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Chemical Kinetics Test - 31

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Chemical Kinetics Test - 31
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  • Question 1
    1 / -0
    Which reaction in the diagram has the lowest activation energy?

    Solution
    In the given curves, activation energy will be lowest for the curve in which the peak is lowest of all as the initial energy of reactants is same for all curves.
    $$\Rightarrow \quad $$ $$D$$ has the lowest activation energy.
  • Question 2
    1 / -0
    How would the activation energy of the reaction diagram above be affected by an increase in temperature?

    Solution
    The increase in temperature increase the number of collision, which increases the rate of reaction. the activation energy curve would grow taller as the molecular collision occur at a higher temperature.
  • Question 3
    1 / -0
    Two molecules collide and a reaction not occur. Which of the following is not a valid explanation for this?
    Solution

    For a reaction to occur,

    $$(i)$$ The two molecules must collide with proper orientation.

    $$(ii)$$ They should have high kinetic energy.

    $$(iii)$$ The temperature should be high.

    $$(iv)$$ But the state of matter does not have any effect on the reaction.

    The states of matter molecules do not affect the rate of reaction.

  • Question 4
    1 / -0
    Activation energy, by definition, is the minimum amount of energy required for reactants to form products. Which of the following is not true of activation energy?
    Solution
    The rate of the reaction increases when the temperature increases because the kinetic energy of molecules increases with increasing temperature. As a result, more molecular collisions occur with energy equal to or greater than the activation energy.
    The value of activation energy varies from reaction to reaction.
  • Question 5
    1 / -0
    A graph of concentration versus time data for a first-order reaction gives a straight line in which of the following plots of the data?
    Solution
    For the first order reaction,
    $$ \ln { \cfrac { [{ A }_{ o }] }{ [{ A }_{ t }] }  } =kt\\ \therefore \ln { [{ A }_{ o }] } =kt+\ln { { [A] }_{ t } } \\ \therefore \ln { [{ A }]_{ t } } =-kt+\ln { { [A }]_{ o } } $$
  • Question 6
    1 / -0
    Assertion: The rate of the reaction of iron and hydorchloric acid will increase if the iron pieces are cut into smaller pieces.
    Reason: Increasing surface area of a reactant helps to reduce activation energy.
    Solution
    It is known that increasing the surface area of the reactants results in more collision of the reactants molecules in any given time which increases the rate of reaction. Due to an increase in surface area of reactant, the activation energy is reduced & the rate of reaction increases.
    So, assertion &  reason are true &  reason is the correct explanation of assertion.
  • Question 7
    1 / -0
    In a reaction mechanism consisting of elementary reaction steps where the relative rate of each is given, which of the following is most likely to be the rate-determining step?
    Solution

    In a multi-step reaction, the elementary step having the slowest-rate is always the rate determining step of the overall reaction.

    Therefore, a step labeled slow will be the rate determining step.

  • Question 8
    1 / -0
    Here is another look at the reaction of crystal violet with sodium hydroxide, a first-order reaction (ln $$A$$ v time).
    What is the significance of the slope?

    Solution
    The slope represents the change in concentration over time showing in this diagram
    digram is show the first order reaction
  • Question 9
    1 / -0
    Reacting $$Cl$$ with $$NO_{2}Cl$$ molecules produces $$NO_{2}$$ and $$Cl_{2}$$ gases.
    Which of the following will require the lowest activation energy based on proper orientation for this reaction?
    Solution
    The atom collides to $$Cl$$ atom present in $$N{ O }_{ 2 }Cl$$. molecule with proper orientation & head or collision.
    Therefore, very low activation energy is required.
  • Question 10
    1 / -0
    An experiment was performed to study the kinetics of the decomposition of substance $$X$$. The concentration of $$X$$, $$[X]$$, was monitored over time as the reaction proceeded. The data are shown in the table above. The time interval between concentration measurements was $$1.0\ minutes (60 s)$$.
    Time (s)$$[X]$$$$ln[X]$$$$\dfrac {1}{[X]}$$
    $$0$$$$20.0$$$$3.00$$$$0.050$$
    $$60$$$$10.0$$$$2.30$$$$0.100$$
    $$120$$$$6.67$$$$1.90$$$$0.150$$
    $$180$$$$5.00$$$$1.61$$$$0.200$$
    $$240$$$$4.00$$$$1.39$$$$0.250$$
    Which of the following best describes the reaction?
    Solution
    Form the given data,
    $$ \cfrac { 1 }{ [X] } \propto Time(t)\\ \therefore \cfrac { 1 }{ [X] } =Kt\longrightarrow $$ K=constant
    $$ \therefore K=\cfrac { 1 }{ [X]t } $$
    $$ \therefore$$ Unit of K are $${ M }^{ -1 }{ time }^{ -1 } $$ which is possible only for second order reaction
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