General Principles and Processes of Isolation of Elements Test

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General Principles and Processes of Isolation of Elements Test - 46

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Question 1
1 / -0

The ore that is concentrated by froth flotation process is:

A
Cinnabar

B
Bauxite

C
Malachite

D
Zincite

Solution

Ores which are concentrated by froth floatation process include Galena (PbS), zinc blende (ZnS) and cinnabar (HgS).

Hence , option A is correct.
Question 2
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The function of fractionating column is:

A
to separate the two components

B
to provide greater, cooling surface to the vapours

C
to kept the vapour pressure constant

D
to avoid mixing of the vapours of two components

Solution

Fractionating column is used in distillation. It helps in bringing the temperature of the vapours lower so that the liquid is attained in its pure form.
Question 3
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Distillation under reduced pressure is used to purify liquids which:

A
are highly volatile

B
have high boiling points

C
are explosives

D
decomposes below their boiling points

Solution

Generally liquids that decomposes at their boiling point or before attaining boiling point requires distillation as a separation method.
Question 4
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For the reaction of FeO at the temperature corresponding to point D, which of the following statement is correct?

A
$$\Delta G $$ value for overall reduction reaction with carbon monoxide is zero.

B
$$\Delta G $$ value for overall reduction reaction with a mixture of 1 mol of carbon and 1 mol of oxygen is positive

C
$$\Delta G $$ value for overall reduction reaction with a mixture of 2 mol of carbon and 1 mol of oxygen is positive

D
$$\Delta G $$ value for overall reduction reaction with carbon monoxide is negative

Solution
Question 5
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Pyrolusite is a/an :

A
oxide ore

B
sulphide ore

C
carbide ore

D
not an ore

Solution

Pyrolusite is an oxide ore of manganese. It is the most common manganese mineral with chemical formula $$MnO_{2}$$.

Hence, option (A) is correct.
Question 6
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Cassiterite is an ore of :

A
$$Mn$$

B
$$Ni$$

C
$$Sb$$

D
$$Sn$$

Solution

Cassiterite is a tin oxide mineral, $$SnO_{2}$$. It is the world's primary ore of tin. It is colourless when pure, but brown or black when iron impurities are present.

Hence, the correct option is (D).
Question 7
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$$ACl_2 +BCl_2 \longrightarrow ACl_4 +B \downarrow$$
(Excess)

$$BO\xrightarrow [ ]{ Heat } B+\dfrac12{ O }_{ 2 }$$
($$A$$ and $$B$$ are metals.)

Their ore of $$B$$ is :

A
cinnabar

B
azurite

C
galena

D
siderite

Solution

$$ACl_2 +BCl_2 \longrightarrow ACl_4 +B \downarrow$$
(Excess)

In this reaction, we can see that the oxidation number of A changes from +2 to +4. So, A should be Sn.

$$BO\xrightarrow [ ]{ Heat } B+\dfrac12{ O }_{ 2 }$$

The oxidation number of B changes from +2 to 0. B should be less reactive metal. So it is Hg. The ore of Hg is cinnabar.

Option (A) is correct.
Question 8
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Consider the following statements :
Roasting is carried out to:
1. convert sulphide into oxide
2. melt the ore
3. remove moisture, water of hydration and expel organic matter
4. remove sulphur and arsenic in the form of volatile oxides
Out of these statements:

A
$$1, 3$$ and $$4$$ are correct

B
$$1, 2$$ and $$3$$ are correct

C
$$2, 3$$ and $$4$$ are correct

D
$$1, 2$$ and $$4$$ are correct

Solution

ROASTING
The removal of the excess sulphur contained in sulphide ores by heating in an excess of air is called roasting. The concentrated sulphide ore is heated in reverberatory furnace, below its melting point or fusion temperature in the presence of an excess of air with or without the addition of an external substance.
In roasting definite chemical like oxidation, chlorination etc. take place but in calcination does not occur any major chemical changes.

Advantages of Roasting :
(i) Excess of sulphur is removed as volatile oxide.
(ii) The metal sulphide is converted into metal oxide and sulphate.
(iii) Impurities of arsenic and antimony are removed as their volatile oxides.

Hence , option A is correct .
Question 9
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In Hall's process, the ore is mixed with

A
coke

B
calcium carbonate

C
sodium hydroxide

D
sodium carbonate

Solution

Hall's process is used for the extraction of Aluminum from Alumina. Bauxite is concentrated through Hall’s process, in which sodium aluminate is prepared using sodium carbonate in bauxite. When excess carbon dioxide is passed through sodium aluminate in the presence of water, it forms aluminum hydroxide along with sodium carbonate. When dried aluminum hydroxide is ignited, alumina is formed.

The reaction involved in Hall's process is as follows:

$$Al_2O_3.2H_2O+2Na_2CO_3→2NaAlO_2+CO_2+2H_2O$$

Option D is correct.
Question 10
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Which of the following elements occurs in native state?

A
$$I$$

B
$$S$$

C
$$Si$$

D
$$P$$

Solution

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General Principles and Processes of Isolation of Elements Test - 46

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General Principles and Processes of Isolation of Elements Test - 46

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Question 1

Cinnabar

Bauxite

Malachite

Zincite

Solution

Question 2

to separate the two components

to provide greater, cooling surface to the vapours

to kept the vapour pressure constant

to avoid mixing of the vapours of two components

Solution

Question 3

are highly volatile

have high boiling points

are explosives

decomposes below their boiling points

Solution

Question 4

$$\Delta G $$ value for overall reduction reaction with carbon monoxide is zero.

$$\Delta G $$ value for overall reduction reaction with a mixture of 1 mol of carbon and 1 mol of oxygen is positive

$$\Delta G $$ value for overall reduction reaction with a mixture of 2 mol of carbon and 1 mol of oxygen is positive

$$\Delta G $$ value for overall reduction reaction with carbon monoxide is negative

Solution

Question 5

oxide ore

sulphide ore

carbide ore

not an ore

Solution

Question 6

$$Mn$$

$$Ni$$

$$Sb$$

$$Sn$$

Solution

Question 7

cinnabar

azurite

galena

siderite

Solution

Question 8

$$1, 3$$ and $$4$$ are correct

$$1, 2$$ and $$3$$ are correct

$$2, 3$$ and $$4$$ are correct

$$1, 2$$ and $$4$$ are correct

Solution

Question 9

coke

calcium carbonate

sodium hydroxide

sodium carbonate

Solution

Question 10

$$I$$

$$S$$

$$Si$$

$$P$$

Solution

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