Biomolecules Test

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Biomolecules Test - 86

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Weekly Quiz Competition

Question 1
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Which of the following acts as a biological catalyst?

A
Carbohydrates

B
Lipids

C
Vitamins

D
proteins

Solution

Enzymes are biological catalysts. Biological means the substance in question is produced or is derived from some living organism.
Catalyst denotes a substance that has the ability to increase the rate of a chemical reaction and is not changed or destroyed by the chemical reaction that it accelerates.
And most enzymes are proteins, so proteins act as biological catalysts.

Option D is correct.
Question 2
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Complete hydrolysis of cellulose gives:

A
D-fructose

B
D-ribose

C
D-glucose

D
L-glucose

Solution

Cellulose is a straight-chain polysaccharide composed of D-glucose units which are joined by β-glycosidic linkages.
Hence, cellulose on hydrolysis produces only D-glucose units.
The answer is option $$C$$.
Question 3
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The purine base present in RNA is:

A
adenine

B
cytosine

C
uracil

D
thymine
Solution
$$\text{There are 4 purines and 4 pyrimidines that are of concern to us.}$$
Purines:
Adenine
Guanine
Hypoxanthine
Xanthine
Pyrimidines
Uracil
Thymine
Cytosine
Orotic acid
Therefore, in the given options $$adenine$$ is purine base. So it is present in RNA. Option A is correct.
Question 4
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The correct statement about the following disaccharide is:

A
ring (I) is pyranose with $$\alpha$$ - glycosidic link

B
ring (I) is furanose with $$\alpha$$ - glycosidic link

C
ring (II) is furanose with $$\alpha$$ - glycosidic link

D
ring (II) is pyranose with $$\beta$$ - glycosidic link

Solution

The disaccharide is source, with ring $$(I)$$ having $$6-$$members and hence is a pyranose and ring $$(II)$$ has $$5-$$ members and hence is a furanose. $$C-1$$ of ring $$(I)$$ has an $$\alpha-$$glycosidic linkage.
Hence option (A) is correct.
Question 5
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Which of the following is not a disaccharide?

A
cane sugar

B
raffinose

C
lactose

D
maltose
Solution
Cane sugar contains glucose and fructose so it is a disaccharide.
Lactose contains glucose and galactose so it is a disaccharide.
Maltose contains glucose and glucose so it is a disaccharide.
Raffinose contains 1 unit of glucose, 1 unit of fructose and 1 unit of galactose so it is not a disaccharide. It is a $$trisaccharide.$$
Option B is correct.
Question 6
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The production of starch, and not glucose, is often used as a measure of photosynthesis in leaves because

A
starch is immediete product of photosynthesis.

B
Glucose formed in photosynthesis soon gets converted into starch

C
Starch is soluble in water.

D
Sugar can not be tested.

Solution

Glucose is the immediate product of photosynthesis which is utilized by the plant and extra glucose is stored in form of starch in the leaves. As glucose gets utilized so its presence cannot be detected. But starch is stored in plants and it can be easily detected, hence the production of starch is often used as a measure of photosynthesis in leaves.

So, the correct option is B. 'Glucose formed in photosynthesis soon gets converted into starch'.
Question 7
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Ampholyte is :

A
$$H_2O$$

B
$$Zn(OH)_2$$

C
$$H_2NCH_2COOH$$

D
all of these

Solution
Question 8
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Parkinson's disease is linked to abnormalities in the levels of dopamine in the body. The structure of dopamine is.

A

B

C

D

Solution
Question 9
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An organic compound answers Molisch's test as well as Benedict's test.But it does not answer Scliwanoffs test.Most probably, it is

A
Sucrose

B
Protein

C
Fructose

D
Maltose

Solution

$$\text{Molisch}$$ test is for identifying $$\text{carbohydrates.}$$ $$\text{Benedict's test}$$ is for $$\text{aldehydes (not aromatic),}$$ and $$\text{scliwanoff's test}$$ is to $$\text{distinguish ketose from aldose.}$$ aldose doesn't show any positive test. so the organic compound may be an $$\text{aldose(carbohydrate with aldehyde group)}$$

$$\text{Hence, correct answer is Option (D).}$$
Question 10
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The metal present in $$Vitamin \ B_{12} $$ is

A
Magnesium

B
Iron

C
Cobalt

D
Manganese

Solution

$$Vitamin \ B_{12} $$ is also referred to as cobalamin because it contains A metal ion (Cobalt).
Hence, Option "C" is the correct answer.