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The p-Block Elements Test - 30

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The p-Block Elements Test - 30
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Weekly Quiz Competition
  • Question 1
    1 / -0
    The ions $$Mg^{+2}$$ and $$PO_{4}^{-3}$$ combine to form compounds:
    Solution
    The ions $$Mg^{+2}$$ and $$PO_{4}^{-3}$$ combine to form compounds $$Mg_3(PO_4)_2$$. Total charge on cation $$=3(2+)=+6$$. Total charge on anion $$=2(-3)=-6$$. Hence, total charge on cation $$=$$ total charge on anion.
  • Question 2
    1 / -0
    Nitrogen can exhibit which of the following oxidation states:
    Solution
    Nitrogen forms oxides in which nitrogen exhibits each of its positive oxidation numbers from +1 to +5. $$N_2O$$ has nitrogen in the +1 oxidation state, $$NO$$ has +2 and $$NO_2$$ has +4 oxidation state.
  • Question 3
    1 / -0
    Magnesium on heating to redness in an atmosphere of $$N_{2}$$ and then on treating with $$H_{2}O$$ gives?
    Solution
    Megnesium when heated with $$N_2$$ in atmosphere it forms magnesium nitride($$Mg_3N_2$$) which on hydrolysis(reaction with water) gives ammonia.
    $$3Mg+N_2\rightarrow Mg_3N_2$$
    $$Mg_3N_2+6H_2O\rightarrow 3Mg(OH)_2+2NH_3$$.
    Hence option A is correct.
  • Question 4
    1 / -0
    Nitrogen is liberated by the thermal decomposition of only :
    Solution
    Nitrogen is liberated by the thermal decomposition of ammonium nitrite $$(NH_4NO_2), NaN_3, (NH_4)_2Cr_2O_7$$
  • Question 5
    1 / -0
    Phosphide and phosphate ions are:
    Solution
    Phosphide and phosphate ions are $$P^{3-}$$ and $$PO_{4}^{3-}$$ respectively. Thus, sodium phosphide can be represented as $$Na_3P$$ and sodium phosphate can be represented as $$Na_3PO_4$$.
  • Question 6
    1 / -0
    The steps for the manufacture of nitric acid by Ostwald process are given. Arrange them in sequence.
    (a) Recirculation of nitric oxide
    (b) Addition of $$H_2O$$ to nitrogen dioxide
    (c) Oxidation of nitric oxide.
    (d) Catalytic oxidation of ammonia
    Solution
    In the first step of Ostwald process, ammonia is oxidised to form nitric oxide.
    $$4NH_3 + 5O_2 \leftrightarrow 4NO + 6H_2O$$

    In the second step, nitric oxide is oxidised to form nitrogen dioxide.
    $$2NO + O_2 \leftrightarrow 2NO_2$$

    Then, nitrogen dioxide is mixed with water in an absorption tower to get nitric acid.
    $$3NO_2 + H_2O \rightarrow 2HNO_3 + NO$$

    Lastly, nitrogen dioxide is recirculated in the absorption tower to ensure that more and more of it is absorbed with water to increase the concentration of nitric acid. The vapours of nitric acid are then passed over concentrated sulphuric acid that absorbs water from it to increase its concentration further. 
  • Question 7
    1 / -0
    At low temperatures, nitrogen:
    Solution
    At low temperatures nitrogen can be liquefied on compression.
  • Question 8
    1 / -0
    Industrial preparations of $$HNO_{3}$$ by Ostwald's process involves:
    Solution
    $$4NH_3 (g) + 5O_2 (g) \rightarrow 4NO (g) + 6H_2O (g)$$

    $$2NO(g) +O_2(g) \xrightarrow {50^oC} 2NO_2(g)$$

    $$4NO_2(g) + 2H_2O(l) +O_2(g) \rightarrow 4HNO_3(aq)$$

    Oxidation of Ammonia occurs in the preparation of ammonia.
    Option B is correct.
  • Question 9
    1 / -0
    Nitrogen reacts with a metal $$M$$ to produce a compound $$X$$. This compound $$X$$, when dissolved in water forms pungent gas $$Y$$ which can be identified easily by the formation of white fumes in the presence of $$HCl$$.

    Identify the compound $$X$$.
    Solution

    Calcium nitride dissolves in water to give ammonia gas. 
    Compound $$X$$ is $$Ca_3N_2$$.

    $${Ca_3}N_2 + 6H_2O  \rightarrow 3Ca (OH)_2+2{NH_3}$$

    Hence, (B) is the correct answer.

  • Question 10
    1 / -0
    $$PCl_5$$ molecule has:
    Solution
    Considering the structure as shown in above image and hybridization of $$PCl_5$$, we can say that it has both three fold axis of symmetry and two fold axis of symmetry.

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