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Chemical Kinetics Test - 81

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Chemical Kinetics Test - 81
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  • Question 1
    1 / -0
    The energy of activation for reaction $$(KJ/mol)$$ is :

    Solution

  • Question 2
    1 / -0
    For a zero order reaction
    Solution
    Rate of $$\textbf {zero order}$$ reaction is independent of the concentration of the reactant and remains constant throughout the reaction.
    hence option (C) is correct.
  • Question 3
    1 / -0
    The rate constant is doubled when temperature increases from $$27^{o}C$$ to $$37^{o}C$$. Activation energy in $$kJ$$ is:
    Solution
    $$\log{\dfrac{K_2}{K_1}}=\dfrac{E_a}{2.303R}\left[\dfrac{1}{T_1}-\dfrac{1}{T_2}\right]$$

    If $$\dfrac{K_2}{K_1}=2$$

    $$\log{2}=\dfrac{E_a}{2.303\times8.314}\left[\dfrac{1}{300}-\dfrac{1}{310}\right]$$

    $${E}_{a}$$ = $$.3010\times2.303\times8.314\left(\dfrac{300\times310}{10}\right)$$

    = $$53598.59 J{mol}^{-1}$$

    = $$53.6kJ$$
  • Question 4
    1 / -0
    A zero order reaction is one whose rate is independent of_________________________
    Solution
    The rate of zero order reaction is not depend on the concentration of the reactants.

    $$Rate = K[A]^0$$
  • Question 5
    1 / -0
    The energy of activation is
    Solution
    Activation energy is the energy needed by reactant molecules to gain threshold energy level.
  • Question 6
    1 / -0
    Activation energy is given by the formula
    Solution
    $$log_eK_2 = log_eA - \cfrac{E_A}{RT_2}$$...........(1)

    $$log_eK_1 = log_eA - \cfrac{E_A}{RT_1}$$..............(2)

    Eqn. (1) - (2) we get,

    $$\log{\cfrac{K_2}{K_1}}=\cfrac{E_a}{2.303R}\left[\cfrac{{T_2}-{T_1}}{{T_1}{T_2}}\right]$$

     Option A is correct.
  • Question 7
    1 / -0
    Certain bimolecular reactions which follow the first order kinetics are called_________________________ 
    Solution
    It is the characteristic of pseudo-unimolecular reactions.
  • Question 8
    1 / -0
    The $$\Delta H$$ value of the reaction $$H_2 + Cl_2 \rightleftharpoons 2HCl$$ is $$-44.12 \,kcal$$. If $$E_1$$ is the activation energy of the products, then for the above reaction
    Solution
    • $$\Delta {H} = E_2- E_1= Negative$$
    $$E_1$$ is the activation energy of the products
    $$E_2$$ is the activation energy of the reactants.

    Thus , $$E_1>E_2$$

    Option (A) is correct.
  • Question 9
    1 / -0
    Half-life period of a zero order reaction is:
    Solution
    $$t_{1/2}$$ of zero-order reaction is independent of the concentration.

    Hence, option B is correct.
  • Question 10
    1 / -0
    Assertion : Order of the reaction can be zero or fractional.
    Reason    : We cannot determine order from the balanced chemical equation.
    Solution
    The assertion is correct as the order can be zero or fraction but it can be determined experimentally.

    Hence, Option "B" is the correct answer.
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