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Biomolecules Test - 63

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Biomolecules Test - 63
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Weekly Quiz Competition
  • Question 1
    1 / -0
    What is the nature of glucose-glucose linkage in starch that males its so susceptible to acid hydrolysis?
    Solution

  • Question 2
    1 / -0
    Which of the following is the monomer of cellulose?
    Solution
    Monomer of Cellulose is $$\beta - D- glucose$$.

  • Question 3
    1 / -0
    A polypeptide on complete hydrolysis gives three amino acids. How many sequences are possible for that polypeptide?
    Solution

  • Question 4
    1 / -0
    In fructose and glucose the possible optical isomers are:
    Solution
    Fructose contains three chiral carbon atom and glucose contain 4 chiral carbon atoms.
    The Number of possible Optical isomers for Fructose are $${2}^{3} = 8$$
    The Number of possible Optical isomers for Glucose are $${2}^{4} = 16$$
    8, 16 is the Answer
  • Question 5
    1 / -0
    A carbohydrate $$X$$ having molecular weight $$180g{mol}^{-1}$$ has one primary alcohol group and four secondary alcoholic groups. It reacts with acetic anhydride to form pentaacetate. The molecular weight of pentaacetate formed is:
    Solution
    X is Glucose.
    The Weight of Glucose Pentaacetate formed is 390

  • Question 6
    1 / -0
    Which of the following is not catalysed by a brush border enzyme?
    Solution
    Maltase, Lactase, and Nucleotidase are brush-border enzymes that catalyze the final catabolism of metabolites in the small intestine.

    So the correct option is C.
  • Question 7
    1 / -0
    The two forms of $$D-$$glycopyranose obtained from solution of $$D-$$glucose are known as 
    Solution

  • Question 8
    1 / -0
    A dextro-rotatory sugar present in fruits is
    Solution
    (A) is the correction option. Natural glucose obtained from fruits is a dextro-rotatory isomer. So, it is denoted as (+) Glucose.
  • Question 9
    1 / -0
    Number of $$HIO_4$$ molecule required to complete oxidation one mole of glucose is :
    Solution

  • Question 10
    1 / -0
    Jitesh carried out a steady-state kinetics experiment for an enzyme degradase with and without molecule X as pat of the reaction mixture. The reactions were carried out for $$5$$ minutes and he got the following results:
    Substrate Concentration (milliMolar)  Amount of product formed without X (milliMoles)Amount of product formed with X (milliMoles)
    0.10.40.2
    0.52.11.3
    1.04.32.7
    1.56.24.1
    2.08.15.4
    2.58.36.7
    3.08.48.1
    3.58.58.3
    Solution
    From the data given, it can be inferred that the presence of X considerably decreases the rate of formation of the product. This could be attributed to the fact that X is a competitive inhibitor of the product. Meaning that X competes for the same active site of the enzyme and does not let the substrate from binding to it.
    So, the correct answer is 'Molecule X is a competitive inhibitor'.
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