Amines Test

Result

Amines Test - 40

Score
-
out of -
Rank
-
out of -

TIME Taken - -

SHARING IS CARING

If our Website helped you a little, then kindly spread our voice using Social Networks. Spread our word to your readers, friends, teachers, students & all those close ones who deserve to know what you know now.

Weekly Quiz Competition

Question 1
1 / -0

the increasing order of diazotisation of the following compound is?

A
$$(a)<(d)<(b)<(c)$$

B
$$(d)<(c)<(b)<(a)$$

C
$$(a)<(b)<(c)<(d)$$

D
$$(a)<(d)<(c)<(b)$$

Solution

SOLUTION:
Electron withdrawing substituents decrease electron density on the benzene ring. Electron donating substituents increase electron density on the benzene ring. They increase the stability of diazonium salts.
Aromatic diazonium salts are more stable than aliphatic diazonium salts. The stability of aryl diazonium salts is due to resonance. Electron donating substituents increase electron density on the benzene ring. They increase the stability of diazonium salts.
Electron withdrawing substituents decrease electron density on the benzene ring. They decrease the stability of diazonium salts.($$-O-COCH_3$$) group is electron-withdrawing and hence, (d) is less stable than (b).
Although $$-O-COCH_3$$ is an electron-donating substituent, but it is present in the meta position. Hence, it will not have a significant effect on stability.
hence the correct option: A
Question 2
1 / -0

The most nucleophilic nitrogen is in :

A

B

C

D
Question 3
1 / -0

Arrange the following nitrogen containing compounds is decreasing order of basicity.

A
$$X > Y > Z$$

B
$$Y > X > Z$$

C
$$Z > X > Y$$

D
$$X > Z > Y$$

Solution
Question 4
1 / -0

The most basic $$N-$$atom is:

A
$$a$$

B
$$b$$

C
$$c$$

D
$$d$$

Solution

Here the most basic nitrogen atom is $$\underset{(c)}{-NH}$$. This is because here nitrogen is attached to the aliphatic carbon atom.
The nitrogen in $$\underset{(b)}{-NH_2}$$ is in conjugation with aromatic ring thus it does not have enough electron to act as a Lewis base.
Similarly, In nitrogen, $$a$$ and $$d$$ the nitrogen is present in the ring thus there is not enough electron available for donation.
Question 5
1 / -0

Which of the following is most basic in nature?

A

B

C

D
Question 6
1 / -0

Image

A

B

C

D

Solution
Question 7
1 / -0

The increasing order of reactivity of the following compounds towards reaction with alkyl halides directly is:

A
$$(B) < (A) < (D) < (C)$$

B
$$(B) < (A) < (C) < (D)$$

C
$$(A) < (C) < (D) < (B)$$

D
$$(A) < (B) < (C) < (D)$$

Solution

Nucleophiles are the compound which have excess of electron and are electron donating group.
here compound D is most nucleophile.
Question 8
1 / -0

Which of the following is weakest base ?

A

B
$$CH_3-CH=NH$$

C

D

Solution
Question 9
1 / -0

Consider the following statements
(i) Out of two $$- NH_{2}$$ groups in semicarbazide only one is involved in formation of semicarbazones.
(ii) Cyclohexane froms cyanohydrin in good yield but $$2, 2, 6-trimethylcyclohexanone$$ does not.
(iii) The $$\alpha - hydrogens$$ in aldehydes and ketones are acidic.

A
i and iii

B
ii and iii

C
i and ii

D
i, ii and iii

Solution

(i) Out of two -NH2 groups in semicarbazide, one is a part of amide functional group. In this, the lone pair on nitrogen atom is involved in the resonance with carbonyl group. Hence, this -NH2 group cannot act as a nucleophile. Hence, it is not involved in the formation of semicarbazones.
(ii) In cyclohexanone, the carbonyl carbon is not hindered. Hence, the nucleophile CN^-ion can easily attack the carbonyl carbon. However in 2,2,6-trimethyl cyclohexanone, the carbonyl carbon is sterically hindered due to presence of methyl groups. Hence, the nucleophile CN^- ion cannot easily attack the carbonyl carbon.
(iii) This is because of simply the difference between the electronegativities of carbon and double bonded oxygen and as you know oxygen the second most electronegative element because of which partial positive and partial negative charges appears and carbon and oxygen respectively because of which dissociation of Alpha hydrogen becomes easier (as we know the acidic character is how easily a particular compound loses H ion). Thus, it show acidic character
Question 10
1 / -0

The major product of the following reaction is:

A

B

C

D

Solution