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Biomolecules Test - 36

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Biomolecules Test - 36
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Weekly Quiz Competition
  • Question 1
    1 / -0
    Which of the following is synthetic sweetener?
    Solution
    Saccharin, aspartame, dulcin all are synthetic sweetener. They have a sugar-like taste but with less food energy.
    Artificial sweeteners are used in one of two ways. They may be used directly in commercially processed foods, or they are mixed with one or more starch-based sweeteners before sale to consumers.

    $$\therefore$$ Option D is the correct answer.
  • Question 2
    1 / -0
    Starch undergoes hydrolysis in presence of mineral acids to form:
    Solution
    Starch undergoes hydrolysis in presence of mineral acids to form glucose.
    $$\underset{\begin{matrix}starch\, or\\cellulose\end{matrix}}{(C_6H_{12}O_5)_n} + nH_2O \xrightarrow[\begin{matrix} 393K\\2-3 \,bars\end{matrix}]{H^+} \underset{glu\,cose}{nC_6H_{12}O_6}$$
  • Question 3
    1 / -0
    Number of $$C=O$$ groups in thymine and X are equal. Now, X is
    Solution
    Number of $$C=O$$ groups in thymine is same as in uracil. Both contains 2 $$C=O$$ groups.

  • Question 4
    1 / -0
    If the amino group of glycine and carboxylic acid group of alanine undergo elimination of water molecule, the name of the compound thus formed is
    Solution
    If the amino group of glycine and carboxylic acid group of alanine undergo elimination of water molecule, the formed compound is glycylalanine (dipeptide).

  • Question 5
    1 / -0
    The functional group which is found in amino acid is
    Solution
    Option (D) is correct. The functional group which is found in amino acid are $$COOH$$ and $$NH_3$$ (amine group). So every amino acid has a central carbon with a $$H$$, $$R$$ group (varies for each amino acid), a carboxylic group and an amine group. These groups are joined to a single (aliphatic) carbon. The carbon directly attached to a carboxyl group is the alpha position, so the amino acids in proteins are all alpha-amino acids.
    $$H_2N - \underset{R}{\underset{|}{\overset{H}{\overset{|}{C}}}} - COOH$$
  • Question 6
    1 / -0
    Match the following
    Set ASet B
    1. Adeninea. $$C_5N_5H_5O$$
    2. Guanineb. $$C_4N_2H_4O_2$$
    3. Uracilc. $$C_5N_5H_5$$
    4. Thymined. $$C_5N_2H_6O_2$$
    Solution
    Option (D) is correct.
    (1) Adenine  has molecular formula of $$C_5N_5H_5$$.
    (2) Guanine has molecular formula of $$C_5N_5H_5O$$.
    (3) Uracil has molecular formula of $$C_4N_2H_4O_2$$.
    (4) Thymine has molecular formula of $$C_5N_2H_6O_2$$.
  • Question 7
    1 / -0
    Which of the following amino acids does not correspond to the general formula: $$R - CH(NH_{2}) - COOH$$?
    Solution
    Among the given amino acids, cysteine, arginine and glutamic acid correspond to the general formula $$R - CH(NH_2) - COOH$$.

    However, proline does not correspond to the general formula $$R - CH(NH_2) - COO$$, as N is a part of a ring.

    Option B is correct.

  • Question 8
    1 / -0
    Which of the following is not optically active?
    Solution
    Glycine is not optically active. 

    A optically active compound should have atleast one carbon atom attached to four different groups. 

    Glycine is not active because it has carbon atom attached to 2 hydrogen atoms, 1 amino group and 1 carboxylic group.

    Option A is correct.

  • Question 9
    1 / -0
    IUPAC name of glycine is:
    Solution

    IUPAC name of glycine is 2-Aminoethanoic acid.
    Its molecular formula is $$NH_2CH_2COOH$$.  

     Hence,Option C is the correct answer.
                                    
                           

  • Question 10
    1 / -0
    The most common reagent for qualitative and quantitative analysis of amino acids is:
    Solution
    The most common reagent for qualitative and quantitative analysis of amino acids is Millon's reagent. 

    Million's reagent is a solution that is usually made by dissolving mercury in concentrated nitric acid and diluting with water and that when heated with phenolic compounds gives a red coloration, for proteins (especially tyrosine amino acids).

    Option B is correct.

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