Biomolecules Test

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Biomolecules Test - 76

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Weekly Quiz Competition

Question 1
1 / -0

Which of the following is energy-giving nutrient?

A
Carbohydrates

B
Proteins

C
Vitamins

D
Minerals

Solution

Carbohydrates, especially glucose is the primary respiratory substrate to release energy in the form of ATP.
So, the correct answer is 'Carbohydrates'
Question 2
1 / -0

Which one of the following is not an attribute of enzymes?

A
They are specific in nature

B
They are used in chemical reactions

C
They are thermolabile in nature

D
They are proteinaceous in nature
Question 3
1 / -0

Reducing sugar can reduce:

A
Aldehydes to alcohols

B
Ferric salts to ferrous salts

C
Chlorates to chlorides

D
Fehling solution to cuprous oxide

Solution

A reducing sugar is any sugar that either has an aldehyde group or is capable of forming one in the solution, through isomerism.

The aldehyde functional group allows the sugar to act as a reducing agent, or example, in the Tollens' test or Benedict's reagent.

Fehling's solution is used to test for the presence of a reducing sugar. The reducing sugar reduces copper(II) ions in these test solutions to copper(I), which then forms a brick red copper(I) oxide precipitate.

An example is given in the attached image.

Option D is correct.
Question 4
1 / -0

Match the following:

Name of the sugar Hydrolysis products
A) Sucrose i) Glucose $$+$$ Fructose $$+$$ Galactose
B) Lactose ii) Glucose $$+$$ Fructose
C) Maltose iii) Glucose $$+$$ Galactose
D) Raffinose iv) Glucose $$+$$ Glucose

A
A- iii , B- ii, C- i, D- iv.

B
A- ii, B- iii, C- i, D- iv.

C
A- ii, B- iii ,C- iv, D- i.

D
A- ii, B- iv, C- iii, D- i.

Solution

(A) Sucrose is made up of glucose and fructose molecules. When sucrose is consumed, the enzyme separates sucrose into its individual sugar units of glucose and fructose.
(B) Lactose is a disaccharide, a type of sugar composed of two simple sugars, glucose and galactose.
(C) Maltose is made up of two molecules of glucose.
(D) Raffinose is a trisaccharide composed of galactose, glucose, and fructose.
$$\therefore$$ Option (C) is correct.
Question 5
1 / -0

Adenosine triphoshate (ATP) molecule is given above. Calculate value of $$n_{1}+n_{2}$$, where $$n_{1}$$ is the net negative charge in neutral medium and $$n_{2}$$ is number of chiral carbon atoms.

A
8

B
7

C
9

D
None of these

Solution

In neutral medium, each OH group is acidic and deprotonates, leaving a negative charge on oxygen. There are four such OH groups. The OH groups on the furan ring are not acidic as two negative charges are not stable on adjacent atoms, in space. Hence, $$n_1=4$$. ATP contains 4 chiral carbon atoms which are marked with asterisk. Hence, $$n_2=4$$. Thus, $$n_1+n_2=4+4=8$$.
Question 6
1 / -0

The shape of an enzyme, and consequntly its acitivity, can be reversibly altered from moment to moment by:

A
Amino acid substitutions

B
Sulphur substitutions

C
Allosteric subunits

D
High pH

Solution
Question 7
1 / -0

Match the following.
A. Homeostasis 1) Insulin
B. Emergency hormone 2) Structure of insulin
C. Metabolism 3) Adrenaline
D. Peptide hormones 4) Thyroxine
E. Pancreatic islets 5) Maintenance of constant internal environment
F. Sanger 6) Affect the properties of Plasma membrane

A
A - 1; B - 5; C - 3; D - 4; E - 6; F - 2

B
A - 2; B - 4; C - 3; D - 1; E - 6; F - 2

C
A - 3; B - 5; C - 3; D - 4; E - 6; F - 1

D
A - 5; B - 3; C - 4; D - 1,6; E - 1; F - 2

Solution

Homeostasis is the maintenance of constant internal environment.
Adrenaline is an emergency hormone. It increases pulse rate, blood pressure during emergency and stimulates the breaking of liver glycogen into blood glucose.
Thyroxine is useful in metabolism. Insulin is secreted from thyroid gland. It regulates general growth and development and controls carbohydrate, lipid and protein metabolism.
Peptide hormones such as insulin, affect the properties of plasma membrane.
Insulin is secreted in pancreatic islets. It controls carbohydrate metabolism and maintains glucose level in the blood.
Sanger represents the structure of insulin.
Question 8
1 / -0

Enzymes differ from inorganic catalysts in

A
not being used up in chemical reactions

B
working at high temperature

C
being proteinaceous in nature

D
working at high pH

Solution
Question 9
1 / -0

The reagent which may be used to distinguish between cane sugar and glucose solutions is:

A
$$I_{2}$$ solution

B
Baeyer's reagent

C
Both $$A$$ and $$B$$

D
Fehling's solution

Solution

Glucose is a reducing sugar while cane sugar is a non-reducing sugar.

Glucose does not have any glycosidic linkage, so, it can be reduced by Fehling's reagent. But cane sugar has a glycosidic linkage so, due to the absence of the free $$-CHO$$ group, it cannot be reduced.

So, Fehling's solution can be used to distinguish between these two.

The correct option is 'D'.
Question 10
1 / -0

Enzymes generally have:

A
Same pH and temperature optima

B
Same pH but different temperature optima

C
Different pH but same temperature optima

D
Different pH and different temperature optima

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Re-Attempt Weekly Quiz Competition

A) Sucrose	i) Glucose $$+$$ Fructose $$+$$ Galactose
B) Lactose	ii) Glucose $$+$$ Fructose
C) Maltose	iii) Glucose $$+$$ Galactose
D) Raffinose	iv) Glucose $$+$$ Glucose

Biomolecules Test - 76

Result

Biomolecules Test - 76

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SHARING IS CARING

Question 1

Carbohydrates

Proteins

Vitamins

Minerals

Solution

Question 2

They are specific in nature

They are used in chemical reactions

They are thermolabile in nature

They are proteinaceous in nature

Question 3

Aldehydes to alcohols

Ferric salts to ferrous salts

Chlorates to chlorides

Fehling solution to cuprous oxide

Solution

Question 4

A- iii , B- ii, C- i, D- iv.

A- ii, B- iii, C- i, D- iv.

A- ii, B- iii ,C- iv, D- i.

A- ii, B- iv, C- iii, D- i.

Solution

Question 5

8

7

9

None of these

Solution

Question 6

Amino acid substitutions

Sulphur substitutions

Allosteric subunits

High pH

Solution

Question 7

A - 1; B - 5; C - 3; D - 4; E - 6; F - 2

A - 2; B - 4; C - 3; D - 1; E - 6; F - 2

A - 3; B - 5; C - 3; D - 4; E - 6; F - 1

A - 5; B - 3; C - 4; D - 1,6; E - 1; F - 2

Solution

Question 8

not being used up in chemical reactions

working at high temperature

being proteinaceous in nature

working at high pH

Solution

Question 9

$$I_{2}$$ solution

Baeyer's reagent

Both $$A$$ and $$B$$

Fehling's solution

Solution

Question 10

Same pH and temperature optima

Same pH but different temperature optima

Different pH but same temperature optima

Different pH and different temperature optima

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