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Electrochemistry Test - 22

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Electrochemistry Test - 22
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  • Question 1
    1 / -0

    Maintenance-free batteries, now in use, in place of common batteries, have :

    Solution
    Calcium-tin-lead alloys are used for making grids for maintenance-free batteries. The calcium content in such alloys for positive grids has varied generally from about 0.06 to about 0.1% by weight of the alloy while the tin has generally ranged from about 0.1 up to 0.8% and even more. More typically, the calcium content in such alloys when used for making maintenance-free battery grids has been at least about 0.08% by weight or more.
    B is correct
  • Question 2
    1 / -0

    Schematic diagram of an electrolytic-cell is:

    Solution
    In an electrolytic cell cations move towards cathode and anions move towards anode. In the external circuit, current flows from anode to cathode. Hence option B is correct.
  • Question 3
    1 / -0
    Which of the following oxide(s) of iron would be obtained on prolonged reaction of iron with steam?
    Solution
    On prolonged heating with steam Fe produces $$Fe_3O_4$$ and release hydrogen gas. It is a mixed oxide of Fe.

    $$3Fe+ 4H_2O \rightarrow Fe_3O_4(s) + 4H_2(g)$$
  • Question 4
    1 / -0
    The process of depositing a thin layer of desired metal over another metal by passing an electric current through some electrolyte is called as ?
    Solution
    Electroplating is the process of coating a metal object with a thin layer of another metal by means of process which is known as Electrolysis. The electroplated coating is usually no more than .002 inch (.05 mm) thick.
  • Question 5
    1 / -0
    $$Al_2O_3$$ is reduced by electrolysis at low potentials and high currents. If $$4.0 \times 10^4$$ amperes of current is passed through molten $$Al_2O_3$$ for 6 hours, what mass of aluminium is produced? (Assume 100% current efficiency, at. mass of $$Al = 27 g \;mol^{-1})$$
    Solution
    $$W=z\times I\times t\\ z=\dfrac { molar\quad mass }{ nf\times 96500 } \\ z=\dfrac { 27 }{ 3\times 96500 } \\ W=\dfrac { 27 }{ 3\times 96500 } \times 4\times { 10 }^{ 4 }\times 6\times 60\times 60\\ \quad =8.1\times { 10 }^{ 4 }g$$
  • Question 6
    1 / -0
    $$E_{N{a^ + }/Na(s)}^0 =  - 2.71V$$ ,  $$E_{M{g^{2 + }}/Mg(s)}^0 =  - 2.37V$$,  $$E_{F{e^{2 + }}/Fe(s)}^0 =  - 0.44V$$  and $$E_{C{r^{3 + }}/Cr(s)}^0 =  - 0.41V$$Based on this data, state which of the following is the weakest reducing agent.
    Solution
    $$M+nX   \rightarrow  M^{n+}+nX^-$$
    So higher the $$E^{\circ}_{M/M^{n-1}}$$  , stronger is that reducing agent.
    $$E^{\circ}_{Na/Na^+}=2.71$$  is largest
    $$\therefore  $$ Na is strongest reducing agent
    $$\therefore  Na^+$$  is weakest reducing agent $$E^{\circ}_{Na^+/Na}$$ is least
  • Question 7
    1 / -0

    For the cell reaction : $$C{u^{2 + }}(aq)({C_1}) + Zn(s) \to Z{n^{2 + }}(aq)({C_2}) + Cu(s)$$ the change in free energy $$\Delta G$$ at a given temperature is a function of

    Solution
    We know $$ΔG = nFE $$
    Again according to Nernst equation,
    $$E=\dfrac{0.059}{n}log$$$$\dfrac{[Zn^{2+}]}{[Cu^{2+}]}$$ $$at$$ $$ 25^0C$$

    So $$\Delta G$$ (free energy change) in an electrochemical cell at a given temperature is a function of
    $$ln$$$$\dfrac{[Zn^{2+}]}{[Cu^{2+}]}=ln \dfrac {C_2}{C_1}$$
  • Question 8
    1 / -0
    Which is true according to the Faraday Law of electrolysis? Here $$m$$ is the mass deposited at an electrode, $$Q$$ is the charge at the electrode and $$I$$ is the current passed.
    Solution
    $$W=ZQ$$(according to Faradays law of electrolysis)
    or $$m=ZQ$$
    $$m=$$ mass deposited
    $$m=Z\times I\times t$$
    So $$m\propto Q$$
  • Question 9
    1 / -0
    Corrosion of iron pipes occurs in the presence of water. To prevent such corrosion, iron pipes are normally coated with an element like magnesium using electroplating.
    Which of the following statements is correct?

  • Question 10
    1 / -0
    According to Faraday's law of electrolysis, the amount of decomposition is proportional to:
    Solution
    The amount of decomposition (i.e., mass of the substance liberated during electrolysis) is proportional to electro chemical equivalent of the substance.
    Using the relation $$[m= Z*i*t]$$
    where  Z is its electrochemical equivalent , i is current , t is time and m is the mass deposited or liberated .
    One can say that the amount of mass deposited will be proportional to the electrochemical equivalent of the substance.
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