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Electrochemistry Test - 8

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Electrochemistry Test - 8
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  • Question 1
    1 / -0

    Resistance of 0.2 M solution of an electrolyte is 50Ω. The specific conductance of the solution is 1.3s m-1. If resistance of the 0.4 M solution of the same electrolyte is 260Ω, its molar conductivity is

    Solution

    κ = G × cell constant and G= 1/R. For 0.2M solution, R = 50 ohms, k= 1.3Sm-1, cell constant l/A = 50 × 1.3 = 65m-1
    Λm = k/c for 0.4M solution , molar conductivity = ? , R = 260ohms, cell constant = 65m-1 so K = 65/260 = 0.25 Sm-1
    molar conductivity = K × 1000/M = 0.25/0.4 × 1000 = 6.25 × 10-4 Sm2/mol

  • Question 2
    1 / -0

    An increase in equivalent conductance of a strong electrolyte with dilution is mainly due to

    Solution

    Equivalent conductance increases on dilution for a strong electrolyte as interionic attraction also decreases along with dilution. So ionic mobility increases which in turn increases the equivalent conductance.

  • Question 3
    1 / -0

    Which of the following electrolytic solutions has the least specific conductance?

    Solution

    Specific conductance or conductivity decreases with decrease in concentration of the electrolytic solution as the number of ions per unit volume that carry the current in a solution decrease on dilution.

  • Question 4
    1 / -0

    The highest electrical conductivity of the following aqueous solutions is of

    Solution

    Acidity increases on attaching electron withdrawing group because of stability of conjugate base. Conduction of electric charge depends on the ions. so higher the number of ions higher is electrical conductivity. As fluoro group causes negative inductive effect increasing ionisation, it gives stable ions in solution. also in difluoroacetic acid, the presence of 2 fluorine atom increases the negative inductive effect.

  • Question 5
    1 / -0

    Saturated solution of KNO3 is used to make 'salt bridge' because

    Solution

    Saturated solution of KNO3 is used in salt bridge because of same mobility of K+ and NO. if the velocities would not have been the same then the ions would not have been able to neutralise the charge equally in both half cells. consequently, an opposing force would be developed that restricts the flow of current.

  • Question 6
    1 / -0

    Li occupies higher position in the electrochemical series of metals as compared to Cu since

    Solution

    Li is alkali metal Eo Li+/Li = -3.045V.

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