The p-Block Elements Test

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The p-Block Elements Test - 19

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Weekly Quiz Competition

Question 1
1 / -0

The halogen which can form both cations and anions is:

A
F

B
Cl

C
Br

D
I

Solution

Iodine can form both cations, as well as anions. Iodine can form cations due to the poor shielding effect of d orbitals where electrons can be removed from the valence shell and the cation is formed.
The cations and anions of Iodine is represented as follow:
$$ I^{-}$$ and $$I^{+}$$
Question 2
1 / -0

The electronic configuration of halogens in their valence shell is:

A
$$\mathrm{n}\mathrm{s}^{2}$$

B
$$\mathrm{n}\mathrm{s}^{2}\mathrm{n}\mathrm{p}^{6}$$

C
$$\mathrm{n}\mathrm{s}^{0}$$

D
$$\mathrm{n}\mathrm{s}^{2}\mathrm{n}\mathrm{p}^{5}$$

Solution

$$\underline{Halogens}$$
Electronic configuration in their
valence shells =$$ns^{2} np^{5}$$
Question 3
1 / -0

In the third excited state, the number of unpaired electrons in chlorine atom is:

A
5

B
7

C
3

D
1

Solution

The general electronic configuration of chlorine is $$[Ne] 3s^{2} 3p^{5}$$.

When electrons are excited in chlorine, the electrons enter into 3d subshell then the electronic configuration of chlorine is given as:
$$[Ne] 3s^{1} 3p^{3} 3d^{3}$$

Thus the number of unpaired electrons will be 7.
Question 4
1 / -0

Halogen elements are those which are:

A
diatomic and form $$X^{--}$$ ions

B
monatomic and form $$\mathrm{X}^{-}$$ ions

C
diatomic and form $$\mathrm{X}^{-}$$ ions

D
monoatomic and form $$X^{--}$$ ions

Solution

Halogen atoms have 7 electrons in their valence shell. So, they require only one electron to complete its octet. Thus, halogens are present in a diatomic form in order to complete their octet by sharing of electrons. Also,
$$x+e^- \rightarrow x^-\ (stable\ for\ Halogens)$$
Question 5
1 / -0

Fluorine does not show variable oxidation states because_________

A
it is a halogen

B
of absence of d-orbitals

C
absence of s-orbital

D
absence of p-orbitals

Solution

Fluorine cannot expand its octet due to absence of d-orbitals.

Therefore it cannot show variable oxidation states.

Option B is correct.
Question 6
1 / -0

The oxidation state of chlorine in bleaching powder is:

A
-2

B
- 1

C
+ 1

D
-1 and + 1

Solution

The chemical formula of bleaching powder is $$CaOCl_{2}$$.

Here, calcium is bonded to $$Cl^{-}$$ ion and $$OCl^{-}$$ ion respectively.

In $$Cl^{-}$$ the oxidation state of chlorine is -1 and in $$OCl^{-}$$ ion the oxidation state of chlorine is +1.
Question 7
1 / -0

The element which can displace three other halogens from their compound is :

A
$$Cl$$

B
$$Br$$

C
$$I$$

D
$$F$$

Solution

F can displace other halogens from their compounds due to its oxidising nature ( Reaction will be feasible).

Reactivity decreases from F to I.

Option D is correct.
Question 8
1 / -0

The halogen which can displace three halogens from their compounds is:

A
$$F$$

B
$$Cl$$

C
$$Br$$

D
$$I$$

Solution

F can displace all other halogens from their compounds i.e three halogens this is because of small size and high electronegativity of fluorine.
Question 9
1 / -0

Which of the following is not formed in the reaction of Xe with $$F_2$$?

A
$$\mathrm{X}\mathrm{e}\mathrm{O}\mathrm{F}_{4}$$

B
$$\mathrm{X}\mathrm{e}\mathrm{F}_{2}$$

C
$$\mathrm{X}\mathrm{e}\mathrm{F}_{4}$$

D
$$\mathrm{X}\mathrm{e}\mathrm{F}_{6}$$

Solution

$$Xe+F_2\xrightarrow \ XeF_2$$
$$Xe+2F_2\xrightarrow \ XeF_4$$
$$Xe+3F_2\xrightarrow \ XeF_6$$
$$XeOF_4$$ is never formed in reaction of Xe with $$F_2$$
Question 10
1 / -0

Which of the following are formed by xenon?

A
$$ \mathrm{X}\mathrm{e}\mathrm{F}_{7}$$

B
$$ \mathrm{X}\mathrm{e}\mathrm{F}_{4}$$

C
$$ \mathrm{X}\mathrm{e}\mathrm{F}_{5}$$

D
$$ \mathrm{X}\mathrm{e}\mathrm{F}_{3}$$

Solution

$$XeF_4 - $$ This compound is formed by xenon .

Xe compounds can contain only even no. of fluorine atoms.

Xe has a complete filled 5p configuration.As a result when it undergoes bonding with an odd number (3 or 5) of F atoms it leaves behind one unpaired electron. This causes the molecule to become unstable.

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The p-Block Elements Test - 19

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The p-Block Elements Test - 19

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Question 1

F

Cl

Br

I

Solution

Question 2

$$\mathrm{n}\mathrm{s}^{2}$$

$$\mathrm{n}\mathrm{s}^{2}\mathrm{n}\mathrm{p}^{6}$$

$$\mathrm{n}\mathrm{s}^{0}$$

$$\mathrm{n}\mathrm{s}^{2}\mathrm{n}\mathrm{p}^{5}$$

Solution

Question 3

5

7

3

1

Solution

Question 4

diatomic and form $$X^{--}$$ ions

monatomic and form $$\mathrm{X}^{-}$$ ions

diatomic and form $$\mathrm{X}^{-}$$ ions

monoatomic and form $$X^{--}$$ ions

Solution

Question 5

it is a halogen

of absence of d-orbitals

absence of s-orbital

absence of p-orbitals

Solution

Question 6

-2

- 1

+ 1

-1 and + 1

Solution

Question 7

$$Cl$$

$$Br$$

$$I$$

$$F$$

Solution

Question 8

$$F$$

$$Cl$$

$$Br$$

$$I$$

Solution

Question 9

$$\mathrm{X}\mathrm{e}\mathrm{O}\mathrm{F}_{4}$$

$$\mathrm{X}\mathrm{e}\mathrm{F}_{2}$$

$$\mathrm{X}\mathrm{e}\mathrm{F}_{4}$$

$$\mathrm{X}\mathrm{e}\mathrm{F}_{6}$$

Solution

Question 10

$$ \mathrm{X}\mathrm{e}\mathrm{F}_{7}$$

$$ \mathrm{X}\mathrm{e}\mathrm{F}_{4}$$

$$ \mathrm{X}\mathrm{e}\mathrm{F}_{5}$$

$$ \mathrm{X}\mathrm{e}\mathrm{F}_{3}$$

Solution

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