Amines Test

Result

Amines Test - 37

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Weekly Quiz Competition

Question 1
1 / -0

What will be the final product of the given reaction?

A

B

C

D

Solution

Diazonium chloride on treating with $$HF/{ BF }_{ 3 }$$ yields benzene diazonium fluoroborate. Benzene diazonium fluoroborate when heated undergoes decomposition reaction to give fluorobenzene.
Option B is correct.
Question 2
1 / -0

The structural feature which distinguishes proline from other natural $$\alpha$$-amino acids is that:

A
it is optically inactive

B
it contains aromatic group

C
it contains two amino groups

D
it is secondary amine

Solution

Structure of proline contains a secondary amine group.
Proline is the only amino acid that contains a secondary amine group.
Question 3
1 / -0

The reaction :[$${ C }_{ 2 }{ H }_{ 5 }{ B }r+{ N }{ H }_{ 3 }$$] is in fact an example of

A
Ammonolysis only

B
Nucleophilic substitution only

C
Ammonolysis as well as nucleophilic substitution

D
None
Question 4
1 / -0

Which of the following is the strongest base?

A

B

C

D
Question 5
1 / -0

The increasing order of basicity of the following compound is:

A

B

C

D

Solution

Due to resonance electron density increases at $$sp^2$$ hybridisation $$NH$$ electron density increase basically increase so this is most basic these are called as anidine here an $$sp^3$$ hybridisation $$NH_2$$ group is in resonance with $$sp^2$$ hybridised $$NH$$
Question 6
1 / -0

Gabriel phthalimide synthesisis used in the preparation of:

A
1$$^{o}$$ amine

B
2$$^{o}$$ amine

C
3$$^{o}$$ amine

D
4$$^{o}$$ amine

Solution

The chemical reaction used for transforming primary alkyl halides into primary amines is called Gabriel phthalimide synthesis. It uses potassium phthalimide. Therefore, Gabriel phthalimide synthesis is used in the preparation of $$1^o$$ amide.
Question 7
1 / -0

The increasing order of basicity of the following compounds is:

A
$$(d)<(b)<(a)<(c)$$

B
$$(a)<(b)<(c)<(d)$$

C
$$(b)<(a)<(c)<(d)$$

D
$$(b)<(a)<(d)<(c)$$

Solution
Question 8
1 / -0

Nitrobenzene when reduced with tin and hydrochloric acid, i.e., in acidic medium, the product formes is:

A
Aniline

B
Benzene

C
Both a and b

D
None of these

Solution

Nitrobenzene is reduced to phenylammonium ions using a mixture of tin and concentrated hydrochloric acid. The mixture is heated under reflux in a boiling water bath for about half an hour.
Under the acidic conditions, rather than getting phenylamine directly, you instead get phenylammonium ions formed.
Question 9
1 / -0

Isopropylamine $$\xrightarrow{KMnO_4} X \xrightarrow{H_3O^+}Y$$.

In the above sequence, $$X$$ and $$Y$$ are _________, ____________ respectively

A
Aceraldimine, Ethanal

B
Ethanal, Ketimine

C
Ketimine, Acetone

D
Acetone, Propan-2-ol

Solution

Isopropylamine on treatment with KMnO$$_4$$ produce ketimine first which gets hydrolysed to give acetone as the final product.

Hence, the correct option is $$\text{C}$$
Question 10
1 / -0

Benzyl amine is............. basis than aniline while ethyl amine is..............basis than diethyl amine

A
More, less

B
Less, more

C
Both

D
None

Solution

Benzyl amine is $$more$$ basic than anniline
while ethyl amine is $$less$$ basic than diethyl amine