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Polymers Test - 44

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Polymers Test - 44
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  • Question 1
    1 / -0
    The commercial name of polyacrylonitrile is:
    Solution
    The commercial name of polyacrylonitrile is orlon or acrilan,
    The addition polymerisation of acrylonitrile in presence of a peroxide catalyst leads to the formation of polyacrylonitrile. Polyacrylonitrile is used as a substitute for wool in making commercial fibers.
  • Question 2
    1 / -0
    Which of the following polymers can be formed by using the following monomer unit?

    Solution
    Nylon-6 is polymer of monomeric unit caprolactum, it is used for the manufacture of tyre cords, fabrics and ropes.
    So the correct option is [D].
  • Question 3
    1 / -0
    Which of the following is monomer of the given polymer?

    Solution
    The monomer is 2-methylpropene. It polymerises by addition polymerisation.

    Hence, option A is correct.

  • Question 4
    1 / -0
    Which of the following statements is not true about low density polythene?
    Solution
    LDP has soft surface due to which it has low working temperature and also has low tensile strength but high ductility.
  • Question 5
    1 / -0
    Natural rubber or raw rubber consists of basic material latex which is a dispersion of isoprene. During the treatment, this isoprene forms a high molecular weight polymer of isoprene. Natural rubber can be obtained from five hundred different species of plants.
    Consider the following properties of rubber,
    (i) Tensile strength of vulcanized rubber is almost ten times more than raw rubber.
    (ii) The elasticity of the raw rubber is very high.
    Choose the correct option.
    Solution
    The elasticity of raw rubber is very high-
    The cis-polyisoprene molecule consists of various chains held together by weak van der Waals interactions and has a coiled structure. Thus, it can be stretched like a spring and exhibits elastic properties.
    The tensile strength of vulcanized rubber is almost ten times more than raw rubber- The cross-linking of sulphur increases the tensile strength of vulcanized rubber.
  • Question 6
    1 / -0
    Give the likely structure of the polymer obtained in each of the following reactions. Also, tell whether these reactions are examples of chain-reaction or step-reaction polymers.

    Solution
    The places of polymer formation by repeated condensation reaction between two bi functional on trifunctional monomel unit by elimination of small molecules like $$H_2O,NH_3,CO_2$$ is known as condensation polymerization and the polymer formed by this reaction is called condensation Polymer
    Examle be- Terylene ,Bakelite, Nylon.6,Cellolose etc
    $$nNH_2(CH_2)_6NH_2+nCOOH(CH_2)_4COOH\rightarrow -\!\!\![NH(CH_2)_6NHCO(CH_2)_4CO-\!\!\!]\,+nH_2O$$
    The Polymer Nylon 6 is obtain by healing caprolactam  will water at high temperature.
    (Refer image)
    And the Nylon-6 polymer is fromed by step growth polymermization process where a single monomel is stepwise repeatedly condensed.
    Hence, Nylon-6 ans step Reaction Polymer is the correct option for the given Polymer Reaction.

  • Question 7
    1 / -0
    Terelyne is a:-
    Solution

  • Question 8
    1 / -0
    Find the odd one.
    Solution
    Thiokol Rubber is a condensation polymer of $$1,2$$- dichloroethane with sodium polysulphide where as others are addition polymers.

  • Question 9
    1 / -0
    Identify correct pair of monomers and their polymers?
    Solution
    Starch, a polymeric carbohydrate consisting of a large number of glucose units as monomers.
    Amino acids are monomers that made upto large macromolecules, proteins.
  • Question 10
    1 / -0
    Determine the degree of association (polymerization) for the reaction in aqueous solution
    $$6HCHO\rightleftharpoons C_6H_{12}O_6$$
    If observed (mean) molar mass of HCHO and $$C_6H_{12}O_6$$ is $$150$$.
    Solution
    Let us consider the problem.
    $$\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, 6HCHO \,\,\,\,\,\leftrightarrow {C_6}{H_{12}}{O_6}$$
    At equation $$c\left( {1 - \alpha } \right)\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\dfrac{{C\alpha }}{6}$$
    $$\dfrac{{Observed\,moles\,concentration}}{{Initial\,moles\,concentration}} = \dfrac{{{M_\gamma }}}{{{M_0}}}$$
    $$\dfrac{{C\left( {1 - \alpha } \right) + \dfrac{{C\alpha }}{6}}}{C} = \dfrac{{{M_\gamma }}}{{{M_0}}} = \dfrac{{30}}{{150}}$$
    Hence the answer is $$\alpha  = 0.96$$
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