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The p-Block Elements Test - 14

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The p-Block Elements Test - 14
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Weekly Quiz Competition
  • Question 1
    1 / -0

    On heating lead nitrate forms oxides of nitrogen and lead. The oxides formed are ______.

    Solution

    2Pb(NO3)→ 2PbO + 4NO2 + O2

     

  • Question 2
    1 / -0

    Which of the following elements does not show allotropy?

    Solution

    The single N-N bond is weak because of high inter-electronic repulsion of the non-bonding electrons, owing to the small bond length. As a result the catenation tendency is weaker in nitrogen that is why it does not show allotropy.

     

  • Question 3
    1 / -0

    Maximum covalency of nitrogen is _________.

    Solution

    The electronic configuration of nitrogen is ns2np3. Nitrogen is restricted to the maximum covalency of 4 since only four (one s and three p) orbitals are available for bonding.

     

  • Question 4
    1 / -0

    If chlorine gas is passed through hot NaOH solution, two changes are observed in the oxidation number of chlorine during the reaction. These are ________ and _________.

    (i) 0 to +5

    (ii) 0 to +3

    (iii) 0 to –1

    (iv) 0 to +1

    Solution

    6NaOH + 3Cl2 → 5NaCl + NaClO3 + 3H2O

    When chlorine gas is passed through hot NaOH solution it produces NaCl and NaClO3 . Thus oxidation state of chlorine changes from 0 to -1 and 0 to +5 respectively.

     

  • Question 5
    1 / -0

    Which of the following statements are correct?

    (i) Among halogens, radius ratio between iodine and fluorine is maximum.

    (ii) Leaving F—F bond, all halogens have weaker X—X bond than X—X' bond in interhalogens.

    (iii) Among interhalogen compounds maximum number of atoms are present in iodine fluoride.

    (iv) Interhalogen compounds are more reactive than halogen compounds.

    Solution

    (i) Among group 17 elements radius ratio of iodine and fluorine is maximum because size of iodine is largest and fluorine is smallest in the group.

    (ii) The correct statement is inter halogen compounds are more reactive than halogens (except fluorine). This is because X-X’ bond in interhalogens is weaker than X-X bond in halogens except F-F.

    (iii) As the ratio between radii of X and X’ increase, the number of atoms per molecule also increases. Thus, iodine (VII) fluoride should have maximum number of atoms as the ratio of radii between I and F will be maximum.

    (iv) Interhalogen compounds are more reactive than halogens (except fluorine). This is because X-X’ bond in interhalogens is weaker than X-X’ bond in halogens.

     

  • Question 6
    1 / -0

    Assertion : N2 is less reactive than P4.

    Reason : Nitrogen has more electron gain enthalpy than phosphorus.

    Solution

    N2 is less reactive than P4 molecule this is so, because nitrogen has very high bond dissociation enthalpy because of triple bond between two nitrogen atom which is not the case with phosphorus.

     

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