The p-Block Elements Test

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The p-Block Elements Test - 22

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Weekly Quiz Competition

Question 1
1 / -0

The catalytic promoter used in Haber's process is :

A
Mo

B
Ni

C
Pt

D
$$\mathrm{V}_{2}\mathrm{O}_{5}$$

Solution

$$Mo$$ is used as catalytic promoter in Haber's process.
Question 2
1 / -0

Calcium cyanamide on treatment with steam under pressure gives ammonia and :

A
calcium carbonate

B
calcium hydroxide

C
calcium oxide

D
calcium bicarbonate

Solution

$$CaCN_2+3H_2O\rightarrow CaCO_3+2NH_3$$
Question 3
1 / -0

Nitrogen form $$N_2$$ but phosphorous when forms $$P_2$$ gets readily converted into $$P_4$$ because : -

A
Triple bond present between phosphorous atom

B
$$p_\pi- p_\pi$$bonding is weak

C
$$p_\pi- p_\pi$$bonding is strong

D
Multiple bond form easilly

Solution

Phosphorus is unable to form $$p\pi-p\pi$$ bonds due to larger atomic size. So, $$P$$ atom is linked with $$P$$ atoms using $$3$$ sigma bonds. On the other hand, Nitrogen forms $$1-\sigma$$ and $$2-\pi$$ bonds i.e., triple bonds and exists as diatomic molecules.
Question 4
1 / -0

Ammonia is dried over :

A
Quick lime

B
Slaked lime

C
Phosphorus pentoxide

D
Con. $$\mathrm{H}_{2}\mathrm{S}\mathrm{O}_{4}$$

Solution

Hint: Ammonia can be dried by such a reagent with which it does not react.

Correct Option: $$A$$
Explanation:
·       Ammonia is dried on being passed through quick lime.
· As ammonia is basic it can’t be dried with phosphorus pentoxide or concentrated sulfuric acid because both are acidic in nature and there will be acid base reaction will happen.
·       Ammonia can’t be dried over $$Ca{(OH)_2}$$ . The reaction is as follows;
              $${\text{N}}{{\text{H}}_4}{\text{Cl}} + {\text{Ca}}{({\text{OH}})_2} \to {\text{CaC}}{{\text{l}}_2} + {\text{N}}{{\text{H}}_4}{\text{OH}}$$
  $$2{\text{N}}{{\text{H}}_3} + {{\text{H}}_2}{\text{S}}{{\text{O}}_4} \to {\left( {{\text{N}}{{\text{H}}_4}} \right)_2}{\text{S}}{{\text{O}}_4}$$
              $$4{\text{N}}{{\text{H}}_3} + {{\text{P}}_2}{{\text{O}}_5} + 3{{\text{H}}_2}{\text{O}} \to {\left( {{\text{N}}{{\text{H}}_4}} \right)_3}{\text{P}}{{\text{O}}_4}$$
   Ammonia can be dried with quick lime as quicklime is also basic as like ammonia so there will be no reaction takes place.
Question 5
1 / -0

Non metals are usually poor conductors of heat and electricity. They are non-lustrous, non-sonorous, non-malleable and are coloured.

Non-metal other than carbon, which shows allotropy is:

A
sulphur

B
phosphorus

C
nitrogen

D
both A and B

Solution

Sulfur has a large number of allotropes, second only to carbon. Some allotropes are rhombic sulphur, monoclinic sulphur, etc.
Phosphorus also has some allotropes like red phosphorus, white phosphorus and black phosphorus.
Question 6
1 / -0

Which of the following belongs to the halogen family?

A
Francium

B
Polonium

C
Radium

D
Astatine

Solution

Astatine belongs to halogen family.
Question 7
1 / -0

Chlorine was discovered by:

A
Priestley

B
Davy

C
Scheele

D
Cavendish

Solution

Chlorine was discovered by Carl Wilhelm Scheele.
Question 8
1 / -0

Zero group elements are known as____________.

A
alkali metals

B
alkaline earth metals

C
transition metals

D
inert gases

Solution

The elements of group $$0$$ have stable complete octate configuration. As a result, they do not react with other elements easily, i.e., they have inert behavior. Hence they are also called inert gases.
Question 9
1 / -0

Most abundant uncombined element present in atmosphere is :

A
Ca

B
Mg

C
Al

D
N

Solution

Nitrogen gas $$N_2$$ makes up about 78% of the atmosphere by volume.
Question 10
1 / -0

The percentage of p-character in the orbitals forming P−P is :

A
25

B
33

C
50

D
75

Solution

In $$P_4$$, all P atoms are in $$sp^3$$ hybridization so p-character in the orbitals forming PP bonds $$100*3/4 =75$$ %.

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Re-Attempt Weekly Quiz Competition

The p-Block Elements Test - 22

Result

The p-Block Elements Test - 22

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SHARING IS CARING

Question 1

Mo

Ni

Pt

$$\mathrm{V}_{2}\mathrm{O}_{5}$$

Solution

Question 2

calcium carbonate

calcium hydroxide

calcium oxide

calcium bicarbonate

Solution

Question 3

Triple bond present between phosphorous atom

$$p_\pi- p_\pi$$bonding is weak

$$p_\pi- p_\pi$$bonding is strong

Multiple bond form easilly

Solution

Question 4

Quick lime

Slaked lime

Phosphorus pentoxide

Con. $$\mathrm{H}_{2}\mathrm{S}\mathrm{O}_{4}$$

Solution

Question 5

sulphur

phosphorus

nitrogen

both A and B

Solution

Question 6

Francium

Polonium

Radium

Astatine

Solution

Question 7

Priestley

Davy

Scheele

Cavendish

Solution

Question 8

alkali metals

alkaline earth metals

transition metals

inert gases

Solution

Question 9

Ca

Mg

Al

N

Solution

Question 10

25

33

50

75

Solution

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