field.
This means it is the pH at which the amino acid is neutral, i.e. the zwitter ion form is dominant.
the isoelectronic point is halfway between the two given values, i.e.,
$$pH=\cfrac{pK_{a_{1}}+pK_{a_{2}}}{2}=\cfrac{2.34+9.60}{2}=5.97$$
Question 10
1 / -0

Acid anhydride on reaction with primary amine give:

A
Amide

B
Imide

C
Secondary amine

D
Imine

Solution

Acid anhydrides react with primary and secondary amines to form amides.
See the given figure.
Option $$A$$ is the answer.