Halogens have a strong tendency to accept electrons. The substances that accept electrons from others are termed oxidizing agents. Thus, halogens act as good oxidizing agents.
The oxidizing powers of halogens are measured in terms of their electrode potentials. The electrode potential is the potential difference developed between the electrode and the electrolyte.
The electrode potentials of halogens decrease in the order:
\(F_{2}(+2.87 \mathrm{~V})>\mathrm{Cl}_{2}(+1.36 \mathrm{~V})>\mathrm{Br}_{2}(+1.09 \mathrm{~V})>\mathrm{I}_{2}(+0.54 \mathrm{~V})\)
Same is the order of their oxidizing powers.
\(\mathrm{HCl}\) is a weak reducing agent than \(\mathrm{HBr}\) and \(\mathrm{Br}_{2}\) is a stronger oxidizing agent than \(\mathrm{I}_{2}\).
The oxidation state of Sulphur in sodium thiosulphate \(\left(\mathrm{Na}_{2} \mathrm{~S}_{2} \mathrm{O}_{3}\right)\) is a whole number \((+2)\), while that in sodium tetrathionate \(\left(\mathrm{Na}_{2} \mathrm{~S}_{4} \mathrm{O}_{6}\right)\) it is a fraction (+2.5).
Hence, the correct option is (C).