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Polymers Test - 21

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Polymers Test - 21
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  • Question 1
    1 / -0
    The number of $$\pi-$$bonds present in the monomer of polyacrylonitrile is:
    Solution
    Polyacrylonitrile is obtained from a monomer, acrylonitrile having the structure as $$CH_2=CH-CN$$.
     
    Cyano group contains two $$\pi$$-bonds and a $$\sigma$$-bond.
     
    A double bond is present between two carbon atoms.
     
    Thus, three $$\pi -$$ bonds are present in the monomer.
  • Question 2
    1 / -0
    List-l                         List-ll                                    
    A)Rayon                   1)$$CH_{2}O+C_{6}H_{5}OH$$

    B)Silicone polymers  2) $$F_{2}C= CF_{2}$$
     
                                                 R
                                                  |
    C) Bakelite              3)  HO-Si-OH
                                                  |
                                                  R
    D) Teflon                     4)Cellulose
    Solution
    (A) Rayon:- Cellulose, organic polymer

    (B) Silicone polymers consist of Si atom. 

    (C) Bakelite:- condensation polymer formed by phenol and formaldehyde network structure

    (D) Teflon:- Tetrafluoro ethene get polymerize forming teflon

    A-4, B-3, C-1, D-2
  • Question 3
    1 / -0
    a.  $$Caprolactum\: \xrightarrow {hydrolysis} A$$

    b.  $$A + Glycine    \rightarrow B (Polymer) $$

    Here, $$B$$ is :
    I. Condensation Polymer
    II. Addition Polymer
    III. Polyamide Polymer
    IV. Polyester Polymer
    V. Biodegradable Polymer
    Solution
    The polymer B which is obtained is Dextron. It is condensation polymer of Glycine and Caprolactum as shown in diagram. It is polyamide polymer since it contains [CO-NH] linkage and it is biodegradable.
    Hence,option A is correct.

  • Question 4
    1 / -0
    Which of the following is not a synthetic rubber?
    Solution
    Synthetic rubber is a man-made polymer formed by chemical process.
    Natural rubber is cis - $$1,\:4$$ - polyisoprene obtained from rubber plants, whereas, Neoprene, Buna-S and Buna-N is produced by different chemical polymerization process using catalysis.
  • Question 5
    1 / -0
    Polymerization in which two or more chemically different monomers take part is called:
    Solution
    Copolymers are these polymers in which two or more monomer units combines and get polymerized. This polymerisation is called as Copolymerisation.
    For example: Dacron, Glyptal,  Nylon - $$6,6$$ etc.
  • Question 6
    1 / -0
    Which of the following monomer will make PHBV more flexible?
    Solution
    PHBV is a biodegradable polymer used for speciality packaging made up of the following:
    $$\beta$$-hydroxybutyric acid + $$\beta$$-hydroxyvelaric acid 
                               $$\downarrow$$
                             PHBV
    In which, $$\beta$$-hydroxy velaric acid makes polymer more flexible.
  • Question 7
    1 / -0
    A : A mixture of raw rubber and sulphur on heating at $$373\:K$$ - $$415\:K$$ gives vulcanised rubber.
    R : ZnO decreases the rate of vulcanisation of rubber.
    Solution
    Natural rubber becomes soft at high temperature (>335 K) and brittle at low temperatures (<283 K) and shows high water absorption capacity. It is soluble in non-polar solvents and is non-resistant to attack by oxidising agents. 

    To improve upon these physical properties, a process of vulcanisation is carried out. This process consists of heating a mixture of raw rubber with sulphur and an appropriate additive at a temperature range between 373 K to 415 K. On vulcanisation, sulphur forms cross links at the reactive sites of double bonds and thus the rubber gets stiffened.

    In sulfur vulcanization of natural rubber, the types of cross-links formed largely depend on the vulcanization system. The vulcanizing agents are zinc oxide (ZnO), stearic acid, accelerators, and sulfur. Conventional ZnO, or micro ZnO, is one of the basic components of rubber compounds and acts as an activator for rubber crosslinking by sulfur or sulfur donors.

    Hence, reason given is incorrect. So, option C is correct.
  • Question 8
    1 / -0
    A : The empirical formula of natural rubber is $$C_{5}H_{8}$$.
    R : Natural rubber contains no conjugate double bonds.
  • Question 9
    1 / -0
    Assertion:
    $$\bar{M_{n}}$$ value is always greater than $$\bar{M_{w}}$$ value for synthetic polymers.

    Reason:
    The mass average molecular weight of the polymer is equal to $$\bar{M_{w}}$$.
    Solution
    $$M_n$$, the number average molecular weight, is calculated from the mole fraction distribution of different sized molecules in a sample, and $$M_w$$, the weight average molecular weight, is calculated from the weight fraction distribution of different sized molecules.

    weight-average calculation puts equal statistical weights to each of the equal mass-fractions in the distribution, while a number-average puts equal weights to each of the equal number-fractions, and given two equal number-fractions, the one with the higher molecular mass molecules will be of a greater mass-fraction than the other

    Thus, Assertion is incorrect but Reason is correct

    Hence, the correct option is $$\text{D}$$
  • Question 10
    1 / -0

    Assertion: Natural rubber is all cis-polyisoprene. 

    Reason: trans - polyisoprene cannot be formed.

    Solution
    $$\text{Natural rubber consists almost exclusively of the cis-1,4 polymer.}$$
    $$\text{Trans-polyisopropene cannot be manufactured.}$$
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