Amines Test

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Amines Test - 39

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Weekly Quiz Competition

Question 1
1 / -0

Which of the following amines cannot be prepared by Gabriel Phthalimide reaction?

A

B

C

D
$$CH_3-\underset{NH_2}{\underset{|\,\,\,\,\,\,\,}{NH_2}}-CH_3$$

Solution

Gabriel phthalimide reaction is used for the conversion of primary alkyl halides into primary amines. Among the given compounds, A, B and D are primary amines (products of Gabriel phthalimide reaction). While C is a secondary amine (cannot be synthesised by this reaction).
Question 2
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Which product can not be formed in given reaction?

A

B

C

D

Solution

This is Diazotization reaction.
Here substitution and elimination, both can happen but OH- ion is not present as to attack onto the carbocation. Thus, product in the option A is not at all feasible.
Question 3
1 / -0

Which of the following is obtained by reducing methyl cyanide with $$Na+ C_2H_5OH$$?

A
Methyl alcohol

B
Acetic acid

C
Ethyl amine

D
Methane

Solution

Sodium in alcohol is a strong reducing agent and reduces nitriles to amines.
$$CH_3-CN+Na+C_2H_5OH\rightarrow C_2H_5-NH_2$$
This reaction is also known as Mendius Reduction.
Question 4
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Factors responsible for base strength comparison of amines in aqueous solution ?

A
Availability of lone pair on nitrogen

B
Lone pair donating power of nitrogen

C
Stability of conjugate acid formed by solvation through H-bonding.

D
All of the above

Solution

The basicity of amines depend upon its ability to donate the lone pair of electrons on nitrogen.
Order of basicity of amines in aqueous solution is,
$$NH_3<Primary \ amines(RNH_2)<Tertiary \ amines(R_3N)<Secondary \ amines(R_2NH)$$
This is due to the combined effect of +I effect of alkyl group, steric hindrance caused by alkyl groups and solvation of amines through H-bonding.
The power to donate lone pair of electrons increases as the number of alkyl groups increase. Therefore, making $$R_3N$$ most basic, followed by $$R_2NH$$ and $$RNH_2$$.
But as the number of alkyl groups increase, the steric hindrance caused by them also increases. Thus, decreasing the electron donating power of amines. Hence, making $$RNH_2$$ most basic followed by $$R_2NH$$ and $$R_3N$$.
Solvation is the formation of protonated amines when they are dissolved in water. As the number of H-atoms on nitrogen increases the possibility of H-bonding also increases, providing greater stability to the amine. Thus, primary amine $$(RNH_2)$$ is more stable than secondary amine $$(R_2NH)$$, which is more stable than tertiary amine $$(R_3N)$$.
The combined effect of these three factors give the observed order of basicity of amines in aqueous solution.
Question 5
1 / -0

Which of the following is an Incorrect statement about benzenediazonium chloride?

A
It is prepared by the reaction of aniline with nitrous acid at 273-278 K

B
It is a colourless crystalline solid

C
Alkyl diazonium salts are more stable than arenediazonium salts

D
Benzene diazonium fluoroborate is water insoluble & stable at room temperature
Question 6
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$$CH_3NH_2+CHCl_3+KOH \rightarrow$$ Nitrogen containing compound +$$KCl +H_2O$$. Nitrogen containing compound is:

A
$$CH_3CN$$

B
$$CH_3NHCH_3$$

C
$$CH_3-\bar{N}\equiv\overset{+}{C}$$

D
$$CH_3-\overset{+}{{N}}\equiv {C}:^-$$

Solution

The reaction of primary amine ($$R-NH_2$$) with chloroform $$(CHCl_3)$$ and a base $$(KOH)$$ is known as carbylamine reaction. The reaction yields isocyanide as the product, along with salt and water.
$$CH_3NH_2+CHCl_3+KOH\rightarrow CH_3N^+\overline{=}C^-+KCl+H_2O$$
Question 7
1 / -0

When $$CH_{3}CH_{2}CHCl_{2}$$ is treated with $$NaNH_{2}$$ the product formed is:

A
$$CH_{3}-CH=CH_{2}$$

B
$$CH_{3}-C\equiv CH$$

C

D

Solution

Solution:- (B) $$C{H}_{3}-C \equiv CH$$
When $$C{H}_{3}-C{H}_{2}-CH-{Cl}_{2}$$ is treated with $$NaN{H}_{2}$$, the product formed is propyne.
$$C{H}_{3}-C{H}_{2}-CH-{Cl}_{2} \xrightarrow[\Delta]{NaN{H}_{2}} \underset{\left( \text{Propyne} \right)}{C{H}_{3}-C \equiv CH}$$
Question 8
1 / -0

Which of the following given compounds is the strongest base?

A

B

C

D
Question 9
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Most basic nitrogen among the following

A

B

C

D
Question 10
1 / -0

The product 'Y' in the following reaction sequence is:

A

B

C

D

Solution