The p-Block Elements Test

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The p-Block Elements Test - 29

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Weekly Quiz Competition

Question 1
1 / -0

Hydrolysis of $$\mathrm{N}\mathrm{Cl}_{3}$$ gives $$\mathrm{N}\mathrm{H}_{3}$$ and $$\mathrm{X}$$. Which of the following is X?

A
$$ \mathrm{H}\mathrm{Cl}\mathrm{O}_{4}$$

B
$$ \mathrm{H}\mathrm{Cl}\mathrm{O}_{3}$$

C
$$ \mathrm{HO}\mathrm{Cl}$$

D
$$\mathrm{H}\mathrm{Cl}\mathrm{O}_{2}$$

Solution

Hydrolysis of $$NCl_3$$ can be explained by the following reaction
$$NCl_3 + 3H_2O \rightarrow NH_3 + 3HOCl$$
So, X is $$HOCl$$.
Question 2
1 / -0

Assertion (A): In the synthesis of ammonia by Haber's process, mixture of potassium and aluminium oxides can be used as promoter.
Reason (R): Promoter enhances the activity of catalyst.

A
Both (A) and (R) are true and (R) is the correct explanation of (A)

B
Both (A) and (R) are true and (R) is not the correct explanation of (A)

C
(A) is true and (R) is false

D
(A) is false but (R) is true

Solution

Promoter enhances the activity of catalyst (here iron in Haber's process), and because of which potassium and aluminium oxides are used as promoter in Haber's process.
Question 3
1 / -0

Gas obtained by heating a mixture of ammonium chloride and slaked lime is:

A
$$\mathrm{N}\mathrm{H}_{3}$$

B
$$\mathrm{N}_{2}$$

C
$$\mathrm{N}_{2}\mathrm{O}$$

D
$$\mathrm{N}\mathrm{O}_{2}$$

Solution

$$2\ NH_4Cl+Ca(OH)_2\rightarrow CaCl_2^{}+2NH_3^{}+2H_2O$$

The gas obtained is ammonia gas.
Question 4
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Which compound does not give ammonia gas on reaction with water ?

A
$$ \mathrm{M}\mathrm{g}_{3}\mathrm{N}_{2}$$

B
$$ \mathrm{A}\mathrm{l}\mathrm{N}$$

C
$$\mathrm{C}\mathrm{a}\mathrm{C}\mathrm{N}_{2}$$

D
$$\mathrm{C}\mathrm{a}(\mathrm{C}\mathrm{N})_{2}$$

Solution

$$Mg_3N_2 + 6H_2O \longrightarrow3Mg(OH)_2 + 2NH_3$$

$$AlN + 3H_2O \longrightarrow NH_3 + Al(OH)_3$$

$$2H_2O + Ca(CN)_2 \longrightarrow Ca(OH)_2 + 2HCN$$

$$CaCN_{2} + 3H_{2}O\longrightarrow$$ $$CaCO_{3} + 2NH_{3}$$

$$Ca(CN)_2$$ does not produce ammonia on reacting with water.
Question 5
1 / -0

A metal X on heating in nitrogen gas gives Y. Y on treatment with $$H_2O$$ gives a colourless gas which when passed through $$CuSO_4$$ solution gives a blue colour. Y is :

A
$$\mathrm{Mg(N}\mathrm{O}_{3})_{2}$$

B
$$\mathrm{M}\mathrm{g}_{3}\mathrm{N}_{2}$$

C
$$\mathrm{N}\mathrm{H}_{3}$$

D
$$\mathrm{M}\mathrm{g}\mathrm{O}$$

Solution

Colorless gas is $$NH_{3}$$.
$$Mg+N_2 \rightarrow Mg_3N_2$$
X Y

$$Mg_{3}N_{2}+3H_{2}O \rightarrow 3MgO+2NH_{3}$$

Ammonia when passed through copper sulphate forms a deep blue colored complex.

Option B is correct.
Question 6
1 / -0

Which of the following catalyst is used in the Haber's process for the manufacture of ammonia?

A
Platinized asbestos

B
Iron with a suitable promoter

C
Copper oxide

D
Alumina
Solution
Hint: The method of preparation of ammonia from nitrogen and hydrogen is called Haber’s process.

Explanation:

In Haber’s process ammonia is produced by the reaction of $$1$$ molecule of $$N_2$$ and $$3$$ molecules of $$H_2$$

The reaction is- $$N_{2(g)}+3H_{2(g)} \rightarrow 2NH_{3(g)}$$.
- This reaction is spontaneous at low temperatures and high pressure.
- At STP, the reaction is quite slow that is why there is a need for a catalyst that speeds up the reaction.
- In this reaction, iron is used as a catalyst. Here elemental $$Mo$$ is used as a promoter.
- Promoters are the ones that improve the performance of the catalyst so the reaction will drive faster.
Final Answer: Correct option (B).
Question 7
1 / -0

The ease of liquefaction of noble gases increases in the order

A
Ar > Kr > Xe > Ne > He

B
Xe > Kr > Ne > Ar > He

C
Kr > Xe > He > Ne > Ar

D
He > Ne > Ar > Kr > Xe

Solution

More the atomic size, more the inter molecular.(Van der waals forces) So less is the ease of liquefaction.
Question 8
1 / -0

Which is soluble in water :

A
AgCl

B
AgBr

C
AgI

D
AgF

Solution

Ionic compounds are soluble in water
In AgF $$F^-$$ is small onion with high charge density so less polarisation and less covalent character in the whole group of Ag holdies. AgF is most Ionic in nature.
Question 9
1 / -0

An element X of group 15 exists as diatomic molecule and combines with hydrogen at 773 K in presence of the catalyst to form a compound, ammonia which has a characteristic pungent smell. The element X is :

A
nitrogen

B
oxygen

C
phosphorous

D
sulphur

Solution

As it is is in group 15 it will have 5 electrons in outermost shell, i.e, nitrogen group family. As we know that nitrogen combines with hydrogen only in the presence of platinum catalyst. Hence the given element is nitrogen.
Question 10
1 / -0

An element with variable (more than one) valency stored under water is:

A
silicon

B
iron

C
phosphorus

D
gold

Solution

Phosphorous can accept either 3 electrons or donate 5 electrons depending on the neighborhood element. Hence, it has variable valency. The allotropic form of phosphorus (white phosphorus) is less stable and therefore highly reactive because of angular strain in $$P_4$$ molecule where the angles are only $$60^o$$.

It readily catches fire in air to give dense white fumes of $$P_{4}O_{10}$$. Therefore, it is kept in water to avoid oxidation by the oxygen present in the air. It is kept in water because it is insoluble in water.

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Re-Attempt Weekly Quiz Competition

The p-Block Elements Test - 29

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The p-Block Elements Test - 29

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SHARING IS CARING

Question 1

$$ \mathrm{H}\mathrm{Cl}\mathrm{O}_{4}$$

$$ \mathrm{H}\mathrm{Cl}\mathrm{O}_{3}$$

$$ \mathrm{HO}\mathrm{Cl}$$

$$\mathrm{H}\mathrm{Cl}\mathrm{O}_{2}$$

Solution

Question 2

Both (A) and (R) are true and (R) is the correct explanation of (A)

Both (A) and (R) are true and (R) is not the correct explanation of (A)

(A) is true and (R) is false

(A) is false but (R) is true

Solution

Question 3

$$\mathrm{N}\mathrm{H}_{3}$$

$$\mathrm{N}_{2}$$

$$\mathrm{N}_{2}\mathrm{O}$$

$$\mathrm{N}\mathrm{O}_{2}$$

Solution

Question 4

$$ \mathrm{M}\mathrm{g}_{3}\mathrm{N}_{2}$$

$$ \mathrm{A}\mathrm{l}\mathrm{N}$$

$$\mathrm{C}\mathrm{a}\mathrm{C}\mathrm{N}_{2}$$

$$\mathrm{C}\mathrm{a}(\mathrm{C}\mathrm{N})_{2}$$

Solution

Question 5

$$\mathrm{Mg(N}\mathrm{O}_{3})_{2}$$

$$\mathrm{M}\mathrm{g}_{3}\mathrm{N}_{2}$$

$$\mathrm{N}\mathrm{H}_{3}$$

$$\mathrm{M}\mathrm{g}\mathrm{O}$$

Solution

Question 6

Platinized asbestos

Iron with a suitable promoter

Copper oxide

Alumina

Solution

Question 7

Ar > Kr > Xe > Ne > He

Xe > Kr > Ne > Ar > He

Kr > Xe > He > Ne > Ar

He > Ne > Ar > Kr > Xe

Solution

Question 8

AgCl

AgBr

AgI

AgF

Solution

Question 9

nitrogen

oxygen

phosphorous

sulphur

Solution

Question 10

silicon

iron

phosphorus

gold

Solution

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