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Biomolecules Test - 15

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Biomolecules Test - 15
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  • Question 1
    1 / -0

    Carbohydrates are classified on the basis of their behaviour on hydrolysis and also as reducing or non-reducing sugar. Sucrose is a __________.

    (i) monosaccharide

    (ii) disaccharide

    (iii) reducing sugar

    (iv) non-reducing sugar

    Solution

    One of the common disaccharides is sucrose which on hydrolysis gives equimolar mixture of D-(+)- glucose and D-(-) fructose. These two monosaccharides are held together by a glycosidic linkage between Cl of α-glucose and C2 of β -fructose. Since the reducing groups of glucose and fructose are involved in glycosidic bond formation, sucrose is a non-reducing sugar.

     

  • Question 2
    1 / -0

    Proteins can be classified into two types on the basis of their molecular shape i.e., fibrous proteins and globular proteins. Examples of globular proteins are :

    (i) Insulin

    (ii) Keratin

    (iii) Albumin

    (iv) Myosin

    Solution

    Globular proteins: This structure results when the chains of polypeptides coil around to give a spherical shape. These are usually soluble in water. Insulin and albumins are the common examples of globular proteins.

     

  • Question 3
    1 / -0

    Which of the following carbohydrates are branched polymer of glucose?

    (i) Amylose

    (ii) Amylopectin

    (iii) Cellulose

    (iv) Glycogen

    Solution

    Amylopectin is insoluble in water and constitutes about 80-85% of starch. It is a branched chain polymer of –D-glucose units in which chain is formed by C1 − C4 glycosidic linkage whereas branching occurs by C1 − C6 glycosidic linkage.

    Glycogen: The carbohydrates are stored in animal body as glycogen. It is also known as animal starch because its structure is similar to amylopectin and is rather more highly branched.

     

  • Question 4
    1 / -0

    Match the vitamins given in Column I with the deficiency disease they cause given in Column II.

    Column I (Vitamins) Column II (Diseases)
    (i) Vitamin A (a) Pernicious anaemia
    (ii) Vitamin B1 (b) Increased blood clotting time
    (iii) Vitamin B12 (c) Xerophthalmia
    (iv) Vitamin C (d) Rickets
    (v) Vitamin D (e) Muscular weakness
    vi) Vitamin E (f) Night blindness
    (vii) Vitamin K (g) Beri Beri
    (h) Bleeding gums
    (i) Osteomalacia
    Solution

    (i) Xerophthalmia (hardening of cornea of eye) night blindness.

    (ii) Beri beri (loss of appetite, retarded growth).

    (iii) Pernicious anaemia (RBC deficient in haemoglobin).

    (iv) Scurvy (bleeding gums).

    (v) Rickets (bone deformities in children) and osteomalacia (soft bones and joint pain in adults)

    (vi) Increased fragility of RBCs and muscular weakness.

    (vii) Increased blood clotting time.

     

  • Question 5
    1 / -0

    Assertion : D (+) – Glucose is dextrorotatory in nature.

    Reason : ‘D’ represents its dextrorotatory nature.

    Solution

    Glucose is correctly named as D(+)- glucose. ‘D’ before the name of glucose represents the configuration whereas ‘(+)’ represents dextrorotatory nature of the molecule.

    The letters ‘D’ or ‘L’ before the name of any compound indicate the relative configuration of a particular stereoisomer.

     

  • Question 6
    1 / -0

    Assertion : Vitamin D can be stored in our body.

    Reason : Vitamin D is fat soluble vitamin.

    Solution

    Fat soluble vitamins are soluble in fat and oils but insoluble in water. They can be stored in liver and adipose (fat storing) tissues.

     

  • Question 7
    1 / -0

    Each polypeptide in a protein has aminoacids linked with each other in a specific sequence. This sequence of amino acids is said to be ____________.

    Solution

    Sequence of amino acids is said to be primary structure of proteins.

     

  • Question 8
    1 / -0

    DNA and RNA contain four bases each. Which of the following bases is not present in RNA?

    Solution

    DNA contains four bases viz. adenine (A), guanine (G), cytosine (C) and thymine (T). RNA also contains four bases; the first three bases are same as in DNA but the fourth one is uracil (U).

     

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