The p-Block Elements Test

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The p-Block Elements Test - 28

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Weekly Quiz Competition

Question 1
1 / -0

Total number of covalent bonds in a white phosphorous molecule is:

A
1

B
4

C
3

D
6

Solution

Number covalent bonds present in white phosphorous $$P_4$$ is 6.
Hence opion D is correct.
Question 2
1 / -0

Statement - I: He -II has high viscosity and flows downward.
Statement - II: Liquid helium is used as cryogenic liquid.

A
Both I and II are true. II is correct

explanation of I.

B
Both I and II are true. II is not correct

explanation of I.

C
I is true but II is false

D
I is false but II is true.

Solution

Helium has low viscosity due to
less van der wool's forces.
It flows upward as it is
lighter than air. Due to low
viscosity it is used as cryogenic
liquid
Question 3
1 / -0

In clathrate atoms or molecules the bond formed is :

A
Metallic

B
Covalent

C
Ionic

D
They do not form bond

Solution

In clathrate bond is not
formed. There is only dipole-
induced dipole interaction which
is not a bond.
Question 4
1 / -0

Assertion (A): Solubility of noble gases in water decreases with increase in atomic size.
Reason (R): Solubility is due to dipole-induced dipole interaction.

A
Both $$A$$ and $$R$$ are correct and $$R$$ is the correct explanation of $$A$$.

B
Both $$A$$ and $$R$$ are correct and $$R$$ is not the correct explanation of $$A$$.

C
$$A$$ is true but $$R$$ is false.

D
$$A$$ is false but $$R$$ is true.

Solution

Solubility $$\alpha $$ dipole-induced dipole interaction $$\alpha $$ Surface area
More surface area more interaction more solubility. Surface area increases down the group. Thus, solubility increases down the group.
Question 5
1 / -0

Which of the following is a superfluid?

A
Krypton

B
Argon II

C
Helium II

D
Helium I

Solution

$$He(II)$$ is a superfluid.
Question 6
1 / -0

The anomalous behaviour of nitrogen is due to:

A
small size and high electronegativity

B
non availability of d-orbitals in valency shell

C
ease of multiple bond formation

D
all are correct

Solution

Nitrogen differs from other members of the group due to its smaller size, high electronegativity, high IE and non availability of d-orbitals. Nitrogen has unique ability to form $$p\pi - p\pi $$ multiple bonds with itself and with other elements having small size and high electronegativity.
Question 7
1 / -0

The solubility of noble gases in water shows the order :

A
$$ He > Ar > Kr > Ne > Xe $$

B
$$ He > Ne > Ar > Kr > Xe $$

C
$$ Xe > Kr > Ar > Ne > He $$

D
$$ Xe > Ar > Ne > Kr > He $$

Solution

Noble gases are sparingly soluble in water and the solubility increases from helium to xenon.
Question 8
1 / -0

Assertion (A): A mixture of $$CaCN_2$$ and graphite is known as nitration mixture.
Reason (R) : $$NH_3$$ is collected by downward displacement of air.

A
Both (A) and (R) are true and (R) is the correct explanation of (A)

B
Both (A) and (R) are true and (R) is not the correct explanation of (A)

C
(A) is true and (R) is false

D
(A) is false but (R) is true

Solution

$$HNO_{3}+H_{2}SO_{4}$$ is known as nitration mixture. So, A is wrong.
$$NH_{3}$$ is collected by downward displacement of air as $$NH_{3}$$ is lighter than air.
Question 9
1 / -0

Ammonia is not a product in the :

A
hydrolysis of nitrolim

B
hydrolysis of aluminium nitride

C
decomposition of ammonium nitrite

D
hydrolysis of urea

Solution

$$NH_3NO_3\rightarrow N_2O+2H_2O$$
Nitrous oxide is produced after decomposition of ammonium nitrite instead of ammonia.
Question 10
1 / -0

Hydrolysis of $$\mathrm{M}\mathrm{g}_{3}\mathrm{N}_{2}$$ gives :

A
$$ \mathrm{N}\mathrm{H}_{3}$$

B
$$\mathrm{N}\mathrm{O}$$

C
$$\mathrm{H}_{2}$$

D
$$\mathrm{C}\mathrm{O}_{2}$$

Solution

Hydrolysis of $$Mg_3N_2$$ is explained by following reaction.
$$Mg_3N_2 + 6H_2O \rightarrow 3Mg{(OH)}_{3} + 2NH_3$$
So, $$NH_3$$ is formed as product.

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The p-Block Elements Test - 28

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The p-Block Elements Test - 28

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Question 1

1

4

3

6

Solution

Question 2

Both I and II are true. II is correctexplanation of I.

Both I and II are true. II is not correctexplanation of I.

I is true but II is false

I is false but II is true.

Solution

Question 3

Metallic

Covalent

Ionic

They do not form bond

Solution

Question 4

Both $$A$$ and $$R$$ are correct and $$R$$ is the correct explanation of $$A$$.

Both $$A$$ and $$R$$ are correct and $$R$$ is not the correct explanation of $$A$$.

$$A$$ is true but $$R$$ is false.

$$A$$ is false but $$R$$ is true.

Solution

Question 5

Krypton

Argon II

Helium II

Helium I

Solution

Question 6

small size and high electronegativity

non availability of d-orbitals in valency shell

ease of multiple bond formation

all are correct

Solution

Question 7

$$ He > Ar > Kr > Ne > Xe $$

$$ He > Ne > Ar > Kr > Xe $$

$$ Xe > Kr > Ar > Ne > He $$

$$ Xe > Ar > Ne > Kr > He $$

Solution

Question 8

Both (A) and (R) are true and (R) is the correct explanation of (A)

Both (A) and (R) are true and (R) is not the correct explanation of (A)

(A) is true and (R) is false

(A) is false but (R) is true

Solution

Question 9

hydrolysis of nitrolim

hydrolysis of aluminium nitride

decomposition of ammonium nitrite

hydrolysis of urea

Solution

Question 10

$$ \mathrm{N}\mathrm{H}_{3}$$

$$\mathrm{N}\mathrm{O}$$

$$\mathrm{H}_{2}$$

$$\mathrm{C}\mathrm{O}_{2}$$

Solution

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Both I and II are true. II is correct

explanation of I.

Both I and II are true. II is not correct

explanation of I.